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Texas Lottery to add 'Sum It Up' feature to Pick 3 game

Topic locked. Last post more than one year ago by rcbbuckeye. 23 comments.

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Posted: November 2, 2007, 10:01 am - IP Logged Bottom

But i am confident LP predictors will take good juice out of this lottery with their predictions....And in cash3 is even worse...My thing is if Texas places such game in Texas and it works, other states will follow, and 1 state is bound to give better payouts...

With the sum it up option states can compete against horseracing which i think was what was happening in texas...I bet that the TX Pick4/Pick3 lottery was losing money against horse racing tracks, if such are legal in Texas...

But i think i saw a Theoretical glitch (yeah because is theoretical) on Texas's Cash4 Sum it up option...It says there that the 5 dollar wager for the 36 or 0 sum pays 25,000 dollars...But if you were to play 5 dollars on 1 sum everyday for 365 days it will equal 1825 dollars AND YOU KNOW that the sum 36 or 0 has to appear once a year, even if it appears once every 2 years that will be 5 X 730 days = 3650 dollars...(and if is 4 years is 7,300 dollars which leaves you with 17,700 dollars) AND YOU KNOW that the sum 36 or 0 HAS TO APPEAR at least Once every 2 years...And this is where my theory of number manipulations come in, because you and i know that in every normal draw even RNG, the sum 36 or "0" comes up at least once a year, but it maybe more because i am kind of rusty on Pick4 for i don't play that game nor i specialize on that game...Maybe i am thinking of Pick3...

 

 

"The Truth is Out There"             from movie "The X-Files"

"My thing is if Texas places such game in Texas and it works, other states will follow, and 1 state is bound to give better payouts..."

As states began creating their lotteries, they didn't raise the standard payoffs of $500 on the Pick-3 and $5000 on the Pick-4 games so I see no reason for them to give better payoffs if they add the Sum bet. 

"But if you were to play 5 dollars on 1 sum everyday for 365 days it will equal 1825 dollars AND YOU KNOW that the sum 36 or 0 has to appear once a year, even if it appears once every 2 years"

There are 10,000 straight combinations in a Pick-4 game and even if they drew twice a day, it would take over 13 years before they would have 10,000 drawings. And there is no guarantee 0000 or 9999 would be drawn.

"YOU KNOW that the sum 36 or 0 HAS TO APPEAR at least Once every 2 years...And this is where my theory of number manipulations come in, because you and i know that in every normal draw even RNG, the sum 36 or "0" comes up at least once a year, but it maybe more because i am kind of rusty on Pick4 for i don't play that game nor i specialize on that game...Maybe i am thinking of Pick3..."

Ask Thoth how many years it's been since 023 was drawn in the Ohio Pick-3. Over 10,000 draws and it's still in hiding.

pumpi76's avatar - milky way
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Posted: November 2, 2007, 11:03 am - IP Logged Bottom Top

"Ask Thoth how many years it's been since 023 was drawn in the Ohio Pick-3. Over 10,000 draws and it's still in hiding."

Maybe 023 (exactly) hasn't played but i am sure 320 and 230 has played already...

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Posted: November 4, 2007, 8:11 am - IP Logged Bottom Top

"Ask Thoth how many years it's been since 023 was drawn in the Ohio Pick-3. Over 10,000 draws and it's still in hiding."

Maybe 023 (exactly) hasn't played but i am sure 320 and 230 has played already...

You can only play 0000 and 9999 straight so the payouts for the sums of 0 and 36 are the same. All the Pick-4 sum payoffs are based on the standard 5000 to 1 payout divided by the number of straight combinations in each sum.

If you played $5 every draw on 0000 (or the sum of 0), your profit would depend on how many draws you played it before it hit. Because 0000 is just one of 10,000 Pick-4 numbers and the payouts are 50% of the true odds, after 5000 draws without a hit you would have to raise your bet to make a profit.

You're assuming that 0000 "should" hit once every two years or around 1500 drawings (based on 2 drawings a day, 7 days a week) and I gave an example of how sometimes assumptions are wrong. 023 is just one of 1000 Pick-3 and the logical assumption is that after it wasn't drawn for 1000 drawings, it "should" hit in the next year or at least in the next 1000 drawings.  

Both 320 and 230 have hit since the last time 023 was drawn, but if you're assuming 023 "should" hit in the next year because it's been 10,000 draws since the last hit, why would you play those numbers?

rcbbuckeye's avatar - 8ball
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Posted: November 6, 2007, 10:13 pm - IP Logged Bottom Top

I don't know about other states, but there are no drawings on Sundays in Tx. There are 313 drawings a year for Pick 3, Daily 4, and Cash 5.

Assuming a sum or number will hit once a year or so, I play Pick 3 that way. For example, the number 543 has hit 13 times in the evening draw, more than any other number. That figures to app 1 time a year on average since Pick 3 was started in Tx. I have started playing $1 every night on that number. If I hit once in 313 drawings, that's $313, but win $500 for a net profit of $187. It's not perfect, but I believe that being in the black on any lottery for the year is pretty good considering the house odds.

Ron