Been wanting to know the answer to this for years...Previous TopicNext Topic

I don't know if i am correct or not [that's why i am asking], but i've been meaning to know the answer to this lottery question...

Let's say you KNEW for sure that 2 or 3 numbers out of Powerball/MMillions where coming on the next drawing, and you was certain and you was correct....Could you some how wheeled or group it with other numbers it in a matter not seen before and get the 5/5? Like with some kind of wheel or numbers grouping or number structuring...

my question to you all is, could this be possible? I don't know if anyone has touched that subject...

Like 3 years ago [2005 i think], i read something not really similar on a website but the information was limited...

So you are talking only about the 5 main numbers and not about the 5 + 1?

5 out of 5 does not pay that much unless you are on a state like Tx where with 1 more Dollar per number you can MegaPly smaller wins such as 5 out of 5 from 1/4 Million to 1 Million.

2 out of 5 not enough I guess, but maybe 3 or better yet 4 out of 5, yes you can wheel, but you probably will get way too many combinations, I don't know, let us see:

54X54= 2916

54x54x54= 157,464.

It better be 2 or 3 for sure if a profit is needed.

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Such a thing would be better used together with other techniques for some reduction of combinations, one such of possible great help would or might be:

-------. Yes, I better don't mention it, things would have to be tried with past draws first and then with future draws, but without buying any tickets and many times to see if it would really work or not.

A proper filtered  wheeler would be needed to put everything together with.

I think I'm misunderstanding the question.

I'm not clear on 2 or 3 numbers matching 5 out of 5 on the main field of numbers... for example, Mega Millions main 5/56 field.

If you knew two numbers were going to be drawn for sure it would give you quite an advantage.

For MegaMillions with 56 numbers you would have 2 key numbers plus the possible combinations of 3of54 or 24,804 possible combinations to match 5of5.

For PowerBall with 59 numbers you would have 2 key numbers plus the possible combinations of 3of57 or 29,260 possible combinations to match 5of5.

In a MegaMillion state your prize would $250K and in a PowerBall state it would be $200K or $1M with powerplay.

Got it!! Never thought of it with Key Numbers. Just thinking of th hunch.

Hi,

i don't know how much it costs to play MM or powerball, but here's an example for the belgian lotto.
It is a 6/42 game.
One ticket costs 0.5 euro and the prizes start at 3 correct numbers.
The prize for 3 correct numbers is fixed, it is 2.5 euro.

So, in this case, if one would be certain of 3 numbers, each draw, one could not care less for all 6, because one would only need 3 to become a millionnaire.

Draw 1: 5 euro = 10 tickets - win 10 times 2.5 euro = 25 euro
Draw 2: 25 euro = 50 tickets - win 50 times 2.5 euro = 125 euro
Draw 3: 125 euro = 250 tickets - win 250 times 2.5 euro = 625 euro
Draw 4: 625 euro = 1250 tickets - win 1250 times 2.5 euro = 3125 euro
Draw 5: 3125 euro = 6250 tickets - win 6250 times 2.5 euro = 15625 euro
and so on...

The only problem would be to fill in that many tickets (even if one would print them using software, you still need to validate them), and the fact that it is all automated they would soon "track you down" (and buy you out of the game)

So there would be 2 goals: keep getting those 3 correct numbers each time,
and remain in low profile, keep the winnings down to  level that is acceptable and validate them in several different stores all over the country (belgium is pretty small lol)

cheers
Ricky

OTOH, you could play one draw 9,139 times - the number of possibilities in a 3/39 draw - and win every prize on the books - jackpot once and everything else multiple times.

I think you are missing the point of what i posted...

cheers
Ricky

What you posted is close to impossible ie getting 3 numbers correct 10 or more drawings in a row.

I would take those two or three numbers go to the store and quick pick the remainning 3 or 2 numbers.

The way I see it, if you cover your odds, luck has a better chance of covering the rest of the odds for you.

What i posted was a response to the openingpost : Let's say you KNEW for sure that 2 or 3 numbers out o...

yea but he didn't say that he will know 2 or 3 numbers is current every drawing. It is more of a hunch, you know lottery, random etc.

Too bad pumpi that there is really no way to know for sure not even 1 number.

It is all a chance, some chances might be better than others, but chances they still are.

But what people said is right if there was a way to know for sure.

Oops, thought TS wrote "knew for sure"... must be my eyes playing tricks on me...

Yep Paurths, my eyes are playing the same trick on me

So, if you would indeed KNOW 2 of the 5 numbers to hit for sure, you can make a full wheel with 2 key (or power) numbers. To cover all possible combinationsn, and therefore be sure to win the jackpot, it would take:

17.296 tickets in a 5/50 lottery

12.341 tickets in a 5/45 lottery

8.436 tickets in a 5/40 lottery

5.456 tickets in a 5/35 lottery

and 3.276 tickets tickets in a 5/30 lottery

Hope this is helpful in some way.

BTW: @ Paurths, any luck finding a 'system' in the Belgian Lotto? Maybe you could PM me (to keep this thread on topic) to exchange some ideas?