You last visited May 24, 2013, 8:03 pm All times shown are Eastern Time (GMT-5:00) | Are you good at Algebra? United States Member #123644 February 25, 2012 156 Posts Offline
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Ok how would you find out what X is if you know Y and Z | | |
mid-Ohio United States Member #9 March 24, 2001 15967 Posts Offline | | Posted: August 17, 2012, 11:15 am - IP Logged | |
First you have to know X relation to Y and Z. Examples: X * Y=Z, Z=X+Y, Y/Z=X and etc. * The fundamentals of winning a lottery jackpot * * play a lottery you can win *
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Aruba Member #123712 February 27, 2012 1799 Posts Offline | | Posted: August 17, 2012, 1:18 pm - IP Logged | |
Ok how would you find out what X is if you know Y and Z If x+y=0 and z=? then z=?. | | |
Illinois United States Member #129183 June 11, 2012 85 Posts Offline | | Posted: August 18, 2012, 3:55 am - IP Logged | |
First you have to know X relation to Y and Z. Examples: X * Y=Z, Z=X+Y, Y/Z=X and etc. reverse operation, right? X * Y=Z, so then X = Z / Y Z=X+Y, so then Z-Y = X | | |
Pittsburgh, PA United States Member #130606 July 20, 2012 36 Posts Offline | | Posted: August 18, 2012, 6:10 am - IP Logged | |
Ok how would you find out what X is if you know Y and Z I'm curious.... Is this a question based somewhat more on number theory? Or is it more literal. You haven't given any context for the question so it's hard to decide in which direction to approach the answer. Your user name suggests you know how to do basic algebra and the relation between the variables is of paramount importance. So since you left it out it leads me to believe either you're being rhetorical in a sense (maybe even mocking) or that you're trying to see if any one knows the general method of finding the answer to arbitrary numbers given the parameters that y and z are known with no further context or relation to x. I'm sure I can come up with a methodology for finding x (or likelihoods of x) given two known paramaters where x is not known, however my initial work up is designed around the idea that through manipulating y and z the "calculator" will be able to determine if x has been found. In other words the methods are based on the fact that the context is not known to begin with but WHEN known the answer will be apparent. This methodolgy even goes beyond numbers saying strictly that if events x, y and z are measurable (in some quantitative or qualitative way) and they are relatable (quantiatively or qualitatively) then x can be found as long as y and z are known. That being said, I say "initial work up" because just beginning to define the possible relationships of x to y and z (and y to z for that matter) is becoming very complex after a few initial steps. With all the known operands of how to compare three numbers with each other (especially considering the multitude of ways in which the operands can be compounded), the more complex the value of the variables means the more complex the solution will be. With no context, essentially I see an infinite set of possibilities. (or near infinite). If you already have the solution and are proposing the question not as a solicitation for assistance in finding the solution but as a method of testing the knowledge of this demographic than I'd be delighted to hear the solution. If you are seeking a generalized way to approach the problem from an arbitrary set of context than please say so. Otherwise could you please provide as much context as you can (or are willing) to eliminate unnecessary diversions. :) | | |
Aruba Member #123712 February 27, 2012 1799 Posts Offline | | Posted: August 18, 2012, 10:13 am - IP Logged | |
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Pittsburgh, PA United States Member #130606 July 20, 2012 36 Posts Offline | | Posted: August 18, 2012, 2:43 pm - IP Logged | |
x = the y root of (z - 2) example: if z = 10 and y = 3, then x = 2 | | |
bgonçalves Brasil Member #92592 June 9, 2010 1137 Posts Offline | | Posted: August 18, 2012, 6:49 pm - IP Logged | |
Hello guru is here to see the frequency of each digit In a lottery, after sorting the numbers put in ascending order In a straight line, should be grouped into sectors for the next sweepstakes How to calculate the execel, from a lists of sweepstakes The frequency of each number? Can you help me! Mount the frequency formula below numexcel 2010? Fazendo o isolamento de F: F = ( A - B + F ) / 3 F / 3 = A - B + F B - A = F - ( F / 3 ) B - A = 2F / 3 F = ( 3 * ( B - A)) / 2 | | |
Pittsburgh, PA United States Member #130606 July 20, 2012 36 Posts Offline | | Posted: August 19, 2012, 4:12 am - IP Logged | |
Hello guru is here to see the frequency of each digit In a lottery, after sorting the numbers put in ascending order In a straight line, should be grouped into sectors for the next sweepstakes How to calculate the execel, from a lists of sweepstakes The frequency of each number? Can you help me! Mount the frequency formula below numexcel 2010? Fazendo o isolamento de F: F = ( A - B + F ) / 3 F / 3 = A - B + F B - A = F - ( F / 3 ) B - A = 2F / 3 F = ( 3 * ( B - A)) / 2 It looks like your calculations are incorrect. If you are trying to isolate the F, then the calculations should run like this: F = (A - B + F) / 3 F*3 = A - B + F 3F - F = A - B 2F = A - B F = (A - B) / 2 Of course if you incorrectly typed the first line of the equation and it was supposed to read : F = (A - B + F) * 3 Then it would follow: F/3 = A - B + F
F/3 - F = A - B 2/3(F) = A - B F = (A - B) * (3/2) OR: F = ((A - B) * 3) / 2 The last line can be either expression because the order of operations outside of (A - B) is irrelevant because of the commutative law of multiplication and division. The first way is easier for me to read and conceptualize though so I personally prefer it. You mentioned something about excel. I don't use excel on a regular basis. I use programming for all my math using Visual Basic or Java. Also, I don't understand what your equation means or does. Does F = Frequency? What is A and what is B? And where does the 3 come from? How did you come up with the original equation or where did you find it? And what data set would you use this equation on? | | |
bgonçalves Brasil Member #92592 June 9, 2010 1137 Posts Offline | | Posted: August 19, 2012, 7:35 am - IP Logged | |
It looks like your calculations are incorrect. If you are trying to isolate the F, then the calculations should run like this: F = (A - B + F) / 3 F*3 = A - B + F 3F - F = A - B 2F = A - B F = (A - B) / 2 Of course if you incorrectly typed the first line of the equation and it was supposed to read : F = (A - B + F) * 3 Then it would follow: F/3 = A - B + F
F/3 - F = A - B 2/3(F) = A - B F = (A - B) * (3/2) OR: F = ((A - B) * 3) / 2 The last line can be either expression because the order of operations outside of (A - B) is irrelevant because of the commutative law of multiplication and division. The first way is easier for me to read and conceptualize though so I personally prefer it. You mentioned something about excel. I don't use excel on a regular basis. I use programming for all my math using Visual Basic or Java. Also, I don't understand what your equation means or does. Does F = Frequency? What is A and what is B? And where does the 3 come from? How did you come up with the original equation or where did you find it? And what data set would you use this equation on? Hello, guru, perfect, good job, down to the full caption, the formula, the frequencies of the numbers of a lottery, the legend, the names of the groups A, BF, etc .... Guru the goal is that after each number by the frequency sorting, putting them In a straight line, and see if the next sweepstakes, are grouped in a sector of the line, the higher parts of numbers, caption = 01 = the number of lottery 02 = the last test 03 = number of times the output of the number / (divided) Average R / D 04 = (A)> (greater than) space between the draws 05 = (B) <less than) space between the draws 06 = (F) Completion Repetition frequency = 07 08 = the largest gap between the draws End = 09 = (A-F) Frequency = 10 11 = (C) sum of the frequencies 12 = (D) amounts of frequencies Guru, this formulation is correct? Can you help me please Please feel free to change the formula, you can build the formula, then I'll see To make a little program, but now I need the formula ok | | |
adelaide sa Australia Member #37542 April 11, 2006 2439 Posts Offline | | Posted: August 19, 2012, 8:56 am - IP Logged | |
heres a goood place to start. http://www.khanacademy.org/exercisedashboard May " The lotto goddess may be blind and heartless, but she also has a wicked sense of humor. " mon/ lotto [8.8] tue/oz lotto [] wed/ lotto [8.8] thur/ power ball [] sat/ lotto [] sat /pools [] keno [21]20 scratch [] jan loss=[260.25] wins= 189; feb loss= [190.05] wins =182.6; mar loss= [311.9] wins = 107.35; apr loss= [320.30] wins= 107.50 2013 YTD loss[1032] wins = 585 2012 total spend =[2486.10], wins = 2176.70 ; year total = -$309.40 | | |
Aruba Member #123712 February 27, 2012 1799 Posts Offline | | Posted: August 19, 2012, 12:07 pm - IP Logged | |
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Pittsburgh, PA United States Member #130606 July 20, 2012 36 Posts Offline | | Posted: August 19, 2012, 3:33 pm - IP Logged | |
Ill look at this. I'll let ya know. If it's not consistent, it's irrelevant :) | | |
Pittsburgh, PA United States Member #130606 July 20, 2012 36 Posts Offline | | Posted: August 19, 2012, 3:36 pm - IP Logged | |
x = (the (Z -2) root of 1246)) / 2y If it's not consistent, it's irrelevant :) | | |
bgonçalves Brasil Member #92592 June 9, 2010 1137 Posts Offline | | Posted: August 19, 2012, 5:58 pm - IP Logged | |
Hello, where is the guru understood A B E etc?, You are allowed to improve the formula The goal, and classify each number of a lottery, and dpois put in ascending order in a line to see for the next drawing on sector line of all the lottery numbers It is located most of the numbers, it is the end or the beginning of the line, you can improve the formula | | |
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