Every combination has exactly the same chance as any other combination, even if it did appaer 10 weeks in a row, in the following draw the stats are reset.

Each combination does have a different chance of appearing in different positions on a ticket but the overall odds always remain unchanged,

In a 6/49 lotto there are 13,983,816 different 6 ball combinations, you pick one line per bet you have one in 13,983,816 of winning the jackpot.

Distributions come in to play when talking less than 6 hits in a 6/49 but the overall odds can never change no matter which combination you select

I will now demonstrate

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In a 6/49 draw

1,712,304 combinations of the possible 13,983,816 combinations have ball 1 as the lowest ball

178,365 combinations of the possible 13,983,816 combinations have ball 2 as the 2nd ball

15,180 combinations of the possible 13,983,816 combinations have ball 3 as the 3rd ball

990 combinations of the possible 13,983,816 combinations have ball 4 as the 4th ball

44 combinations of the possible 13,983,816 combinations have ball 5 as the 5th ball

1 combination of the possible 13,983,816 combinations have ball 6 as the 6th ball (01 02 03 04 05 06)

1,712,304 + 178,365 + 15,180 + 990 + 44 +1 = 1,906,884

So 1,906,884 possible combinations in the 6/49 have at least one number that intersects one of the combination 01,02,03,04,05,06

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Now to prove that there is a difference for whatever line chosen I will pick last week's lotto draw results which were 07 09 20 21 30 37 and repeat the above

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In a 6/49 draw

850,668 combinations of the possible 13,983,816 combinations have ball 7 as the lowest ball

731,120 combinations of the possible 13,983,816 combinations have ball 9 as the 2nd ball

624,834 combinations of the possible 13,983,816 combinations have ball 20 as the 3rd ball

430,920 combinations of the possible 13,983,816 combinations have ball 21 as the 4th ball

451,269 combinations of the possible 13,983,816 combinations have ball 30 as the 5th ball

376,992 combination of the possible 13,983,816 combinations have ball 37 as the 6th ball

850,668 + 731,120 + 624,834 + 430,920 + 451,269 + 376,992 = 3,465,803

So 3,465,803 possible combinations in the 6/49 have at least one number that intersects one of the combination 07,09,20,21,30,37

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By changing the numbers from 1,2,3,4,5,6 to 7,9,20,21,30,37 we have increased the odds of intersecting a single number by 1,558,919 to 1

We can go further and do the same for two ball combinations, however this gets a little more complex in the approach as instead of 6 ball positions we now have 15 possible pair positions to deal with, (6 numbers break into 15 pairs

1 2|1 3|1 4|1 5|1 6|2 3|2 4|2 5|2 6|3 4|3 5|3 6|4 5|4 6|5 6

In a 6/49 draw

01: 178,365 combinations of the possible 13,983,816 combinations have ball pair 1 2 at position 1 2

02: 15180 combinations of the possible 13,983,816 combinations have ball pair 1 3 at position 1 3

03: 990 combinations of the possible 13,983,816 combinations have ball pair 1 4 at position 1 4

04: 44 combinations of the possible 13,983,816 combinations have ball pair 1 5 at position 1 5

05: 1 combinations of the possible 13,983,816 combinations have ball pair 1 6 at position 1 6

06: 15,180 combinations of the possible 13,983,816 combinations have ball pair 2 3 at position 2 3

07: 990 combinations of the possible 13,983,816 combinations have ball pair 2 4 at position 2 4

08: 44 combinations of the possible 13,983,816 combinations have ball pair 2 5 at position 2 5

09: 1 combination of the possible 13,983,816 combinations have ball pair 2 6 at position 2 6

10: 990 combinations of the possible 13,983,816 combinations have ball pair 3 4 at position 3 4

11: 44 combinations of the possible 13,983,816 combinations have ball pair 3 5 at position 3 5

12: 1 combinations of the possible 13,983,816 combinations have ball pair 3 6 at position 3 6

13: 44 combinations of the possible 13,983,816 combinations have ball pair 4 5 at position 4 5

14: 1 combinations of the possible 13,983,816 combinations have ball pair 4 6 at position 4 6

15: 1 combinations of the possible 13,983,816 combinations have ball pair 5 6 at position 5 6

178,365+15180 +990 +44 +1+15,180 +990 +44+1 +990 +44 +1+44 +1 +1 = 211,876

So 211,876 combinations in the 6/49 have two numbers that intersects one of the possible 15 pairs found in the combination 01,02,03,04,05,06

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Again repeat for last week's numbers

In a 6/49 draw

01: 178,365 combinations of the possible 13,983,816 combinations have ball pair 7 9 at position 1 2

02: 15,180 combinations of the possible 13,983,816 combinations have ball pair 7 20 at position 1 3

03: 990 combinations of the possible 13,983,816 combinations have ball pair 7 21 at position 1 4

04: 44 combinations of the possible 13,983,816 combinations have ball pair 7 30 at position 1 5

05: 1 combinations of the possible 13,983,816 combinations have ball pair 7 37 at position 1 6

06: 29,232 combinations of the possible 13,983,816 combinations have ball pair 9 20 at position 2 3

07: 33,264 combinations of the possible 13,983,816 combinations have ball pair 9 21 at position 2 4

08: 28,880 combinations of the possible 13,983,816 combinations have ball pair 9 30 at position 2 5

09: 23,400 combinations of the possible 13,983,816 combinations have ball pair 9 37 at position 2 6

10: 64,638 combinations of the possible 13,983,816 combinations have ball pair 20 21 at position 3 4

11: 29,241 combinations of the possible 13,983,816 combinations have ball pair 20 30 at position 3 5

12: 20,520 combinations of the possible 13,983,816 combinations have ball pair 20 37 at position 3 6

13: 21,660 combinations of the possible 13,983,816 combinations have ball pair 21 30 at position 4 5

14: 17,100 combinations of the possible 13,983,816 combinations have ball pair 21 37 at position 4 6

15: 4,845 combinations of the possible 13,983,816 combinations have ball pair 30 37 at position 5 6

178,365 +15,180 +990 +44 +1 +29,232 +33,264 +28,880 +23,400+64,638 +29,241 +20,520 +21,660 +17,100 +4,845 =467,360

So 467,360 possible combinations in the 6/49 have two numbers that intersects one of possible 15 pairs found in the combination 7,9,20,21,30,37

By changing the numbers from 1,2,3,4,5,6 to 7,9,20,21,30,37 we have increased the odds of intersecting a pair by 255,484 to 1

So to cap this up, the lines you choose do appear to change the odds however

And a big However

Each pair appears the same number of times in the total combinations

Just different amounts in different ticket positions.

The fact is that in the 6/49 draw

Each 2 ball combo appears a total of 178,365 times

Each 3 ball combo appears a total of 15,180 times (1 in 56.6559)

Each 4 ball combo appears a total of 990 times (1 in 1,032.4)

Each 5 ball combo appears a total of 44 times (1 in 55,491.3)

Each 6 ball combo appears once 1: (1 in 13,983,816)

So the conclusion here is shuffling numbers about increases odds on some combinations but then in the same instance decreases the combinations in other ticket positions.

Always leaveing the overall odds unchanged.

Here is a small snippet taken from LSA that shows each 2 ball combo positions in a 6/49 draw, note they all add up to 178,365

1=1 2 = 178,365 0 0 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365

2=1 3 = 163,185 15,180 0 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365

3=1 4 = 148,995 28,380 990 0 0 0 0 0 0 0 0 0 0 0 0 = 178,365

4=1 5 = 135,751 39,732 2,838 44 0 0 0 0 0 0 0 0 0 0 0 = 178,365

5=1 6 = 123,410 49,364 5,418 172 1 0 0 0 0 0 0 0 0 0 0 = 178,365

6=1 7 = 111,930 57,400 8,610 420 5 0 0 0 0 0 0 0 0 0 0 = 178,365

7=1 8 = 101,270 63,960 12,300 820 15 0 0 0 0 0 0 0 0 0 0 = 178,365

8=1 9 = 91,390 69,160 16,380 1,400 35 0 0 0 0 0 0 0 0 0 0 = 178,365

9=1 10 = 82,251 73,112 20,748 2,184 70 0 0 0 0 0 0 0 0 0 0 = 178,365

10=1 11 = 73,815 75,924 25,308 3,192 126 0 0 0 0 0 0 0 0 0 0 = 178,365

11=1 12 = 66,045 77,700 29,970 4,440 210 0 0 0 0 0 0 0 0 0 0 = 178,365

12=1 13 = 58,905 78,540 34,650 5,940 330 0 0 0 0 0 0 0 0 0 0 = 178,365

13=1 14 = 52,360 78,540 39,270 7,700 495 0 0 0 0 0 0 0 0 0 0 = 178,365

14=1 15 = 46,376 77,792 43,758 9,724 715 0 0 0 0 0 0 0 0 0 0 = 178,365

15=1 16 = 40,920 76,384 48,048 12,012 1,001 0 0 0 0 0 0 0 0 0 0 = 178,365

16=1 17 = 35,960 74,400 52,080 14,560 1,365 0 0 0 0 0 0 0 0 0 0 = 178,365

It has been said every software has a bug in it, it has also been said that every program can be reduced by one line of code.

There for any program can be reduced to 1 line that dont work.