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P-4 for P-3 pairs giver system

Topic closed. 20 replies. Last post 2 years ago by retxx.

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United States
Member #128795
June 2, 2012
5031 Posts
Offline
Posted: January 7, 2013, 5:50 pm - IP Logged

I was just glancing over the p-4 and p-3 numbers and noticed something that occurs quite regularly.

At least here in florida, If you take the the last evening P-4 winner and look at the gap differences between the numbers, a good portion of the time two of those numbers will show up in the next day's mid or eve P-3.

Example, Florida, Dec. 2012 through January 2013,

Nov. 30 eve-2572   Between 2 and 5 is a gap of 3 numbers, so the first number is 3. Between 5 and 7 is a gap of 2 numbers, so the second number is 2, and between the 7 and and 2 is a gap of 5, so the third number is 5.

So we have 325

Dec. 1 mid-533

 

Sometimes all three numbers produced by the P-4 show a few days down the line.

More examples below.

 

Dec. 2 eve-6331=302

Dec. 3 eve-312

 

Dec. 9 eve-9083=985

Dec. 10 mid-995

 

Dec. 10 eve-7391=468

Dec. 11 eve-064

 

Dec. 15 eve-7845=141

Dec. 16 mid-421

 

Dec. 17 eve-9950=045

Dec. 18 eve-407

 

Dec. 19 eve-4437=014

Dec. 20 eve-048

 

Dec. 23 eve-8890=019

Dec. 24 mid-129

 

Dec. 24 eve-5153=642

Dec. 25 mid-642------------------STRAIGHT HIT !

 

Dec. 27 eve-0103=113

Dec. 28 mid-134

 

Dec. 31 eve-7960=236   236

Jan. 1 mid-223         eve-367

 

Jan. 2 eve-7802=182

Jan. 3 eve-871

 

Jan. 4 eve-3562=214

Jan. 5 mid-146

    onlymoney's avatar - stargate pyramid.jpg

    United States
    Member #128795
    June 2, 2012
    5031 Posts
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    Posted: January 7, 2013, 5:54 pm - IP Logged

    So for tonight's eve we use last night's P-4 winner, 7754=021

    I'm going to predict the 21 in the front or back. We'll see.

      ONEDAY's avatar - DiscoBallGlowing
      OHIO
      United States
      Member #5328
      June 30, 2004
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      Posted: January 7, 2013, 6:47 pm - IP Logged

      very nice find.

      have a great winning day!

        emilyg's avatar - cat anm.gif
        Miss Kitty

        United States
        Member #14
        November 9, 2001
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        Posted: January 7, 2013, 6:51 pm - IP Logged

        Thanks

        love to nibble those micey feet.

         

                                     

          ONEDAY's avatar - DiscoBallGlowing
          OHIO
          United States
          Member #5328
          June 30, 2004
          1284 Posts
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          Posted: January 7, 2013, 7:01 pm - IP Logged

          works in ohio for the most part..nice tool to have!

          have a great winning day!

            onlymoney's avatar - stargate pyramid.jpg

            United States
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            Posted: January 7, 2013, 9:57 pm - IP Logged

            Thank You All for the nice comments.

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              United States
              Member #128795
              June 2, 2012
              5031 Posts
              Offline
              Posted: January 7, 2013, 10:01 pm - IP Logged

              I was just glancing over the p-4 and p-3 numbers and noticed something that occurs quite regularly.

              At least here in florida, If you take the the last evening P-4 winner and look at the gap differences between the numbers, a good portion of the time two of those numbers will show up in the next day's mid or eve P-3.

              Example, Florida, Dec. 2012 through January 2013,

              Nov. 30 eve-2572   Between 2 and 5 is a gap of 3 numbers, so the first number is 3. Between 5 and 7 is a gap of 2 numbers, so the second number is 2, and between the 7 and and 2 is a gap of 5, so the third number is 5.

              So we have 325

              Dec. 1 mid-533

               

              Sometimes all three numbers produced by the P-4 show a few days down the line.

              More examples below.

               

              Dec. 2 eve-6331=302

              Dec. 3 eve-312

               

              Dec. 9 eve-9083=985

              Dec. 10 mid-995

               

              Dec. 10 eve-7391=468

              Dec. 11 eve-064

               

              Dec. 15 eve-7845=141

              Dec. 16 mid-421

               

              Dec. 17 eve-9950=045

              Dec. 18 eve-407

               

              Dec. 19 eve-4437=014

              Dec. 20 eve-048

               

              Dec. 23 eve-8890=019

              Dec. 24 mid-129

               

              Dec. 24 eve-5153=642

              Dec. 25 mid-642------------------STRAIGHT HIT !

               

              Dec. 27 eve-0103=113

              Dec. 28 mid-134

               

              Dec. 31 eve-7960=236   236

              Jan. 1 mid-223         eve-367

               

              Jan. 2 eve-7802=182

              Jan. 3 eve-871

               

              Jan. 4 eve-3562=214

              Jan. 5 mid-146

              Dec. 24 eve-5153=642

              Dec. 25 mid-642------------------STRAIGHT HIT !

               

               

              This is actually wrong. It should be 442. My bad !

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                United States
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                June 2, 2012
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                Posted: January 7, 2013, 10:15 pm - IP Logged

                The winner was 117. No cigar, but there's always tomorrow. It's been two days since a hit, so it's overdue.

                 

                Party


                  United States
                  Member #137125
                  December 27, 2012
                  15 Posts
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                  Posted: January 8, 2013, 9:58 am - IP Logged

                  I was just glancing over the p-4 and p-3 numbers and noticed something that occurs quite regularly.

                  At least here in florida, If you take the the last evening P-4 winner and look at the gap differences between the numbers, a good portion of the time two of those numbers will show up in the next day's mid or eve P-3.

                  Example, Florida, Dec. 2012 through January 2013,

                  Nov. 30 eve-2572   Between 2 and 5 is a gap of 3 numbers, so the first number is 3. Between 5 and 7 is a gap of 2 numbers, so the second number is 2, and between the 7 and and 2 is a gap of 5, so the third number is 5.

                  So we have 325

                  Dec. 1 mid-533

                   

                  Sometimes all three numbers produced by the P-4 show a few days down the line.

                  More examples below.

                   

                  Dec. 2 eve-6331=302

                  Dec. 3 eve-312

                   

                  Dec. 9 eve-9083=985

                  Dec. 10 mid-995

                   

                  Dec. 10 eve-7391=468

                  Dec. 11 eve-064

                   

                  Dec. 15 eve-7845=141

                  Dec. 16 mid-421

                   

                  Dec. 17 eve-9950=045

                  Dec. 18 eve-407

                   

                  Dec. 19 eve-4437=014

                  Dec. 20 eve-048

                   

                  Dec. 23 eve-8890=019

                  Dec. 24 mid-129

                   

                  Dec. 24 eve-5153=642

                  Dec. 25 mid-642------------------STRAIGHT HIT !

                   

                  Dec. 27 eve-0103=113

                  Dec. 28 mid-134

                   

                  Dec. 31 eve-7960=236   236

                  Jan. 1 mid-223         eve-367

                   

                  Jan. 2 eve-7802=182

                  Jan. 3 eve-871

                   

                  Jan. 4 eve-3562=214

                  Jan. 5 mid-146

                  INSTANT NEXT NUMBERS FOR P4 GAMES

                   

                  EX: CA JAN 1 2013 NUMBERS 4539

                   

                  4539 PLUS MIRROR

                  4539=9084

                   

                  USING TOTAL IN P4 GAMES 9999 SUBTRACT BOTH THE WINNING AND MIRROR NUMBERS

                   

                  9999                                    9999

                  - 4539                                - 9084

                  5460                                     0915

                  NOW NUMBERS THAT ARE REPEAT SHOULD BE OUT

                  45 OF 4539            90 OF 9084

                  54 OF 5460             09 OF 0915

                  NOW I HAD 39 AND 60                     84 AND 15 LEFT

                  SINCE 39 AND 84 ARE ON TOP OF BOTH 60 AND 15

                  3 OF 39 SHOULD BE WITH 6 OF 60

                  9 OF 39 WITH 0 OF 60

                  8 OF 84 WITH 1 OF 15

                  4 OF 84 WITH 5 OF 15

                  NOW I WILL HAD 3-6 9-0 8-1 4-5

                  SO WHAT I DO IS NOW SUBTRACT THE RIGHT NUMBERS TO THE LEFT NUMBERS

                  3-6 IS 6 MINUS 3= 3 SINCE 0 CANT SUBTRACT ABY NUMBERS I WILL CARRY 1 TO IT 0 + 1 = 10 NOW 10 MINUS 9= 1

                  IF ANY NUMBERS OF RIGHT SIDES IS SMALLER THAN LEFT SIDES JUST CARRY 1 TO IT

                  SO 11 MINUS 8= 3 AND 5 MINUS 4= 1

                  NOW I HAD THE NUMBERS 3131

                  SO WHAT I DO IS ADD THAT NUMBERS TO THE WINNING NUMBERS OF 4539 ON JAN 1 2013 OF CA

                  4539

                  + 3131

                  7670 THIS JUST REGULAR MATH

                  NOW SINCE I HAD 3131 ALL I NEED IS A PAIR OF 2 NUMBERS AND ADD THEM TOGTHER SO 3 + 1 = 4

                  THE 7670 PLUS 4

                  I GET 7674 WHICH IS THE NEXT WINNING NUMBER IN CA

                  A STRAIGHT AUTOMATC WIN INSTANTLY

                  FINALLY I BEAT THE LOTTO SYSTEM OF CA

                  TAKE THAT SYSTEM AND THAT TOO LOL.

                  I THINK IT MAY WORK IN P3 TOO

                  I HAVENT TEST IT OUT YET ON P3 GAMES

                  SO THANKS ALOT

                  ANY SUGGESTIONS TO MAKE THIS SECRET TECHNIQUE MORE PERFECT IS ACCEPTED

                  THANKS

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                    United States
                    Member #128795
                    June 2, 2012
                    5031 Posts
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                    Posted: January 8, 2013, 10:05 am - IP Logged

                    INSTANT NEXT NUMBERS FOR P4 GAMES

                     

                    EX: CA JAN 1 2013 NUMBERS 4539

                     

                    4539 PLUS MIRROR

                    4539=9084

                     

                    USING TOTAL IN P4 GAMES 9999 SUBTRACT BOTH THE WINNING AND MIRROR NUMBERS

                     

                    9999                                    9999

                    - 4539                                - 9084

                    5460                                     0915

                    NOW NUMBERS THAT ARE REPEAT SHOULD BE OUT

                    45 OF 4539            90 OF 9084

                    54 OF 5460             09 OF 0915

                    NOW I HAD 39 AND 60                     84 AND 15 LEFT

                    SINCE 39 AND 84 ARE ON TOP OF BOTH 60 AND 15

                    3 OF 39 SHOULD BE WITH 6 OF 60

                    9 OF 39 WITH 0 OF 60

                    8 OF 84 WITH 1 OF 15

                    4 OF 84 WITH 5 OF 15

                    NOW I WILL HAD 3-6 9-0 8-1 4-5

                    SO WHAT I DO IS NOW SUBTRACT THE RIGHT NUMBERS TO THE LEFT NUMBERS

                    3-6 IS 6 MINUS 3= 3 SINCE 0 CANT SUBTRACT ABY NUMBERS I WILL CARRY 1 TO IT 0 + 1 = 10 NOW 10 MINUS 9= 1

                    IF ANY NUMBERS OF RIGHT SIDES IS SMALLER THAN LEFT SIDES JUST CARRY 1 TO IT

                    SO 11 MINUS 8= 3 AND 5 MINUS 4= 1

                    NOW I HAD THE NUMBERS 3131

                    SO WHAT I DO IS ADD THAT NUMBERS TO THE WINNING NUMBERS OF 4539 ON JAN 1 2013 OF CA

                    4539

                    + 3131

                    7670 THIS JUST REGULAR MATH

                    NOW SINCE I HAD 3131 ALL I NEED IS A PAIR OF 2 NUMBERS AND ADD THEM TOGTHER SO 3 + 1 = 4

                    THE 7670 PLUS 4

                    I GET 7674 WHICH IS THE NEXT WINNING NUMBER IN CA

                    A STRAIGHT AUTOMATC WIN INSTANTLY

                    FINALLY I BEAT THE LOTTO SYSTEM OF CA

                    TAKE THAT SYSTEM AND THAT TOO LOL.

                    I THINK IT MAY WORK IN P3 TOO

                    I HAVENT TEST IT OUT YET ON P3 GAMES

                    SO THANKS ALOT

                    ANY SUGGESTIONS TO MAKE THIS SECRET TECHNIQUE MORE PERFECT IS ACCEPTED

                    THANKS

                    Thanks, i will try to absorb the workout but i must first get past the first hill by asking how you got 9084.

                    Shouldn't it be 9584?

                    The mirror of 5 is 0, so 5+0=5, no? or am i doing it wrong?

                      onlymoney's avatar - stargate pyramid.jpg

                      United States
                      Member #128795
                      June 2, 2012
                      5031 Posts
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                      Posted: January 8, 2013, 10:38 am - IP Logged

                      INSTANT NEXT NUMBERS FOR P4 GAMES

                       

                      EX: CA JAN 1 2013 NUMBERS 4539

                       

                      4539 PLUS MIRROR

                      4539=9084

                       

                      USING TOTAL IN P4 GAMES 9999 SUBTRACT BOTH THE WINNING AND MIRROR NUMBERS

                       

                      9999                                    9999

                      - 4539                                - 9084

                      5460                                     0915

                      NOW NUMBERS THAT ARE REPEAT SHOULD BE OUT

                      45 OF 4539            90 OF 9084

                      54 OF 5460             09 OF 0915

                      NOW I HAD 39 AND 60                     84 AND 15 LEFT

                      SINCE 39 AND 84 ARE ON TOP OF BOTH 60 AND 15

                      3 OF 39 SHOULD BE WITH 6 OF 60

                      9 OF 39 WITH 0 OF 60

                      8 OF 84 WITH 1 OF 15

                      4 OF 84 WITH 5 OF 15

                      NOW I WILL HAD 3-6 9-0 8-1 4-5

                      SO WHAT I DO IS NOW SUBTRACT THE RIGHT NUMBERS TO THE LEFT NUMBERS

                      3-6 IS 6 MINUS 3= 3 SINCE 0 CANT SUBTRACT ABY NUMBERS I WILL CARRY 1 TO IT 0 + 1 = 10 NOW 10 MINUS 9= 1

                      IF ANY NUMBERS OF RIGHT SIDES IS SMALLER THAN LEFT SIDES JUST CARRY 1 TO IT

                      SO 11 MINUS 8= 3 AND 5 MINUS 4= 1

                      NOW I HAD THE NUMBERS 3131

                      SO WHAT I DO IS ADD THAT NUMBERS TO THE WINNING NUMBERS OF 4539 ON JAN 1 2013 OF CA

                      4539

                      + 3131

                      7670 THIS JUST REGULAR MATH

                      NOW SINCE I HAD 3131 ALL I NEED IS A PAIR OF 2 NUMBERS AND ADD THEM TOGTHER SO 3 + 1 = 4

                      THE 7670 PLUS 4

                      I GET 7674 WHICH IS THE NEXT WINNING NUMBER IN CA

                      A STRAIGHT AUTOMATC WIN INSTANTLY

                      FINALLY I BEAT THE LOTTO SYSTEM OF CA

                      TAKE THAT SYSTEM AND THAT TOO LOL.

                      I THINK IT MAY WORK IN P3 TOO

                      I HAVENT TEST IT OUT YET ON P3 GAMES

                      SO THANKS ALOT

                      ANY SUGGESTIONS TO MAKE THIS SECRET TECHNIQUE MORE PERFECT IS ACCEPTED

                      THANKS

                      I also ran into another problem. Using Florida Jan. 1 as the starting point eve-4194

                      4914+ mirror=3373

                       

                      9999 minus 4914=5085

                      9999 minus 3373=6626

                       

                      Now here's where I run into a snag. You say to eliminate any repeating pairs, so let's start with 4914. I don't see any repeating pairs, so how would I conitnue? Unless you count 49 Twice, like 4914     4914

                       

                      And the same problem with 3373, 5085, and 6626. I can't continue until I get a resolution for the first problem with the mirror, and then this one with the pairs.

                      I'll wait for your response. Thanks.


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                        January 3, 2013
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                        Posted: January 8, 2013, 10:44 am - IP Logged

                        Works in GA.  Thankts


                          United States
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                          December 27, 2012
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                          Posted: January 8, 2013, 12:25 pm - IP Logged

                          Thanks, i will try to absorb the workout but i must first get past the first hill by asking how you got 9084.

                          Shouldn't it be 9584?

                          The mirror of 5 is 0, so 5+0=5, no? or am i doing it wrong?

                          WHAT I MEANT BY 4539 PLUS MIRROR

                          IS THAT I MIRROR THE NUMBER 4539

                          TO ITS MIRROR NUMBER

                          SO I HAD 9084

                          9084

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                            United States
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                            Posted: January 8, 2013, 12:32 pm - IP Logged

                            WHAT I MEANT BY 4539 PLUS MIRROR

                            IS THAT I MIRROR THE NUMBER 4539

                            TO ITS MIRROR NUMBER

                            SO I HAD 9084

                            9084

                            Got it, thanks. Now to the second problem of not finding any duplicate pairs. Thanks.


                              United States
                              Member #137125
                              December 27, 2012
                              15 Posts
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                              Posted: January 8, 2013, 1:08 pm - IP Logged

                              I also ran into another problem. Using Florida Jan. 1 as the starting point eve-4194

                              4914+ mirror=3373

                               

                              9999 minus 4914=5085

                              9999 minus 3373=6626

                               

                              Now here's where I run into a snag. You say to eliminate any repeating pairs, so let's start with 4914. I don't see any repeating pairs, so how would I conitnue? Unless you count 49 Twice, like 4914     4914

                               

                              And the same problem with 3373, 5085, and 6626. I can't continue until I get a resolution for the first problem with the mirror, and then this one with the pairs.

                              I'll wait for your response. Thanks.

                              OK I SEE

                              WELL FOR ME

                              IT SEEMS TO WORK IN CA LOTTERY

                              BUT I NOT SURE YET ON THE REST OF THE PREVIOUS NUMBERS CUX I ONLY HAD THIS IDEA SINCE YESTERDAY ONLY

                              AND HAD TESTED IT OUT ON THE JAN 1 P4 GAME "ONCE" ONLY IN CA

                              IT SEEMS TO WORK FOR THIS SINGLE DIGITS ON JAN 1 ONLY

                              RIGHT NOW I TRYING TO TEST OUT TO SEE IF I CAN GET AT LEAST 3 OUT OF 4 NEXT WINNING NUMBERS

                              AND DO SAME METHOD TO SEE IF I CAN GET THE NEXT 1 SINGLE WINNING NUMBER TO BE WITH THE 3 NEXT WINNING NUMBERS

                              THATS WHAT I AM GOING TO DO AT LEAST NOW.

                               

                               

                               

                              WELL WHAT I DID WAS USING 9999 MINUS 4539 AND GET 5460 IN HERE

                              9999

                              -4539

                              5460

                              NOTICED: SINCE THERE IS THE PAIR OF 45 IN 4539 AND 54 OF 5460.

                              U TAKE THEM OUT FROM 4 TO 4 AND 5 TO 5 CRISS CROSS TAKE OUTS

                              I GUESS U CAN  SAY IT THE BIG     X        TAKE OUTS

                              BECUX IT HAD TWO OF THE SAME NUMBERS WHICH IS 4 AND 5

                              WHICH LEFT ONLY THE 3 AND 9 OF 4539 ON TOP OF RIGHT SIDES 

                              NEXT TO THE NUMBER 4 AND 5 OF 4539 WHICH WAS TAKEN OUT BY CRISS CROSS

                              THE BOTTOM RIGHT SIDES WITH ONLY THE 6 AND 0 OF 5460

                              THE SAME IS FOR THE MIRROR NUMBERS AS WELL

                              WITH 8 AND 4 OF 9084 ON TOP RIGHT SIDES AND 1 AND 5 OF BOTTOM RIGHT SIDES

                              9999                                9999

                              - 4539                            - 9084

                              54 60                               09 15

                               


                              SO WHAT I DID NOW IS GROUP THEM ALL TOGETHER LIKE THIS:

                              3 TO 6

                              9 TO 0

                              8 TO 1

                              4 TO 5

                              NOW NEXT I SUBTRACT NUMBERS FROM RIGHT SIDES TO LEFT

                              6 MINUS 3 = 3

                              SINCE 0 CANT SUBTRACT ANY NUMBERS AT ALL I JUST CARRY THE ONE TO THE ZERO MAKING IT A TEN 10

                              SO 10 MINUS 9 = 1

                              IF ANY NUMBERS FROM RIGHT SIDES IS LESS THAN LEFT SIDES NUMBERS JUST CARRY 1 TO IT

                              SO IT CAN SUBTRACT THE LEFT SIDES

                              NOW NEXT IS 1 MINUS 8 SO CARRY 1 TO IT

                              1 NOW IS 11 MINUS 8= 3

                              5 MINUS 4 = 1

                              SO I GET THE NUMBERS 3131

                              SE 3131 AND ADDED TO THE WINNING NUMBERS OF 4539

                              U GET 7670

                              THEN USE THE 3131 AGAIN BUT THIS TIME ONLY A PAIR SO I GET

                              31, ADD THEM I GET 4

                              SO I ADD 4 TO THE RESULT OF 7670 TO BE

                               

                              7674 THE NEXT STRAIGHT WINNING NUMBERS FOR JAN 2 2013 IN CALIFORNIA.