P-4 for P-3 pairs giver system

I was just glancing over the p-4 and p-3 numbers and noticed something that occurs quite regularly.

At least here in florida, If you take the the last evening P-4 winner and look at the gap differences between the numbers, a good portion of the time two of those numbers will show up in the next day's mid or eve P-3.

Example, Florida, Dec. 2012 through January 2013,

Nov. 30 eve-2572   Between 2 and 5 is a gap of 3 numbers, so the first number is 3. Between 5 and 7 is a gap of 2 numbers, so the second number is 2, and between the 7 and and 2 is a gap of 5, so the third number is 5.

So we have 325

Dec. 1 mid-533

Sometimes all three numbers produced by the P-4 show a few days down the line.

More examples below.

Dec. 2 eve-6331=302

Dec. 3 eve-312

Dec. 9 eve-9083=985

Dec. 10 mid-995

Dec. 10 eve-7391=468

Dec. 11 eve-064

Dec. 15 eve-7845=141

Dec. 16 mid-421

Dec. 17 eve-9950=045

Dec. 18 eve-407

Dec. 19 eve-4437=014

Dec. 20 eve-048

Dec. 23 eve-8890=019

Dec. 24 mid-129

Dec. 24 eve-5153=642

Dec. 25 mid-642------------------STRAIGHT HIT !

Dec. 27 eve-0103=113

Dec. 28 mid-134

Dec. 31 eve-7960=236   236

Jan. 1 mid-223         eve-367

Jan. 2 eve-7802=182

Jan. 3 eve-871

Jan. 4 eve-3562=214

Jan. 5 mid-146

I was just glancing over the p-4 and p-3 numbers and noticed something that occurs quite regularly.

At least here in florida, If you take the the last evening P-4 winner and look at the gap differences between the numbers, a good portion of the time two of those numbers will show up in the next day's mid or eve P-3.

Example, Florida, Dec. 2012 through January 2013,

Nov. 30 eve-2572   Between 2 and 5 is a gap of 3 numbers, so the first number is 3. Between 5 and 7 is a gap of 2 numbers, so the second number is 2, and between the 7 and and 2 is a gap of 5, so the third number is 5.

So we have 325

Dec. 1 mid-533

Sometimes all three numbers produced by the P-4 show a few days down the line.

More examples below.

Dec. 2 eve-6331=302

Dec. 3 eve-312

Dec. 9 eve-9083=985

Dec. 10 mid-995

Dec. 10 eve-7391=468

Dec. 11 eve-064

Dec. 15 eve-7845=141

Dec. 16 mid-421

Dec. 17 eve-9950=045

Dec. 18 eve-407

Dec. 19 eve-4437=014

Dec. 20 eve-048

Dec. 23 eve-8890=019

Dec. 24 mid-129

Dec. 24 eve-5153=642

Dec. 25 mid-642------------------STRAIGHT HIT !

Dec. 27 eve-0103=113

Dec. 28 mid-134

Dec. 31 eve-7960=236   236

Jan. 1 mid-223         eve-367

Jan. 2 eve-7802=182

Jan. 3 eve-871

Jan. 4 eve-3562=214

Jan. 5 mid-146

INSTANT NEXT NUMBERS FOR P4 GAMES

EX: CA JAN 1 2013 NUMBERS 4539

4539 PLUS MIRROR

4539=9084

USING TOTAL IN P4 GAMES 9999 SUBTRACT BOTH THE WINNING AND MIRROR NUMBERS

9999                                    9999

- 4539                                - 9084

5460                                     0915

NOW NUMBERS THAT ARE REPEAT SHOULD BE OUT

45 OF 4539            90 OF 9084

54 OF 5460             09 OF 0915

NOW I HAD 39 AND 60                     84 AND 15 LEFT

SINCE 39 AND 84 ARE ON TOP OF BOTH 60 AND 15

3 OF 39 SHOULD BE WITH 6 OF 60

9 OF 39 WITH 0 OF 60

8 OF 84 WITH 1 OF 15

4 OF 84 WITH 5 OF 15

NOW I WILL HAD 3-6 9-0 8-1 4-5

SO WHAT I DO IS NOW SUBTRACT THE RIGHT NUMBERS TO THE LEFT NUMBERS

3-6 IS 6 MINUS 3= 3 SINCE 0 CANT SUBTRACT ABY NUMBERS I WILL CARRY 1 TO IT 0 + 1 = 10 NOW 10 MINUS 9= 1

IF ANY NUMBERS OF RIGHT SIDES IS SMALLER THAN LEFT SIDES JUST CARRY 1 TO IT

SO 11 MINUS 8= 3 AND 5 MINUS 4= 1

NOW I HAD THE NUMBERS 3131

SO WHAT I DO IS ADD THAT NUMBERS TO THE WINNING NUMBERS OF 4539 ON JAN 1 2013 OF CA

4539

+ 3131

7670 THIS JUST REGULAR MATH

NOW SINCE I HAD 3131 ALL I NEED IS A PAIR OF 2 NUMBERS AND ADD THEM TOGTHER SO 3 + 1 = 4

THE 7670 PLUS 4

I GET 7674 WHICH IS THE NEXT WINNING NUMBER IN CA

A STRAIGHT AUTOMATC WIN INSTANTLY

FINALLY I BEAT THE LOTTO SYSTEM OF CA

TAKE THAT SYSTEM AND THAT TOO LOL.

I THINK IT MAY WORK IN P3 TOO

I HAVENT TEST IT OUT YET ON P3 GAMES

SO THANKS ALOT

ANY SUGGESTIONS TO MAKE THIS SECRET TECHNIQUE MORE PERFECT IS ACCEPTED

THANKS

INSTANT NEXT NUMBERS FOR P4 GAMES

EX: CA JAN 1 2013 NUMBERS 4539

4539 PLUS MIRROR

4539=9084

USING TOTAL IN P4 GAMES 9999 SUBTRACT BOTH THE WINNING AND MIRROR NUMBERS

9999                                    9999

- 4539                                - 9084

5460                                     0915

NOW NUMBERS THAT ARE REPEAT SHOULD BE OUT

45 OF 4539            90 OF 9084

54 OF 5460             09 OF 0915

NOW I HAD 39 AND 60                     84 AND 15 LEFT

SINCE 39 AND 84 ARE ON TOP OF BOTH 60 AND 15

3 OF 39 SHOULD BE WITH 6 OF 60

9 OF 39 WITH 0 OF 60

8 OF 84 WITH 1 OF 15

4 OF 84 WITH 5 OF 15

NOW I WILL HAD 3-6 9-0 8-1 4-5

SO WHAT I DO IS NOW SUBTRACT THE RIGHT NUMBERS TO THE LEFT NUMBERS

3-6 IS 6 MINUS 3= 3 SINCE 0 CANT SUBTRACT ABY NUMBERS I WILL CARRY 1 TO IT 0 + 1 = 10 NOW 10 MINUS 9= 1

IF ANY NUMBERS OF RIGHT SIDES IS SMALLER THAN LEFT SIDES JUST CARRY 1 TO IT

SO 11 MINUS 8= 3 AND 5 MINUS 4= 1

NOW I HAD THE NUMBERS 3131

SO WHAT I DO IS ADD THAT NUMBERS TO THE WINNING NUMBERS OF 4539 ON JAN 1 2013 OF CA

4539

+ 3131

7670 THIS JUST REGULAR MATH

NOW SINCE I HAD 3131 ALL I NEED IS A PAIR OF 2 NUMBERS AND ADD THEM TOGTHER SO 3 + 1 = 4

THE 7670 PLUS 4

I GET 7674 WHICH IS THE NEXT WINNING NUMBER IN CA

A STRAIGHT AUTOMATC WIN INSTANTLY

FINALLY I BEAT THE LOTTO SYSTEM OF CA

TAKE THAT SYSTEM AND THAT TOO LOL.

I THINK IT MAY WORK IN P3 TOO

I HAVENT TEST IT OUT YET ON P3 GAMES

SO THANKS ALOT

ANY SUGGESTIONS TO MAKE THIS SECRET TECHNIQUE MORE PERFECT IS ACCEPTED

THANKS

Thanks, i will try to absorb the workout but i must first get past the first hill by asking how you got 9084.

Shouldn't it be 9584?

The mirror of 5 is 0, so 5+0=5, no? or am i doing it wrong?

WHAT I MEANT BY 4539 PLUS MIRROR

IS THAT I MIRROR THE NUMBER 4539

TO ITS MIRROR NUMBER

SO I HAD 9084

9084

I also ran into another problem. Using Florida Jan. 1 as the starting point eve-4194

4914+ mirror=3373

9999 minus 4914=5085

9999 minus 3373=6626

Now here's where I run into a snag. You say to eliminate any repeating pairs, so let's start with 4914. I don't see any repeating pairs, so how would I conitnue? Unless you count 49 Twice, like 4914     4914

And the same problem with 3373, 5085, and 6626. I can't continue until I get a resolution for the first problem with the mirror, and then this one with the pairs.

I'll wait for your response. Thanks.