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P-4 for P-3 pairs giver system

Topic closed. 20 replies. Last post 2 years ago by retxx.

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onlymoney's avatar - stargate pyramid.jpg

United States
Member #128795
June 2, 2012
4664 Posts
Offline
Posted: January 8, 2013, 1:18 pm - IP Logged

OK I SEE

WELL FOR ME

IT SEEMS TO WORK IN CA LOTTERY

BUT I NOT SURE YET ON THE REST OF THE PREVIOUS NUMBERS CUX I ONLY HAD THIS IDEA SINCE YESTERDAY ONLY

AND HAD TESTED IT OUT ON THE JAN 1 P4 GAME "ONCE" ONLY IN CA

IT SEEMS TO WORK FOR THIS SINGLE DIGITS ON JAN 1 ONLY

RIGHT NOW I TRYING TO TEST OUT TO SEE IF I CAN GET AT LEAST 3 OUT OF 4 NEXT WINNING NUMBERS

AND DO SAME METHOD TO SEE IF I CAN GET THE NEXT 1 SINGLE WINNING NUMBER TO BE WITH THE 3 NEXT WINNING NUMBERS

THATS WHAT I AM GOING TO DO AT LEAST NOW.

 

 

 

WELL WHAT I DID WAS USING 9999 MINUS 4539 AND GET 5460 IN HERE

9999

-4539

5460

NOTICED: SINCE THERE IS THE PAIR OF 45 IN 4539 AND 54 OF 5460.

U TAKE THEM OUT FROM 4 TO 4 AND 5 TO 5 CRISS CROSS TAKE OUTS

I GUESS U CAN  SAY IT THE BIG     X        TAKE OUTS

BECUX IT HAD TWO OF THE SAME NUMBERS WHICH IS 4 AND 5

WHICH LEFT ONLY THE 3 AND 9 OF 4539 ON TOP OF RIGHT SIDES 

NEXT TO THE NUMBER 4 AND 5 OF 4539 WHICH WAS TAKEN OUT BY CRISS CROSS

THE BOTTOM RIGHT SIDES WITH ONLY THE 6 AND 0 OF 5460

THE SAME IS FOR THE MIRROR NUMBERS AS WELL

WITH 8 AND 4 OF 9084 ON TOP RIGHT SIDES AND 1 AND 5 OF BOTTOM RIGHT SIDES

9999                                9999

- 4539                            - 9084

54 60                               09 15

 


SO WHAT I DID NOW IS GROUP THEM ALL TOGETHER LIKE THIS:

3 TO 6

9 TO 0

8 TO 1

4 TO 5

NOW NEXT I SUBTRACT NUMBERS FROM RIGHT SIDES TO LEFT

6 MINUS 3 = 3

SINCE 0 CANT SUBTRACT ANY NUMBERS AT ALL I JUST CARRY THE ONE TO THE ZERO MAKING IT A TEN 10

SO 10 MINUS 9 = 1

IF ANY NUMBERS FROM RIGHT SIDES IS LESS THAN LEFT SIDES NUMBERS JUST CARRY 1 TO IT

SO IT CAN SUBTRACT THE LEFT SIDES

NOW NEXT IS 1 MINUS 8 SO CARRY 1 TO IT

1 NOW IS 11 MINUS 8= 3

5 MINUS 4 = 1

SO I GET THE NUMBERS 3131

SE 3131 AND ADDED TO THE WINNING NUMBERS OF 4539

U GET 7670

THEN USE THE 3131 AGAIN BUT THIS TIME ONLY A PAIR SO I GET

31, ADD THEM I GET 4

SO I ADD 4 TO THE RESULT OF 7670 TO BE

 

7674 THE NEXT STRAIGHT WINNING NUMBERS FOR JAN 2 2013 IN CALIFORNIA.

OK I SEE

WELL FOR ME

IT SEEMS TO WORK IN CA LOTTERY

BUT I NOT SURE YET ON THE REST OF THE PREVIOUS NUMBERS CUX I ONLY HAD THIS IDEA SINCE YESTERDAY ONLY

AND HAD TESTED IT OUT ON THE JAN 1 P4 GAME "ONCE" ONLY IN CA

IT SEEMS TO WORK FOR THIS SINGLE DIGITS ON JAN 1 ONLY

 

So you're basically saying that this will only work if the original combo used, the mirror, and the rest of the combos from minusing from 9999 are singles only?

If so, then I 'll have to skip over any that produce doubles or triples.


    United States
    Member #137125
    December 27, 2012
    15 Posts
    Offline
    Posted: January 8, 2013, 1:27 pm - IP Logged

    OK I SEE

    WELL FOR ME

    IT SEEMS TO WORK IN CA LOTTERY

    BUT I NOT SURE YET ON THE REST OF THE PREVIOUS NUMBERS CUX I ONLY HAD THIS IDEA SINCE YESTERDAY ONLY

    AND HAD TESTED IT OUT ON THE JAN 1 P4 GAME "ONCE" ONLY IN CA

    IT SEEMS TO WORK FOR THIS SINGLE DIGITS ON JAN 1 ONLY

     

    So you're basically saying that this will only work if the original combo used, the mirror, and the rest of the combos from minusing from 9999 are singles only?

    If so, then I 'll have to skip over any that produce doubles or triples.

    THE DOUBLES AND TRIPLES I NOT SURE

    CUX I HAVENT TEST IT OUT YET

    RITE NOW I JUST TESTING FOR PREVIOUS WINNING SINGLE DIGITS ONLY 

    TO SEE IF I CAN GET THE NEXT DAY WINNNG RESULTS

    THE WINNING NUMBERS WITH TRIPLE DIGITS AND DOUBLES DIGITS ARE KINDA HARD TO DO

    I WILL NEED MORE TESTING TO DO

      onlymoney's avatar - stargate pyramid.jpg

      United States
      Member #128795
      June 2, 2012
      4664 Posts
      Offline
      Posted: January 8, 2013, 1:53 pm - IP Logged

      THE DOUBLES AND TRIPLES I NOT SURE

      CUX I HAVENT TEST IT OUT YET

      RITE NOW I JUST TESTING FOR PREVIOUS WINNING SINGLE DIGITS ONLY 

      TO SEE IF I CAN GET THE NEXT DAY WINNNG RESULTS

      THE WINNING NUMBERS WITH TRIPLE DIGITS AND DOUBLES DIGITS ARE KINDA HARD TO DO

      I WILL NEED MORE TESTING TO DO

      Ok, thanks. Will try another combo that's single and see what I get.

      Florida Dec. 26 eve-5709

       

       

      5709's mirror is 0254

       

      9999-5709=4290

      9999-0254=9740

       

      5709     4290

      0254     9740

      So let me see how to do this. My question is, does the 50 in 5709 count as a pair? and does the 05 in 0254 also count as a pair, or do they have to be next to each other? Because If they don't count as pairs, how do I line them up across so I can minus from right to left?

      50724927 and 05949400

      I guess if you can't find any repeating pairs, we'll just have to use all of them right? or do we skip over this alltogether and move on to the next eve to play?

      Let's try it by using all the pairs since we can't find any eliminating pairs.

      Ok, first string-50724927

      10-5=5

      12-7=5

      9-4=5

      7-2=5

      So first combo is 5555

      Now add the original number, 5709+5555=0254

      Now add two of the numbers from 5555 to change the last number in 0254, so 5+5=0, so nothing changes cause 5+0=0

       

      0254- oh well, no luck.

      Thu, Dec 27, 20120-1-0-3

       

       

      So lets try the other string, 05949400

      5-0=0

      14-9=5

      14-9=5

      0-0=0

      We have 0550

      Add 0550 to 5709= 5259

      Won't add to change the last number cause it's a 0 again, so the final numbers remains 5259. Winner was 0103, oh well, I wish someone would put this into a program so I can backtest it quicker. But the programmer would firsy need to know what to do when no repeating pairs can be found, does he/she still use all the pairs like i did above, or just skip to the next eve winner. What? 

        retxx's avatar - mrthumbs
        BOSTON
        United States
        Member #48
        September 9, 2001
        3180 Posts
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        Posted: January 9, 2013, 8:55 pm - IP Logged

        hi only money. can you see me kicking  butt because the very first time I used e formula here in Mass which the number was 8364 so you can the play was 231 straight whichI played for eve. Of course knowing the lottery here it came out in mid straight.
        Wonder about what you think of trying to do all 4 somehow using your formula.
        Any thoughts on this?

          onlymoney's avatar - stargate pyramid.jpg

          United States
          Member #128795
          June 2, 2012
          4664 Posts
          Offline
          Posted: January 9, 2013, 9:31 pm - IP Logged

          hi only money. can you see me kicking  butt because the very first time I used e formula here in Mass which the number was 8364 so you can the play was 231 straight whichI played for eve. Of course knowing the lottery here it came out in mid straight.
          Wonder about what you think of trying to do all 4 somehow using your formula.
          Any thoughts on this?

          Funny you mention it. Before I came up this P-3 version, it all started by looking at repeat pairs for the P-4. Once it was apparent that it didn't work too well, I started looking at the P-3. And that's when I discovered the prediction accuracy level rising significantly.

          The P-4 is the Parent, and the P-3 is their children.

            retxx's avatar - mrthumbs
            BOSTON
            United States
            Member #48
            September 9, 2001
            3180 Posts
            Offline
            Posted: January 15, 2013, 1:35 pm - IP Logged

            update to only money. Had another box hit yesterday using just the first program you posted. No mish mush, just subtract from the 4 previous days eve number and play for todays mid and eve.
            Now to try and get a little greedy and figure how to add a 4th digit also using previous eve numbers. Any suggestions?No Pity!