/blogentry/193979 hypersoniq's Blog: Distributions and wondering if a pick 6 would be viable... en-us Lottery Post RSS Generator /blogentry/193979#c280067 /blogentry/193979#c280067 Sat, 16 Aug 2025 01:36:16 GMT grwurston You wouldn't have to pick 6 digits for a box hit. Just eliminate 4 and play the rest.

]]> grwurston /blogentry/193979 /blogentry/193979 Fri, 15 Aug 2025 18:15:52 GMT hypersoniq In the 1,000 pick 3 possible combinations are 720 combos with unique digits. Derived by 10x9x8 = 720. There are 10 triples, 000 through 999 which leaves 1,000 - 730 = 270 combos with a pair.

In the 10,000 pick 4 possible combinations, we use 10x9x8x7 to get 5,040 unique digit combinations, there are 10 quads, 342 triples, 270 two pairs and 4,338 combos with one pair.

In the 100,000 pick 5 possible combinations, using 10x9x8x7x6 yields 30,240 combinations with all unique digits, 10 all the same digits, 450 4 of a kinds, 900 full houses (3+2), 7,200 3 of a kinds, 10,800 having 2 pairs, and finally 61,200 combos with 1 pair.

So, at the pick 5, we cross over into having almost twice as many having one pair than having all 5 digits unique. It is truly amazing that the pick 5 ever gets hit at all...

What if there were a pick 6? NOT a replacement draw jackpot game, but a daily game where 6 machines are used to pick digits? Based on the lottery commission paying about 1/2 of the odds, a straight hit would be worth $500,000 !!!

I wonder if that would be a popular game?

Just for fun, the 6 digit all unique combinations would be 10x9x8x7x6x5 = 151,200...... [ More ]

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