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		<title>Using pick4 numbers to determine next pick3</title>
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		<description>soothsayer's Blog: Using pick4 numbers to determine next pick3</description>
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			<title>Comment #2</title>
			<link>/blogentry/44571#c52603</link>
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			<pubDate>Wed, 04 Aug 2010 02:53:11 GMT</pubDate>
			<dc:creator>soothsayer</dc:creator>
			<description><![CDATA[<p>Thank You Jani.........Am going out on a limb and posting my best pick for midday 8/4 here........679..........(fingers crossed)</p>]]></description>
			<category>soothsayer</category>
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			<title>Comment #1</title>
			<link>/blogentry/44571#c52591</link>
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			<pubDate>Tue, 03 Aug 2010 13:02:06 GMT</pubDate>
			<dc:creator>Jani Norman</dc:creator>
			<description><![CDATA[<p>Excellent discovery........will continue to follow, thank you so much......</p>]]></description>
			<category>Jani Norman</category>
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			<title>Original Blog Entry: Using pick4 numbers to determine next pick3</title>
			<link>/blogentry/44571</link>
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			<pubDate>Mon, 02 Aug 2010 23:04:18 GMT</pubDate>
			<dc:creator>soothsayer</dc:creator>
			<description><![CDATA[<p> I have found a way/system to get pick3 #&#x27;s from the previous pick4 #&#x27;s. I will use today&#x27;s pick3 result and last night&#x27;s pick4 to illustrate. Midday p3 result: 663 , Last nite p4: 9690 . Double #&#x27;s can turn into 0 or it&#x27;s mirror. Using simple lottery math I get: 9/9=0 , 9-6=3 ,9-6=3(since there were two 9&#x27;s) , 6-0=6 , This tels me the 6 is a strong digit because usually at least one of those p4 digits will show in the p3. So I now see a 6 from p4, another 6 from 6-0=6/3+3=6, and of course the 9-6=3.........663!!!<br /><br />... &#x5b;&#xa0;<a href="/blogentry/44571">More</a>&#xa0;&#x5d;</p>]]></description>
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			<category>soothsayer</category>
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