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		<title>Three ON Three</title>
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			<title>Comment #2</title>
			<link>/blogentry/45411#c53306</link>
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			<pubDate>Sat, 28 Aug 2010 15:38:56 GMT</pubDate>
			<dc:creator>ochoop17</dc:creator>
			<description><![CDATA[<p>834&#x3c;br /&#x3e;159&#x3c;br /&#x3e;672 is correct too.</p>]]></description>
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			<title>Comment #1</title>
			<link>/blogentry/45411#c53295</link>
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			<pubDate>Sat, 28 Aug 2010 03:27:45 GMT</pubDate>
			<dc:creator>johnph77</dc:creator>
			<description><![CDATA[<p>7  5  3&#x3c;br /&#x3e;6  1  8&#x3c;br /&#x3e;&#x3c;br /&#x3e;Diagonally adds to 15 as well.&#x3c;br</p>]]></description>
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			<title>Original Blog Entry: Three ON Three</title>
			<link>/blogentry/45411</link>
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			<pubDate>Fri, 27 Aug 2010 13:13:08 GMT</pubDate>
			<dc:creator>ochoop17</dc:creator>
			<description><![CDATA[<p> 3 on 3<br /><br />Using the numbers 1-9 (you can only use each number ONE time) can you make 3 rows of 3 so that the sum total of all 3 digits in any direction (vertical and horizontal) is 15?<br /><br /></p>]]></description>
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