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		<title>Lottery Math for P3/P4</title>
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		<description>time*treat's Blog: Lottery Math for P3/P4</description>
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			<title>Original Blog Entry: Lottery Math for P3/P4</title>
			<link>/blogentry/51835</link>
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			<pubDate>Mon, 28 Feb 2011 17:38:37 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>Non-carrying math<br /><br />P3: 987 + 456 = 333<br /><br />P4: 9557 + 1576 = 0023<br /><br />(use custon formatting to show leading zeroes)<br /><br />Begin by splitting the old numbers ... sum by column, mod sums by 10, then place the new numbers.<br /><br />* D E F G H<br /><br />2<br /><br />3 987 = INT(D3/100) = INT(MOD(D3,100)/10) = MOD(D3,10)<br /><br />4 456 = INT(D4/100) = INT(MOD(D4,100)/10) = MOD(D4,10)<br /><br />5 =E5*100+F5*10+G5 =MOD(E3+E4,10) =MOD(F3+F4,10) =MOD(G3+G4,10)<br /><br />6<br /><br />7<br /><br />8 9557 = INT(D8/1000) = INT(MOD(D8,1000)/100) = INT(MOD(D8,100)/10) = MOD(D8,10)<br /><br />9 1576 = INT(D9/1000) = INT(MOD(D9,1000)/100) = INT(MOD(D9,100)/10) = MOD(D9,10)<br /><br />10 =E10*1000+F10*100+G10*10+H10 =MOD(E8+E9,10) =MOD(F8+F9,10) =MOD(G8+G9,10) =MOD(H8+H9,10)<br /><br />Visually =E10 F10 G10 H10 gives the same result as =E10*1000+F10*100+G10*10+H10.<br /><br />The difference is the first is a text string, the second is still a number. You can do further calculations on the second.<br /><br />*Sometimes you&#x27;re not using cell A1<br /><br />=E5*100+F5*10+G5<br /><br />... &#x5b;&#xa0;<a href="/blogentry/51835">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Blog Entry</category>
			<category>time*treat</category>
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