Original Blog Entry: One way of using LSA's Last Out Report

Developer — Tue, 01 Nov 2011 22:34:50 GMT

Hi, continuing with my coverage of the reports found in LSA today I am going to cover the LAST OUT report, this report and graph provide information and statistics on the last numbers to appear.

For this demonstration I will be using the UK's Plus 5 - 6/49 draw, but this will work with any draw in LSA. This draw has 13,983,816 combinations so just a few combinations there to choose from.

The primary aim of this report is to show the user how many draws have occurred since each ball last appeared, I am going to show you how to use this report along with another report to find the next best number for ball position 1, but first a quick insight into the graph.

Using LSA's Last Out report

The graph in the above image is filtered on ball 1, which clearly shows a bias toward the lower range of the graph.

Quick Information you should know:

The bars in the graph represent the number of draws past without a show for each ball. Higher bars mean less appearances over time, hence less likely. Bars at 0 mean the number last appeared in the last draw.

Example of usage:

In LSA select the options Counts - Last Out By default Ball 1 is selected so leave as is for now. Click the report button Move the report that opens aside, leaving it open as you will need this in a moment. Click the menuReports - Global Reports - True Hot Warm Cold Now align top and bottom on your screen theTrue Hot Warm Coldand theLast Outreports as in the picture below.

Above are two samples one from each graph which I will refer to as A and B from now on.

Pen and paper might be a good idea or Excel if you have it would be great for this.

We want to see the likelihood of each number appearing in the next draw.

This is how.......

Using ball position one

Ball 1

(A) shows ball 1 was drawn 1 draw ago, (B) says ball 1 appears every 8 draws. So this one is simple ball one mathematically will appear in 7 draws time. 8 - 1 = 7

Ball 2

(A) shows ball 2 was drawn 5 draws ago (B) say ball 2 appears every 9 draws in position 1. (B) say ball 2 appears every 78 draws in position 2 Now this gets a little more involved Calculate when ball 2 is due to appear as ball position 1 9 - 5 = 4 : Ball 2 is due to appear in position 1 in 4 draws time Calculate when ball 2 is due to appear as ball position 1 Number 2 was last seen 05 draws ago as ball position 1 9 - 5 = 4 : Ball 2 is due to appear in position 1 in 4 draws time Repeat for 10 to 15 draws to get a results like the following Ok 6 is enough for this demo, from this it can be seen that ball 6 is most likely to appear Now you understand how to find the mathematical best picks repeat for ball position 2, 3 ,4 etc Join the sums of the positions A and b for each set to see the best candidate globally

I know this can take some time but it's well worth the effort, I say this because I have had another user report a large win a few weeks ago and after some urging on my part this is how he told me he found the numbers that hit 5 of 6.

Good luck

More tomorrow

... [ More ]