https://blogs.lotterypost.com/jadelottery/2014/2/quantum-quasiality.htm JADELottery's Blog: Quantum Quasiality. en-us Lottery Post RSS Generator https://blogs.lotterypost.com/jadelottery/2014/2/quantum-quasiality.htm#c123025 https://blogs.lotterypost.com/jadelottery/2014/2/quantum-quasiality.htm#c123025 Sun, 16 Feb 2014 23:44:06 GMT JADELottery We'll get you Humons up to speed yet.

]]> JADELottery https://blogs.lotterypost.com/jadelottery/2014/2/quantum-quasiality.htm https://blogs.lotterypost.com/jadelottery/2014/2/quantum-quasiality.htm Sun, 16 Feb 2014 21:27:57 GMT JADELottery Now, that you have seen the Common Math applied to Boolean States.

Let's look at a Quasi Boolean State, where the boolean state is not just an absolute 0 or 1, but a value greater than 0 and less than 1; some Probable state between 0 and 1.

Let's say we can only be 50% certain of A and B are either 0 or 1, then A = 0.5 and B = 0.5.

Then (A And B) = A B = 0.5 0.5 = 0.25

From the truth table in the absolute states we have

(A And B) = A B

A B A And B

0 0 0

0 1 0

1 0 0

1 1 1

If we average the total outcomes it becomes, (0 + 0 + 0 + 1) / 4 = 1 / 4 = 0.25; just what we got when we took a 50/50 guess on their states.

Let's try the Or condition: (A Or B) = A - (A B) + B = 0.5 - (0.5 0.5) + 0.5 = 0.5 - 0.25 + 0.5 = 0.75

Looking at the truth table for Or,

(A Or B) = A - (A B) + B

A B A Or B

0 0 0

0 1 1

1 0 1

1 1 1

Now, average the outcomes, (0 + 1 + 1 + 1) / 4 = 3 / 4 = 0.75

And one more for Xor.

(A Xor B) = A - (A B) - (A B) + B = 0.5 - (0.5 0.5) - (0.5 0.5) + 0.5 = 0.5 - 0.25 - 0.25 + 0.5 = 0.5

Truth table for Xor

(A Xor B) = A - (A B) - (A B) + B

A B A Xor B

0 0 0

0 1 1

1 0 1

1 1 0

Average the outcomes, (0 + 1 + 1 + 0) / 4 = 2 / 4 = 1 / 2 = 0.5

... [ More ]

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