Sequencial Groups Predicting

Reply #7

paint1 — Sat, 10 Dec 2005 21:32:53 GMT

I used to do something very similar to this for the 6/49 game. It often gave 3 or 4 numbers never more.After we finish Lantern's filtering lessons who knows. Might have to come back to this.

Reply #6

JKING — Fri, 09 Dec 2005 05:19:52 GMT

dynodyno,I'm not familiar with 6/49. If it's a 5 ball +1 bonus ball then:49/5=9.89.8*3=29.4I would probably go for a 29 game spread. With an average hit of 3 per number, practically every number should have a hit value of at least 1+.dynodyno, this system is new and in progress. I'm trying to make a break from the norm here and change the mindset. It will become more refined. I feel the core concept isn't very far off the mark.

Reply #5

dynodyno — Fri, 09 Dec 2005 01:50:48 GMT

Hi Jking, for a 6/49 game, would you still go with 23 games as a game spread

Reply #4

JKING — Fri, 09 Dec 2005 01:43:49 GMT

I've just started using it and had success. I had an earlier post where I said that I would detail the strategy more completely. I hope the following will anser you questions:How many times did each number occur the last 23 games(1-22), how many times for the 23 games before that(23-45), how many times for the 23 games before that(46-68), and finally how many times did each number occur for the 23 games before that (69-91). So you are measuring occurrances of each lottery number 4 times in equal... [ More ]

Reply #3

RJOh — Fri, 09 Dec 2005 00:36:38 GMT

In that case, how well has it worked with California Fantasy5? I didn't understand what you meant by a game spread of 23 for occurrences of numbers in segments 1-22,23-46,47-68,69-91 for a 5/39 game.

Reply #2

JKING — Thu, 08 Dec 2005 23:14:28 GMT

Rjoh, I don't know, I have barely enough time for CA. Theoretically, it should work for all 5/39 games.

Reply #1

RJOh — Thu, 08 Dec 2005 22:49:52 GMT

How do those figures compare to an actual 5/39 game like Ohio Rolling Cash5

Sequencial Groups Predicting

JKING — Thu, 08 Dec 2005 22:03:18 GMT

For 5/39 take a game spread of 23. Then get occurrences, by lotto number, in the segments 1-22, 23-46, 47-68, 69-91. At that point I calculated the overall average occurrence by lotto number using the four segments.To predict, I took the occurrences for each number over the last 20 games and found the highest differences from the average.The first test got 3 out 5....we'll see how it goes.note: there were a couple additional filters, but this was the core of the program.Any comments