If you were to SUM all 1000 numbers

Reply #11

Raven62 — Sun, 11 Dec 2005 19:51:15 GMT

Take the first (000) and last (999) numbers and add them together (999) then multiply 999 by 500 (500 pairs: 001+998=999, 002+997=999, etc) for a sum of 499,500. (4+9+9+5=27) Root Sum is 9.

Reply #10

hypersoniq — Sun, 11 Dec 2005 15:25:51 GMT

9that's also the same sum for all 10000 pick4 combos49,995,000 = 4+9+9+9+5+0+0+0 = 363+6=9LD=6 (differing from the 3digit LD of 7

Reply #9

sirbrad — Sun, 11 Dec 2005 14:20:02 GMT

9 is what I got also.

Reply #8

WIN D — Sun, 11 Dec 2005 13:55:39 GMT

It's input! We need input, man. ahhh input.... More input

Reply #7

truecritic — Sun, 11 Dec 2005 12:12:42 GMT

Does it help anything to know that

Reply #6

Raven62 — Sun, 11 Dec 2005 11:48:00 GMT

Who would have guessed

Reply #5

lottaloot — Sun, 11 Dec 2005 11:21:59 GMT

Interesting.

Reply #4

Raven62 — Sun, 11 Dec 2005 10:51:46 GMT

The Root Sum of the Sum of 000 thru 999 is 9.

Reply #3

lottaloot — Sat, 10 Dec 2005 16:41:56 GMT

You tell us cuz I sure don't know. But I will take my chances with WSLS.

Reply #2

winsumloosesum — Fri, 09 Dec 2005 19:01:14 GMT

Sum of Pick 3 numbers 000 through 999 = 499,500Sum = 4 + 9 + 9 + 5 + 0 + 0 = 27Root Sum = 9Left Digit Sum = 7

Reply #1

winsumloosesum — Fri, 09 Dec 2005 18:35:42 GMT

Sums 0 through 27 = 13,500Root Sums = 4950Last Digit Root Sums: 4500

If you were to SUM all 1000 numbers

Raven62 — Fri, 09 Dec 2005 18:26:19 GMT

If you were to SUM all 1000 numbers of the Pick-3 Lottery: What would be the resultant Root SUM?(ie: 000 thru 999