<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/">
	<channel>
		<title>off topic, for excel people</title>
		<link>https://www.lotterypost.com/thread/126410</link>
		<atom:link href="https://www.lotterypost.com/rss/topic/126410" rel="self" type="application/rss+xml" />
		<description>Lottery Post Forum Topic: off topic, for excel people</description>
		<dc:language>en-us</dc:language>
		<generator>Lottery Post RSS Generator</generator>
		<item>
			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/126410/518683</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/126410/518683</guid>
			<pubDate>Thu, 12 Jan 2006 19:59:28 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>Put your time in cell(1,1). e.g. 17:45Make sure there is no date component by looking in the formula bar up top.(it should read 5:45:00 PM with no date.)In cell(1,2) type  =RC[-1]*24 set number format in cell(1,2) to general</p>]]></description>
			<category>time*treat</category>
		</item>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/126410/518622</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/126410/518622</guid>
			<pubDate>Thu, 12 Jan 2006 18:55:01 GMT</pubDate>
			<dc:creator>hareless</dc:creator>
			<description><![CDATA[<p>any time I input. This is actually for work...haha.i looked at the time serial, I may need to look at it harder.</p>]]></description>
			<category>hareless</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/126410/518307</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/126410/518307</guid>
			<pubDate>Thu, 12 Jan 2006 11:13:21 GMT</pubDate>
			<dc:creator>Todd</dc:creator>
			<description><![CDATA[<p>I know that Visual Basic stores time and date information internally as a number, with the date being the part to the left of the decimal and the time to the right of the decimal.VB has two functions -- DateSerial() and TimeSerial() -- which extract the numeric representations.You may be able to use TimeSerial(), and then create some kind of multiplication formula or something that converts it into the hour.minutes format that you want.</p>]]></description>
			<category>Todd</category>
		</item>
		<item>
			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/126410/518303</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/126410/518303</guid>
			<pubDate>Thu, 12 Jan 2006 10:54:53 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>Do you want to convert your system&#x27;s time, or any arbitrary time you input</p>]]></description>
			<category>time*treat</category>
		</item>
		<item>
			<title>off topic, for excel people</title>
			<link>https://www.lotterypost.com/thread/126410</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/126410</guid>
			<pubDate>Wed, 11 Jan 2006 21:16:50 GMT</pubDate>
			<dc:creator>hareless</dc:creator>
			<description><![CDATA[<p>I need to have a formula that converts time. What I mean is, change it to decimals.so for instance I put in 15:30 (hour, min)I want the formula to divide the minutes by 60 and display the decimal version of that.So it would give me 15.5 anyone know? I have been looking, but can&#x27;t find the answer.</p>]]></description>
			<category>hareless</category>
		</item>
	</channel>
</rss>

