Need help with straight pick 4 wheel

Reply #13

powerplayer — Fri, 13 Jan 2006 18:55:12 GMT

I thought this might be usefull for everyone:Singles,(ABCD)December,05Key,Digit,(0):,3086,3052,2890,2406,5609,9508,3940,4201,9042,4350,3950,4091,4701,1820,1702,0678,4103,4270,1062,0753,9803,4069,9130,1905,2670,0937,2034,0896,7908,7640,2506,8250,3650,0841,0832,8074,6901,1086,3015,6805,0485,7310,0846,4028,0189,0718,0932,3740,2405,2690,9205,1750,0176,2031,2807,6034,5830,0794,4160,0971,1920,0936,2015,3870,9540,2750,0489,8340,8130,5740,0362,0679,5607,0637,6820,0581,2370Key,Digit,(1):,,1928,8491,4201,... [ More ]

Reply #12

truecritic — Fri, 13 Jan 2006 18:41:38 GMT

If you box a 4 digit number for the Pick4, that will produce 24 possible combinations (as long as each digit is unique i.e. 1,2,3,4 not 1,2,2,3 or 1,2,2,2 or 1,1,1,1). If you were to lay those out separately, you would have 24 tickets. Boxing is simply a convenient way of making those bets. If your digits are the correct ones that are drawn, by boxing (or playing each individually), you will have a straight hit. The reason the payoff is smaller for a boxed $1 ticket is because you are dividi... [ More ]

Reply #11

time*treat — Fri, 13 Jan 2006 18:11:36 GMT

in this case r=40! = 1 and 1! = 1 so 4!/1 = 245!/1! = 5!/ (5-4)! = 5p4 = 1206!/ (6-4)! = 6!/2! = 6p4 = 360 7p4 = 8408p4 = 16809p4 = 302410p4 = 5040 <-- that one should look familiar

Reply #10

cps10 — Fri, 13 Jan 2006 14:30:10 GMT

LOL

Reply #9

retxx — Fri, 13 Jan 2006 14:26:32 GMT

now if someone can write it to a spreadsheet for us laymen maybe it might be the key to a winning system for the pick 4. Anyone want to give it a try

Reply #8

calabs — Fri, 13 Jan 2006 14:20:03 GMT

Thanks time*treat - Forgive my ignorance, but what is represented by r

Reply #7

time*treat — Fri, 13 Jan 2006 02:01:42 GMT

If you want to know the number of permutations the formula is: n!/(n-r

Reply #6

calabs — Thu, 12 Jan 2006 19:22:55 GMT

Quote: Originally posted by Raven62 on January 12, 2006 I'm not sure why you would want to unbox the pick4 numbers to their 24-way, 12-way, 6-way, 4-way combinations. A wealth of information exits in the forums and some of it can be found with the search function:

https://www.lotterypost.com/thread/108382

Inquiring minds want to know!!!

I do a search. Thanks.

Reply #5

Raven62 — Thu, 12 Jan 2006 19:14:22 GMT

I'm not sure why you would want to unbox the pick4 numbers to their 24-way, 12-way, 6-way, 4-way combinations. A wealth of information exits in the forums and some of it can be found with the search function:

https://www.lotterypost.com/thread/108382

Reply #4

calabs — Thu, 12 Jan 2006 16:41:40 GMT

thanks Lottaloot - WOW, that's way over my Excel head! I was hoping for something a little less intimidating ! Like 4 numbers = 24 combosLike 5 numbers = XX combosLike 6 numbers = XXX combos Is something like this easy to crunch? My guess is it would be way to staggering of a number to actually play all combos past 4 numbers, but would like to know. Thanks again.

Reply #3

lottaloot — Thu, 12 Jan 2006 16:41:19 GMT

Here's what you do. Place C in A1 4 in A2And the numbers that you want in A3: down to whateverRun the code in order to see that wheels...There will be another sheet added to your workbook. Doesn't give you straights but I am sure someone could tweak the system a bit to make it do straights.

Reply #2

lottaloot — Thu, 12 Jan 2006 16:39:47 GMT

Option Explicit 'Written by Myrna Larson - Microsoft Excel MVPDim vAllItems As VariantDim Buffer() As StringDim BufferPtr As LongDim Results As Worksheet Sub ListPermutations() Dim Rng As Range Dim PopSize As Integer Dim SetSize As Integer Dim Which As String Dim N As Double Const BufferSize As Long = 4096 Set Rng = Range(Range( A1 ), Cells(Rows.Count, A ).End(xlUp)) PopSize = Rng.Cells.Count - 2 If PopSize < 2 Then GoTo DataError SetSize = Rng... [ More ]

Reply #1

cps10 — Thu, 12 Jan 2006 16:29:08 GMT

calabs - I think that is something I am trying to get to as well. I was working with pairs though.

Need help with straight pick 4 wheel

calabs — Thu, 12 Jan 2006 16:21:01 GMT

For a pick 4 wheel which has 4 numbers, the required lines to get every combo straight would be 24 (I believe this is right). This assumes no doubles or triples, etc. What would be the minimum combination for a 5 number wheel? What about a 6 number wheel? Is there a formula anyone is willing to share? Thanks