What does a Winning formula require?

Reply #14

Thoth — Sat, 25 Mar 2006 06:23:15 GMT

For me, a winning formula would have to take advantage of a loophole in the laws of probability. Not that one actually exists, but if one were ever to be found, you could bet that this is what the formula would revolve around. Perhaps the loophole would be a probability within a probability of sorts, maybe 10 layers deep, maybe more.

If you could take several combinations and give each one of them an individual 50% chance to be drawn within a measured (but short span) of trials, then a

Reply #13

Shane3 — Fri, 24 Mar 2006 19:14:31 GMT

Here is the problem.......the lotto drawings are actually designed to dance around all numbers waged by the betting public. It will then settle on the numbers with the least amount of payout. That is why it is a game of luck. You have got to be lucky form when they are compelled to drawn 6 numbers that has actually been waged by someone. Haven't you noticed that most winners come after the Jackpot crosses $100 million. The higher the total....the bigger the freenzy....the more money the States m... [ More ]

Reply #12

RJOh — Thu, 23 Mar 2006 19:34:49 GMT

If there was a formula or system that could come up with the winning combinations even some times then it could be simulated on paper or in your computer. There is no need to ask how about my formula or system or what about that formula or system when you have a computer. If you really want to know if a formula or system works then simply test it.

I doubt if anyone taking the time to develop and test a formula or system that worked even some times would post it for the benefits of othe... [ More ]

Reply #11

NewClub — Thu, 23 Mar 2006 17:35:53 GMT

How about my formula?

https://www.lotterypost.com/thread/129944.htm

Quote: Originally posted by NewClub on March 23, 2006 That reminds me of the idea to play all 146,107,962 combinations some one mentioned before. It has been proposed a 4000 terminal hours needed for that purpose. So for a 1000 member pool, each one would spend 4 hours and buy 146,108 tickets.

Say the previous JP is 200m.

If no one share the JP, then each member makes $150,000, double the money.

If JP is shared

Reply #10

xavier102772 — Tue, 28 Feb 2006 18:49:53 GMT

Oops, combinations to start sould have been more like 300, not 657....I was thinking of another strategy's combinations.

Reply #9

xavier102772 — Tue, 28 Feb 2006 00:49:15 GMT

I like your thought processes JKING. I've also thought along these same lines in testing and trying different strategies and systems. And yes it is very much a multiplication of the components of the whole system.

As an example: Parts of a system for pick3 I am working(still testing....takes a lot of time) on involves this thought.

1. There is a 55% chance that one number will repeat in the next draw. 657 combinations.

2. Add 1-6 filters from a software package of choice that wi... [ More ]

Reply #8

Greg — Sun, 26 Feb 2006 01:02:52 GMT

INTUITION

Reply #7

MADDOG10 — Sat, 25 Feb 2006 17:08:06 GMT

now, that is the best definition of luck that has come across these pages in a long time...

Reply #6

Butters — Sat, 25 Feb 2006 16:55:06 GMT

Hello,

Many systems could be considered Winning formulas as most of them can consistently beat the odds.The problem is these systems have not yet beaten the odds to the point where they would be profitable or pratical.

Current systems that are publicly available seem to elimiate too many possible comblinations therefore they eliminate the winner,or they generate so may possible combinations its is not profitable or pratical to play them all.

One system I have been testing is MDI... [ More ]

Reply #5

Dream — Sat, 25 Feb 2006 01:38:36 GMT

MONEY AND LUCK

Reply #4

time*treat — Sat, 25 Feb 2006 01:36:24 GMT

Instead of multiplying, how about adding? Maybe your winner shows up in 3 or 4 of your 5 systems/filters.

Reply #3

truecritic — Fri, 24 Feb 2006 21:54:37 GMT

Instead of multiplication, think of it as a multiple regression equation.

gems*X +sums*Y +V-tracs*Z etc; =a win=1

Reply #2

RJOh — Fri, 24 Feb 2006 21:42:11 GMT

Winning formula implies that when used the results will be the same as the drawing outcome while the outcomes of the drawings are one of thousands of possible outcomes picked randomly.

Reply #1

Raven62 — Fri, 24 Feb 2006 19:49:52 GMT

What does a Winning formula require?

LUCK

What does a Winning formula require?

JKING — Fri, 24 Feb 2006 18:03:05 GMT

I think of a winning formula as a multiplication problem. If you take a comment made on another post:

incorpate all the systems, gems,sums,V-tracs,Elimination,pairs,

lead and pointers, and you will be able to narrow it down.

You would have gems x sums x V-tracs x Elimination x pairs x leads and pointers =a win=1

So if V-tracs=0 then you lose

If V-tracs is only half right then your final equivalency is less than 1 and you lose

Consequently, each element must be 100% corre... [ More ]