Powerball Normal Distrubution 55-5

Reply #23

Just6ntlc — Tue, 09 May 2006 17:45:42 GMT

Wow, that's a great bell curve and distribution.

Reply #22

Developer — Sun, 23 Apr 2006 11:28:17 GMT

Some facts found so far

In a 6/49 draw (ignoring any bonus numbers)

There are 935,151 combinations that total 100 or less in a 6/49 distribution, this proved to be an unlikely occurrence in all draws tested

avg 6.1% of all drawings fell in this range, ignoring this range when betting reduces the odds by nearly 1 million,

so for every 100 draws you play it is likely 6 will be in this range. if you were able to bet 923,973 per draw this knowledge would save you a substantial amount o... [ More ]

Reply #21

RJOh — Sat, 22 Apr 2006 22:52:35 GMT

Sounds like you are coming to the same conclusions that others have come to before you, that is a lot of knowledge about combinations or past drawings of a lottery is of little value when predicting future winning numbers. While I believe that's true when picking a few combinations, it is essential when picking a large group of numbers to play. Good luck on your search.

Reply #20

Developer — Wed, 19 Apr 2006 23:59:45 GMT

I have decided the distribution of a draw is not the way to go, this conclusion is after my computer ran for days calculating variants of the normal distribution against the draw distribution.

I have however found a use for the normal distribution

My goal now is to standardise any lottery results regardless of pick or pool.

A reference/ranking table for any draw if you like. (1 table fits any draw)

How to explain this one....

Right as an example; take the Standard Distribution tab... [ More ]

Reply #19

Jacques — Fri, 14 Apr 2006 16:08:40 GMT

Developer,

Have you tried the Maximum Likelihood Estimators for Binomial/Normal Distributions?.

Regards

Jacques

Reply #18

time*treat — Wed, 12 Apr 2006 15:35:09 GMT

If you don't have all 5 numbers, it is better that you also don't have the winning sum.

Reply #17

cmpmcg25 — Wed, 12 Apr 2006 00:41:48 GMT

Numbers for Miday 4/11/06 21-29-33-39-44 And Evening numbers are 17-21-33-34-41 Ok now the Hot digits for Miday where from the 4/10/06 Hot/cold/overdue Are from 50 Draws HOT DIGITS ARE= 33-42-06-20-02-08 / COLD DIGITS ARE= 34-32-44-37-30-27/ OVERDUE DIGITS ARE= 27-37-40=24=03-11. And the Evening digits are HOT # 08-16-35-01-10-05/ COLD# 21-39-44-34-18-07/ OVERDUE# 21-06-22-33-38-39 Hope this will help! thanks,

Reply #16

Developer — Tue, 11 Apr 2006 22:32:58 GMT

Prediction 1 (All Calculated for draw on 11th April 2006)

Don't know what the results were for the 11th April 2006 mid-day maybe some one can post them so we can see if using the distrubution of the draw is better using more or less draws

Reply #15

Developer — Tue, 11 Apr 2006 22:18:30 GMT

Heres some info on the Missouri Show-Me 5 Midday

May be this will help you pick those lucky numbers

Stats calculated from draw 1 to 04/08/06

======= Average Appearance Report =======

Ball = The Ball Number

Count = The number of draws each ball has appeared in

Avg = Shows the average number of draws that pass before this ball appears again

Last = Shows the number of draws past since the number last appeared

Ball-Count-Avg -Last

01 - 85 - 7.3 - 6

02 - 86 - 7.2 - 7... [ More ]

Reply #14

johnph77 — Tue, 11 Apr 2006 06:31:49 GMT

61 drawings out of 3,478,761 possibilities is probably too small a sample to be drawing any conclusions, but

Out of the 3,478,761 possibilities, 1,722,712, or 49.52%, have sums that fall between 130 and 180. 32 of the 61 drawings, or 52.46%, have this characteristic.

Out of the 3,478,761 possibilities, 2,404,939, or 69.13%, have sums that fall between 105 and 175. 39 of the 61 drawings, or 63.94%, have this characteristic.

Thanks, RJOh, for doing the slogging.

gl

j

Reply #13

cmpmcg25 — Tue, 11 Apr 2006 04:19:50 GMT

Numbers i have chose for Miday are 3-7 -11-34-37 Evening are 7-8-16-22-38

Reply #12

cmpmcg25 — Tue, 11 Apr 2006 04:05:24 GMT

Thank you Developer can you do Miday to i am very interest in this. Hoping to hit it big one of these days. Always win $2.00 and hit $25.00 twice. Thank you for your help.

Reply #11

Developer — Tue, 11 Apr 2006 03:49:49 GMT

Heres an example of a predition for the Missouri Show Me 5 evening draw using the distrubution table of the draw.

The pic above shows the past 30 draws as of 03/21/06

The prediction is for 03/22/06 , results were (7 11 12 30 42) bad one to choose

The blue line represents the predition line its a LOWESS (Robust locally weighted regression and smoothing scatterplots)

Info on LOWESS

LOWESS works by assuming a small segment of any curve can be approximated by a straight line. For each d... [ More ]

Reply #10

Developer — Tue, 11 Apr 2006 03:32:57 GMT

ID - Sum - Times

1 - 15 - 1 - Min

2 - 16 - 1

3 - 17 - 2

4 - 18 - 3

5 - 19 - 5

6 - 20 - 7

7 - 21 - 10

8 - 22 - 13

9 - 23 - 18

10 - 24 - 23

11 - 25 - 30

12 - 26 - 37

13 - 27 - 47

14 - 28 - 57

15 - 29 - 70

16 - 30 - 84

17 - 31 - 101

18 - 32 - 119

19 - 33 - 141

20 - 34 - 164

21 - 35 - 192

22 - 36 - 221

23 - 37 - 255

24 - 38 - 291

25 - 39 - 333

26 - 40 - 377

27 - 41 - 427

28 - 42 - 480

29 - 43 - 540

30 - 44 - 603

31 - 45 - 674

32 - 46 - 748

33 - 47 - 831

34 - 48 - 9... [ More ]

Reply #9

cmpmcg25 — Tue, 11 Apr 2006 03:22:09 GMT

Hello everyone can you give me the showME 5 in Missouri please! Thank You,

Reply #8

Developer — Tue, 11 Apr 2006 03:14:56 GMT

I am just coding my program to do that, I am having problems mapping the Norm Dist to the draws dist so I can display them in the same chart, the distribution of this draw (NJ) is very strange, I almost say it is not random according to what I have hear, getting almost straight lines on a regression analysis comparing the two.

May be a calculation error on my part will check again, will post it when done

Reply #7

RJOh — Tue, 11 Apr 2006 03:02:04 GMT

How does the normal distribution compare with the actual distribution? When looking at the last 61 PB drawings, the actual peek seems to be forming at a point higher than the means.

Reply #6

Developer — Tue, 11 Apr 2006 02:22:44 GMT

Heres the normal distrubution for the NJ 5/40

ID - Sum - Times

1 - 15 - 1 - Min

2 - 16 - 1

3 - 17 - 2

4 - 18 - 3

5 - 19 - 5

6 - 20 - 7

7 - 21 - 10

8 - 22 - 13

9 - 23 - 18

10 - 24 - 23

11 - 25 - 30

12 - 26 - 37

13 - 27 - 47

14 - 28 - 57

15 - 29 - 70

16 - 30 - 84

17 - 31 - 101

18 - 32 - 119

19 - 33 - 141

20 - 34 - 164

21 - 35 - 192

22 - 36 - 221

23 - 37 - 255

24 - 38 - 291

25 - 39 - 333

26 - 40 - 377

27 - 41 - 427

28 - 42 - 480

29 - 43 - 540

30 - 44 - 603

31

Reply #5

RJOh — Mon, 10 Apr 2006 15:16:39 GMT

Since the last PowerBall matrix change 32 of the 61 drawings had sums between 130 and 180 and 39 had sums between 105 and 175.

Reply #4

johnph77 — Mon, 10 Apr 2006 09:39:20 GMT

https://www.lotterypost.com/news/132174.htm

According to Gail Howard in the above thread, one should play toward the center of the probabilities - 2 or 3 odd/even, 2 or 3 high/low, and tend toward the median of the sums. Extrapolating on the example given there for a 5/40 matrix, my best guess would be sums between 105 and 175 for the Powerball 5/55 matrix. I'm not sure how the differing number of odd and even numbers would affect her thinking on this, though. Also, five consecutive numbers w... [ More ]

Reply #3

RJOh — Mon, 10 Apr 2006 01:08:51 GMT

Developer writes:

It is possible to create an algorithm that could predict every past draw as we know what the numbers were, if someone spent enough time they could produce this formula and then use it against the next draw. Worth thinking about.

I've thought about it and I would be satisfied with an algorithm that could predict past drawing in 50 lines 5% of the time. That would amount to picking 50 lines every drawing and having the winning combination at least five times per year. I... [ More ]

Reply #2

Developer — Sat, 08 Apr 2006 02:53:45 GMT

Yes I completely agree, the bell shape curve just shows the vast amount of number combinations in a very small area, does not help in any way to pick a winning combination, although it is in there somewhere and is every draw.

What we need is someone to work out how to divide the curve in to areas of probability, percentages etc so we know what to discard and what to keep, maybe a little pixie may help, a little magic should do the trick.

It is possible to create an algorithm that could pre... [ More ]

Reply #1

LckyLary — Sat, 08 Apr 2006 01:50:23 GMT

If you cut a pizza into 8 slices, 7 of them have 'shrooms and 1 has pepperoni, you would have a distribution where the odds of getting stuck with 'shrooms is .875 but yet the chance of picking any given slice at random is .125

The odds of choosing any set of Powerball numbers on the lower 5 is the SAME no matter what they add up to. There are vastly more COMBINATIONS that add up to your medium than there are odd sets with very low or high add-ups. So yes the actual numbers are that much... [ More ]

Powerball Normal Distrubution 55-5

Developer — Sat, 08 Apr 2006 01:20:28 GMT

Reading a past post about normal distribution or the bell curve as some call it I wanted to post my own two cents worth, however the post was closed so I though I would start my own.

I use this site allot but rarely post so here's my contribution.

The above shows the bell curve of the Powerball Lottery, not much use as a picture so here is the data that makes the above curve.

Sum Times

15 - 1 - Min

16 - 1

17 - 2

18 - 3

19 - 5

20... [ More ]