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		<title>Binary Pick 3 Anyone?</title>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/146844/733686</link>
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			<pubDate>Tue, 19 Dec 2006 12:55:18 GMT</pubDate>
			<dc:creator>Todd</dc:creator>
			<description><![CDATA[<p>You might want to keep it like it was before, because it gives the most value to recent drawings, but that&#x27;s your call -- it&#x27;s your system!<br /><br />The way binary works is that you start with the right-most digit, which is 0 or 1.  Then, as you move to the left, the value is doubled, so a zero is still worth 0, but a 1 is worth 2.  The next digit to the left you double again, so it&#x27;s worth 0 or 4, and so on.<br /><br />Therefore, the sequence 011100100010111 would be (reading from right-to-left):<br /><br />1 + 2... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/146844/733686">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Todd</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/146844/733599</link>
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			<pubDate>Tue, 19 Dec 2006 04:44:53 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>Quote: Originally posted by Raven62 on December 17, 2006<br /><br />210000000000<br /><br />005210000000<br /><br />421526310000<br /><br />842684268421<br /><br />-------------<br /><br />001111000101<br /><br />512+256+128+064+004+001=965<br /><br />Binary and hexadecimal numbers are two alternatives to the traditional decimal numbers we use in daily life. Engineers and mathematicans sometimes call the binary numbering system a base-two system because binary numbers only contain two digits. By comparison, our normal decimal number system is a base-ten system. All bi... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/146844/733599">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Raven62</category>
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			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/146844/733508</link>
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			<pubDate>Tue, 19 Dec 2006 02:09:33 GMT</pubDate>
			<dc:creator>Thoth</dc:creator>
			<description><![CDATA[<p>You are exactly right Todd...except I think I overlooked one important aspect of binary numbers.  If they are supposed to be built and/or read from right to left then all my outcome sequences need flipped horizontally.  The left-most digit in the sequence is the outcome of the 1st span of 693 games and the right most the 15th.  Hmm...I may have gotten in a little over my head with this idea lol.<br /><br />The 16th digit would all be zeros until the combo hits (if it hits).  One interesting thing to wat... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/146844/733508">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Thoth</category>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/146844/732887</link>
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			<pubDate>Mon, 18 Dec 2006 02:56:49 GMT</pubDate>
			<dc:creator>Todd</dc:creator>
			<description><![CDATA[<p>Thoth,<br /><br />This is a very interesting and unique way of looking at things, thanks for sharing it!<br /><br />One the things I really like about it is that it uses the value of a huge history of drawing data effectively, and does so using the most basic principle of a  1  or a  0 .  Great stuff!<br /><br />Just so I can understand clearly, you are starting with the right-most digit in the binary sequence, and working your way left, correct?<br /><br />If I have this correct, if the straight combo  0-0-0  was drawn anytim... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/146844/732887">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Todd</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/146844/732819</link>
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			<pubDate>Mon, 18 Dec 2006 00:10:31 GMT</pubDate>
			<dc:creator>Thoth</dc:creator>
			<description><![CDATA[<p>I&#x27;m not sure what you mean Ravern?  Please explain</p>]]></description>
			<category>Thoth</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/146844/732546</link>
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			<pubDate>Sun, 17 Dec 2006 13:13:06 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>210000000000<br /><br />005210000000<br /><br />421526310000<br /><br />842684268421<br /><br />-------------<br /><br />001111000101<br /><br />512+256+128+064+004+001=965</p>]]></description>
			<category>Raven62</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/146844/731923</link>
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			<pubDate>Sat, 16 Dec 2006 09:03:04 GMT</pubDate>
			<dc:creator>JADELottery</dc:creator>
			<description><![CDATA[<p>ok.</p>]]></description>
			<category>JADELottery</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/146844/731900</link>
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			<pubDate>Sat, 16 Dec 2006 05:40:57 GMT</pubDate>
			<dc:creator>Thoth</dc:creator>
			<description><![CDATA[<p>It&#x27;s base 2 JADE,<br /><br />965 is the number of the Pick 3 Permutation, the  111000010001000  is the binary outcome sequence code, of which there are 2^15 possibilities.<br /><br />111000010001000 = converts to base ten as 28,808<br /><br />1*2^14<br /><br />1*2^13<br /><br />1*2^12<br /><br />0*2^11<br /><br />0*2^10<br /><br />0*2^9<br /><br />0*2^8<br /><br />1*2^7<br /><br />0*2^6<br /><br />0*2^5<br /><br />0*2^4<br /><br />1*2^3<br /><br />0*2^2<br /><br />0*2^1<br /><br />+0*2^0<br /><br />28,808</p>]]></description>
			<category>Thoth</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/146844/731673</link>
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			<pubDate>Fri, 15 Dec 2006 22:33:05 GMT</pubDate>
			<dc:creator>JADELottery</dc:creator>
			<description><![CDATA[<p>In this case, Thoth&#x27;s binary sequence of bits do not equate to the decimal value of the bit sequence.<br /><br />965   111000010001000 Thoth&#x27;s bit sequence<br /><br />965 &#xb9; 111000010001000 binary, base-2  or<br /><br />965 &#xb9; 1111000101 binary, base-2 in this example.</p>]]></description>
			<category>JADELottery</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/146844/731638</link>
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			<pubDate>Fri, 15 Dec 2006 21:23:31 GMT</pubDate>
			<dc:creator>JADELottery</dc:creator>
			<description><![CDATA[<p>1 - bit - one bit<br /><br />1111 - nibble - four bits<br /><br />11111111 - byte - eight bits<br /><br />1111111111111111 - word - sixteen bits<br /><br />it&#x27;s computer jargon.</p>]]></description>
			<category>JADELottery</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/146844/731502</link>
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			<pubDate>Fri, 15 Dec 2006 16:41:42 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>What Base is used for your Binary?<br /><br />965 in Binary Base 2=1111000101</p>]]></description>
			<category>Raven62</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/146844/731489</link>
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			<pubDate>Fri, 15 Dec 2006 16:15:13 GMT</pubDate>
			<dc:creator>Thoth</dc:creator>
			<description><![CDATA[<p>Hmm... not sure what you mean.  Are you looking for a 16th bit, rather than 15?  If so, I&#x27;ll use a state with 16 spans.</p>]]></description>
			<category>Thoth</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/146844/731404</link>
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			<pubDate>Fri, 15 Dec 2006 13:54:48 GMT</pubDate>
			<dc:creator>JADELottery</dc:creator>
			<description><![CDATA[<p>Great idea, however, you&#x27;re one bit short of a Word.<br /><br />Have you done it for a full Word</p>]]></description>
			<category>JADELottery</category>
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			<title>Binary Pick 3 Anyone?</title>
			<link>https://www.lotterypost.com/thread/146844</link>
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			<pubDate>Fri, 15 Dec 2006 05:43:43 GMT</pubDate>
			<dc:creator>Thoth</dc:creator>
			<description><![CDATA[<p>As disclosed in my recent posts concerning the Matrix Completion Cycle and its Decomposition Rate by Half-Life, it&#x27;s an established fact that very close to 500 different Pick 3 straights (+ or - 20 either way) will be drawn during any span of 693 consecutive games.  Because of this fact, each individual straight Pick 3 number can be given a 50% probability to be drawn within any given span of 693 consecutive games. Esentially, this 50/50 chance allows each combo&#x27;s performance within a span to be... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/146844">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Thoth</category>
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