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		<title>Question for excel experts</title>
		<link>https://www.lotterypost.com/thread/150505</link>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/150505/769302</link>
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			<pubDate>Fri, 09 Feb 2007 03:45:38 GMT</pubDate>
			<dc:creator>retxx</dc:creator>
			<description><![CDATA[<p>thanks Mickie,looking forward to good results I hope.</p>]]></description>
			<category>retxx</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/150505/769096</link>
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			<pubDate>Thu, 08 Feb 2007 22:49:51 GMT</pubDate>
			<dc:creator>Mickie</dc:creator>
			<description><![CDATA[<p>SirMetro<br /><br />Wow!! Thank you!<br /><br />There is a small problem though, I did fix one part(I took and made them individual in cells)<br /><br />see what the last number is? A 3 digit.<br /><br />0027<br /><br />5196196196156152152452422422422722702707707<br /><br />Here is the original:<br /><br />00275196 - 1961 - 9615 - 6152 - 1524 - 5242 - 2422 - 4227 - 2270 - 2707 - 707<br /><br />The purple is the number I want to Sq root.<br /><br />Retxx as soon as I finish I will send you a copy.<br /><br />Mickie</p>]]></description>
			<category>Mickie</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/150505/768681</link>
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			<pubDate>Thu, 08 Feb 2007 13:51:20 GMT</pubDate>
			<dc:creator>SirMetro</dc:creator>
			<description><![CDATA[<p>Here is the Macro that will function IF your primary number is in Cell A1<br /><br />=CONCATENATE(LEFT(TEXT((SQRT(A1)*1000000000000), ############### ),4),  -  ,MID(TEXT((SQRT(A1)*1000000000000), ############### ),2,4),  -  ,MID(TEXT((SQRT(A1)*1000000000000), ############### ),3,4),  -  ,MID(TEXT((SQRT(A1)*1000000000000), ############### ),4,4),  -  ,MID(TEXT((SQRT(A1)*1000000000000), ############### ),5,4),  -  ,MID(TEXT((SQRT(A1)*1000000000000), ############### ),6,4),  -  ,MID(TEXT((SQRT(A1)*10000000... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/150505/768681">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>SirMetro</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/150505/768514</link>
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			<pubDate>Thu, 08 Feb 2007 04:05:32 GMT</pubDate>
			<dc:creator>retxx</dc:creator>
			<description><![CDATA[<p>hey mickie i am not very good at macros so could you or someone set up the macro in a spreadsheet so I can download it and see ifit works.Thanks</p>]]></description>
			<category>retxx</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/150505/767621</link>
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			<pubDate>Wed, 07 Feb 2007 00:30:02 GMT</pubDate>
			<dc:creator>Mickie</dc:creator>
			<description><![CDATA[<p>Thank you!<br /><br />You got my mind a flowing. Here is what happened and what I ended up with. Hope others enjoy on their endeavors of the sqrt and PI they are working on.<br /><br />Original #<br /><br />6082What it gave me<br /><br />779877798.71784333817798798.98.78.71.7177178178478438433433333383381<br /><br />What I wanted77987987987187177178178478438433433333383381<br /><br />7798717843338177987987987187177178178478438433433333383381<br /><br />Left7798<br /><br />Right7178433381<br /><br />Concentrate77987178433381<br /><br />NEW=CONCATENA... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/150505/767621">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Mickie</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/150505/767558</link>
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			<pubDate>Tue, 06 Feb 2007 22:55:26 GMT</pubDate>
			<dc:creator>phileight</dc:creator>
			<description><![CDATA[<p>Mickie<br /><br />let me assume your # is in a1    you want your result to be in c1  and you want the 4 # starting at position 5<br /><br />in c1 type        =mid(a1,5,4)                 cell a1 start position 5  4 #<br /><br />enjoy<br /><br />p8</p>]]></description>
			<category>phileight</category>
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			<title>Question for excel experts</title>
			<link>https://www.lotterypost.com/thread/150505</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/150505</guid>
			<pubDate>Tue, 06 Feb 2007 21:10:41 GMT</pubDate>
			<dc:creator>Mickie</dc:creator>
			<description><![CDATA[<p>Every one is doing, Square roots   Pi&#x27;s.<br /><br />My number is 6082 and I did a square root which equals 7798.7178433381<br /><br />Now I want to make these new numbers:<br /><br />7798 - 7987 - 9871 - 8717 - 7178 - 1784 - 7843 - 8433 - 4333 - 3381<br /><br />What I did was to take the first 4# then the next 4#, etc<br /><br />What formulas would I use to extract these.<br /><br />Thank you<br /><br />Mickie</p>]]></description>
			<category>Mickie</category>
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