5th Degree Polynomial Wave Projection

Reply #18

JADELottery — Sun, 05 Aug 2007 10:13:58 GMT

jarasan,

I'd like to redirect on your earlier reply.

Quote: P.S. Just for grins I wonder if differentiating the equations and plotting against the original may give any valuable data from the intersects? Or possibly shifting the phase by introducing a sine, cosine, or cotangent function into the lower degrees of the polynomials. I say this because the plot shown looks like 2.5 cycles of a dinged decay. Just a thought.

I have made another post related to this one topic, link: 1 to 11... [ More ]

Reply #17

JADELottery — Wed, 01 Aug 2007 18:14:20 GMT

Fibonacci,

Yes, you are right.

Same goes for myself not posting more examples.

However, I'm posting this information for those who know how to use the information.

Also, when JADE LSG 2.0 is relased, all the topics I've posted will be a function in some form within the JADE LSG program.

Reply #16

Fibonacci — Tue, 31 Jul 2007 11:21:09 GMT

Great stuff but after two pages we are yet to see anyone apply this to any set of numbers.

Reply #15

JADELottery — Tue, 31 Jul 2007 09:29:40 GMT

hypersoniq,

I have a basic process for finding the Wave Matrix for the Powerball Number 1 to 42. You'll have to goto the following link because the LP editor can't handle the load of information and the formatting.

Powerball Number Linear Regression, BMA and Wave Matrix

Reply #14

jarasan — Sun, 29 Jul 2007 03:28:08 GMT

Thanks.

Reply #13

JADELottery — Sun, 29 Jul 2007 01:32:28 GMT

Posted earlier:

You can go to this link to see the process for finding the equations.

Process for Finding Variable Coefficients and Polynomial Equations

Reply #12

jarasan — Sat, 28 Jul 2007 23:51:57 GMT

I am curious, how the coefficients are chosen? Thanks.

P.S. Just for grins I wonder if differentiating the equations and plotting against the original may give any valuable data from the intersects? Or possibly shifting the phase by introducing a sine, cosine, or cotangent function into the lower degrees of the polynomials. I say this because the plot shown looks like 2.5 cycles of a dinged decay. Just a thought.

Reply #11

JADELottery — Sat, 28 Jul 2007 19:37:36 GMT

Have you tried to apply the Bidirectional Mean Averaging to find The Wave Matrix for the Powerball number?

There are a few techniques to using the BMA to arrive at a particular Wave Matrix.

One is with the RMS adjustment and one is without the RMS adjustment.

Also, play around with the Degree of Weighting Data value in the BMA.

I'll get back to this later tonight.

We are having my son's birthday party today and I'll be busy most of the day.

Reply #10

hypersoniq — Sat, 28 Jul 2007 01:38:08 GMT

kind of makes sense if your data plots with a nice sine wave...

red balls in powerball have a range of 1 to 42 every draw, a graph of that is a jagged sawtooth that appears to have no rhyme or reason....

you can limit sorted order whiteballs to observed range and cut the choices, but the red ones are as noisy as plotting DRAW ORDER data.

all we have to go on is past history, which is supposedly random (looks random to me, except how they always manage to avoid drawing the numbers on my

Reply #9

JADELottery — Tue, 24 Jul 2007 21:41:31 GMT

You can go to this link to see the process for finding the equations.

Process for Finding Variable Coefficients and Polynomial Equations

The LP editor can't handle the formating.

Enjoy.

Reply #8

JADELottery — Mon, 23 Jul 2007 19:49:55 GMT

Typo correction

Reply #7

JADELottery — Mon, 23 Jul 2007 19:00:44 GMT

Mean Difference and Standard Deviation Quantum Projection

reference - Random Number Transforms - Normal Distribution

After calculating the Mean Difference and Standard Deviation, the Standard Deviation can be used to induce a Quantum Projection of the Wave using the Random Number Transforms - Normal Distribution. The projection can be a single point, a set of points or a range above and below the mean difference.

The Normal Distribution line shows the level of probability above and

Reply #6

JADELottery — Mon, 23 Jul 2007 17:30:52 GMT

Thank you for your useless comments.

Yes, it is meaningless dribble, specially made for you.

Please feel free to add more pseudo psycho babble.

Reply #5

hennybogan — Mon, 23 Jul 2007 05:21:19 GMT

So, are you going to plug some drawing numbers into these equations and see if they produce a hit in any state, or is this just meaningless dribble

Reply #4

JADELottery — Mon, 23 Jul 2007 05:06:30 GMT

The last equation should look like this.

Reply #3

JADELottery — Mon, 23 Jul 2007 03:55:31 GMT

Mean Difference and Standard Deviation

1 - Set of Wave Values

{W0, W1, W2, ... Wn-2, Wn-1, Wn}

2 - Approximate Projection Set

First difference calculation.

S0 = {y0, y1, y2, y3, y4, y5} = {W0, W1, W2, W3, W4, W5}

Plug values into following equations.

a0 = 720y0 - 1800y1 + 2400y2 - 1800y3 + 720y4 - 120y5

a1 = -1044y0 + 3510y1 - 5080y2 + 3960y3 - 1620y4 + 274y5

a2 = 580y0 - 2305y1 + 3720y2 - 3070y3 + 1300y4 - 225y5

a3 = -155y0 + 685y1

Reply #2

JADELottery — Mon, 23 Jul 2007 01:29:25 GMT

Deviation from The Wave for 5th Degree Wave Projection

Using the basic 3 steps, we can apply it to a long history of a wave to find a mean difference and standard deviation of the mean difference for the approximate projection. The standard deviation is used to Quantumly Project a point or a range for the final y6 value. Within a set of y wave values a subset of 6 points can be created starting at the beginning and then the 6 point move along the wave by 1 to 1 less than the final y values. A... [ More ]

Reply #1

hennybogan — Sun, 22 Jul 2007 22:52:16 GMT

Fractals is the final ultimate frontier. When one of you youngsters discovers how ro apply it to games of chance, ALL and I do mean ALL, casinos and state lotteries will be no more.

5th Degree Polynomial Wave Projection

JADELottery — Sun, 22 Jul 2007 22:33:44 GMT

5th Degree Polynomial Wave Projection

Reference - Bidirectional Mean Averaging and The Wave Matrix

1 - 6 Point Set of y Wave Values

{y0, y1, y2, y3, y4, y5}

2 - Variable Coefficient Equations

a0 = 720y0 - 1800y1 + 2400y2 - 1800y3 + 720y4 - 120y5

a1 = -1044y0 + 3510y1 - 5080y2 + 3960y3 - 1620y4 + 274y5

a2 = 580y0 - 2305y1 + 3720y2 - 3070y3 + 1300y4 - 225y5

a3 = -155y0 + 685y1 - 1210y2 + 1070y3 - 475y4 + 85y5

a4 = 20y0 - 95y1 + 180y2 - 170... [ More ]