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		<title>looking for a math formula</title>
		<link>https://www.lotterypost.com/thread/164437</link>
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		<description>Lottery Post Forum Topic: looking for a math formula</description>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/164437/912834</link>
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			<pubDate>Mon, 15 Oct 2007 20:40:40 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>I stand corrected, when you use the scientific version of the calculator that comes in Windows to calculate 70!/(50! * 20!) the answer is not in scientific notation 1.618846036626579D+17 but in whole numbers 161884603662657876.</p>]]></description>
			<category>RJOh</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/164437/912461</link>
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			<pubDate>Mon, 15 Oct 2007 02:41:14 GMT</pubDate>
			<dc:creator>regy</dc:creator>
			<description><![CDATA[<p>All the info i was looking for is there !<br /><br />Thanks for the link</p>]]></description>
			<category>regy</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/164437/912118</link>
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			<pubDate>Sun, 14 Oct 2007 13:38:36 GMT</pubDate>
			<dc:creator>johnph77</dc:creator>
			<description><![CDATA[<p>http://www.johnph77.com/math/kenocomp.html<br /><br />No ads, nothing to sell, for informational purposes only.<br /><br />gl<br /><br />j</p>]]></description>
			<category>johnph77</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/164437/912020</link>
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			<pubDate>Sun, 14 Oct 2007 04:31:53 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>nice little app, but it seems to not like numbers this big.<br /><br />closest you can get are 70C18 and 80C16</p>]]></description>
			<category>time*treat</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/164437/911947</link>
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			<pubDate>Sun, 14 Oct 2007 01:56:49 GMT</pubDate>
			<dc:creator>KY Floyd</dc:creator>
			<description><![CDATA[<p>Even easier:<br /><br />http://www.wiley.com/college/mat/gilbert139343/java/java05_applet.html</p>]]></description>
			<category>KY Floyd</category>
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		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/164437/911940</link>
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			<pubDate>Sun, 14 Oct 2007 01:43:43 GMT</pubDate>
			<dc:creator>regy</dc:creator>
			<description><![CDATA[<p>Wow ! Thank for the fast response guy&#x27;s</p>]]></description>
			<category>regy</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/164437/911927</link>
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			<pubDate>Sun, 14 Oct 2007 01:25:34 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>C(20,70) = 1.618846036626579D+17  It&#x27;s approximately 161,884,603,662,658,000.  You use the same formula that you use to calculate the number of smaller combinations within a pool of numbers but you will get the scientific notation when using your computer if the program can&#x27;t handle more than 16 digits.<br /><br />You might get more accuracy if you used a program designed to calculate keno odds or a scientific calculator.</p>]]></description>
			<category>RJOh</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/164437/911925</link>
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			<pubDate>Sun, 14 Oct 2007 01:21:02 GMT</pubDate>
			<dc:creator>time*treat</dc:creator>
			<description><![CDATA[<p>To calculate the number of combinations of n elements taken r at a time.<br /><br />n C r = n! / [(n-r)! * r!]<br /><br />70 C 20 = 70! / [(70-20)! * 20!]<br /><br />= 70! / [50! * 20!]<br /><br />= 1.6188 e 17</p>]]></description>
			<category>time*treat</category>
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		<item>
			<title>looking for a math formula</title>
			<link>https://www.lotterypost.com/thread/164437</link>
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			<pubDate>Sun, 14 Oct 2007 00:40:28 GMT</pubDate>
			<dc:creator>regy</dc:creator>
			<description><![CDATA[<p>Do someone know the formula to calculate how many X combination in Y !<br /><br />For example lets say i wanna know how many 20 numbers combination bettween 1 and 70</p>]]></description>
			<category>regy</category>
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