Past 10 drawings having next drawings 5-6 numbers?(6/49)

Reply #12

RJOh — Fri, 16 Nov 2007 21:40:59 GMT

The winning numbers were 23 29 30 31 32 so the experiment wasn't successful. The winning numbers did everything I try to avoid with my picks. Three of the numbers had hit the previous drawing, their total range was less than 15, all the numbers were in the top half of the number pool and etc. While I played all the winning numbers 2-4 times in the 21 lines only twice were two of them in the same line.

Reply #11

Hans — Thu, 15 Nov 2007 23:54:23 GMT

Playing too many numbers and try win back a few bucks is not good enough.But only when 33 numbers could steadily 5-6 winning numbers,we have some chance to reduce 33 numbers to 16 numbers and only lose one winning number.And you can win to play like 60 dollars if you are more sure of your 16 numbers have 4 winning numbers.

The hard part is hwo to reduce 33 numbers to 16 numbers and only lose one winning number.

Perhaps some filter like zone gap would help

Hans

Reply #10

RJOh — Thu, 15 Nov 2007 23:14:59 GMT

As an experiment, I picked 21 lines for tonight's Ohio Rolling Cash5 (5/39) as I suggested:

05 20 24 34 37

16 22 23 28 38

11 14 17 26 33

03 18 27 32 35

02 19 30 31 36

02 16 24 27 33

07 09 26 31 37

06 20 22 35 36

09 14 18 23 34

01 03 17 28 29

10 14 22 27 37

05 11 28 30 35

15 18 29 31 33

16 21 26 29 36

04 07 17 24 38

02 11 15 20 32

03 07 12 30 34

04 20 26 27 30

06 16 18 19 37

05 19 32 33 38

17 21 22 31 34

Thirty-five of the thirty-nine numbers came up... [ More ]

Reply #9

RJOh — Thu, 15 Nov 2007 10:26:26 GMT

You might skip the previous drawing and include the next 10 instead for example. (Didn't work with the sample in my first post, went from 14% to 7%)

Or you might include more drawings and use the most or less popular 30-33 numbers in the group.

What ever you do, it won't be near 100% and if you have all six winning numbers even 50% of the time in a group of 33 your odds of having three of those numbers in one combination are 1:20. You have to pick a strategy and be prepared to lose some... [ More ]

Reply #8

Hans — Thu, 15 Nov 2007 08:31:35 GMT

what other way for example

Reply #7

RJOh — Thu, 15 Nov 2007 00:50:15 GMT

If as you say 33 numbers picked using the previous 10 drawings only have all 6 winning numbers 10% of the time then 10% is the best you can ever do picking 33 numbers that way. You can only get all 6 winning numbers out of any group of numbers when all six winning numbers are in that group. If you want to do better than 10% with a group of 33 numbers then you'll have to pick 33 numbers some other way.

Reply #6

Hans — Wed, 14 Nov 2007 23:59:43 GMT

Looks like the chance of 6 hit from past 10 drawings is only 10%.

Since past 10 drawings averagely have 33 numbers,that means this strategy can make get all 6 winning numbers in 33 numbers with success ratio of 10%.

Any better strategy to beat 10%,to catch all 6 winning numbers in 33 numbers?

Hans

Reply #5

RJOh — Tue, 13 Nov 2007 05:28:43 GMT

What's the percentage of Past 10 drawings having next drawings 5-6 numbers?

Sounded like a statistical question that couldn't be answered by I agree or disagree , don't you think?. I included charts for both 5 and 6 winning numbers for the last 100 drawings because both were part of the question and 100 drawings make the percentages easy to figure.

Reply #4

psykomo — Tue, 13 Nov 2007 00:55:27 GMT

PLEASE........agree/disagree.............don't,,,,<<<throw-UP<<<<STAT's......??

WHATCHA.........

tonking BOUT on this one in SIMPLE????????????World Laungauage

?????????????????????????????????????????????????????????????

note:

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Reply #3

psykomo — Tue, 13 Nov 2007 00:45:44 GMT

YOUR last........10 drawing's like to STAB your PORK in the >>>>>BACK!!!!!!

lol

psykomo

Reply #2

psykomo — Mon, 12 Nov 2007 23:47:56 GMT

Hans:

YOU should expect to HIT on @ LEAST.....................................(1)

but and all know PSYKOMO is (krazy)......................................(0)

LOL

Reply #1

RJOh — Mon, 12 Nov 2007 23:45:30 GMT

In the Ohio Classic Lotto (6/49) during the last 100 drawings the counts of previous drawings that had all six winning numbers were as follows:

0. 0 10. 7 20. 2 30. 1 40. 0 50. 0

1. 0 11. 4 21. 1 31. 0 41. 0 51. 0

2. 0 12. 4 22. 3 32. 2 42. 0 52. 0

3. 0 13. 9 23. 4 33. 0 43. 0 53. 1

4. 0 14. 8 24. 2 34. 0 44. 1 54. 0

5. 0 15. 5 25. 1 35. 1 45. 0

Past 10 drawings having next drawings 5-6 numbers?(6/49)

Hans — Mon, 12 Nov 2007 22:41:55 GMT

Has anyone done any research on this subject :

What's the percentage of Past 10 drawings having next drawings 5-6 numbers?

Thanks