Pick 5 Filter Program

Reply #6

RJOh — Mon, 24 Dec 2007 09:39:34 GMT

You are missing the boat if you think covering 3,876 of the 575,757 possible combinations would guaranteed you a win every time. You would only win if the winning combination had a number 01 and four even or four odd numbers depending on which ones you covered.

Ohio Rolling Cash5 is a 5/39 game that has had 1037 drawings so far. Only 131 of those drawings had a combination with the number one in it. Only in eleven of those combinations were the other four numbers all even and in seven the o... [ More ]

Reply #5

time*treat — Mon, 24 Dec 2007 08:55:03 GMT

3,876 is the number of combinations removed from the 575,757, holding one key number steady and dropping all-odds or all-evens, in the other four. With these lotto style games you're going to need to be either lucky with your number selection, or good at math.

Reply #4

Tinker — Mon, 24 Dec 2007 08:43:56 GMT

This looks really good or maybe I'm missing the boat.

Remove all even/odd numbers would remove 19 numbers = 4/19 = 3,876 possible combinations

So if I played one number, removing all even/odd numbers, that leaves

3,876 possible combinations. Therefore it looks like I should win the

jackpot about every time playing 3,876 possible combinations in a 5/39 game.

I would invest that amount to win $100,000.

I think I must have missed the boat somewhere.

Reply #3

RJOh — Mon, 24 Dec 2007 07:05:40 GMT

1-X-X-X-X = 4/38(39-1) = 73,815 possible combinations

Remove all even/odd numbers would remove 19 numbers = 4/19 = 3,876 possible combinations

Remove 1 odd + 4 even would remove 5 numbers = 4/33 = 40,920 possible combinations

Removing other groups and figuring the possible combinations requires a little more thought.

Reply #2

Tinker — Mon, 24 Dec 2007 05:51:43 GMT

Let's say we took this for example.

1-X-X-X-X = 4/38(39-1) = 73,815 possible combinations.

Is there any way to filter it down. Filter out all odd and even.

Filter out 4 odd, 1 even. 4 even, 1 odd. Filter out consecutive 3 and 4 numbers.

Thanks.

Reply #1

RJOh — Mon, 24 Dec 2007 05:24:32 GMT

An odds calculator may be all you need.

1-2-3-4-5 = 5/5 = 1 possible combination

1-2-3-4-X = 1/35(39-4) = 35 possible combinations

1-2-3-X-X = 2/36(39-3) = 630 possible combinations

1-2-X-X-X = 3/37(39-2) = 7,770 possible combinations

1-X-X-X-X = 4/38(39-1) = 73,815 possible combinations

X-X-X-X-X = 5/39(39-0) = 575,757 possible combinations

All even numbers = 5/19 = 11,628 possible combinations

All odd numbers = 5/20 = 15,504 possible combinations

Pick 5 Filter Program

Tinker — Mon, 24 Dec 2007 04:48:37 GMT

I wish I had a program for the pick 5 like Paurth's freewheelpick4. In a 5/39 game, I would like to see how many combinations there are for 1 or 2 numbers.

Example:

There are 575,757 combinations in a 5/39 game.

1-2-3-4-5 = 1 combination

1-2-3-4-x = 35 combinations

1-2-3-x-x = ?

1-2-x-x-x = ?

1-x-x-x-x = ?

So if I played one number, there won't be 575,757 combinations.

Also a way to filter out consecutive numbers. Also all odd, even.

So in probability, some combinations are not l... [ More ]