"The old man zero trick" possible formula idea

Reply #12

Amazing Grace — Wed, 30 Apr 2008 12:52:27 GMT

The zero trick should include all these single and pair numbers.

3,6,9,33,66,99,36,39,69,

Reply #11

jackpotismine — Thu, 17 Apr 2008 15:21:20 GMT

Thank you, Thank you. Go get 'em

Reply #10

Maggie-Nolia — Thu, 17 Apr 2008 15:15:04 GMT

Well, it didn't take long for ya'll to blow my mind, but you surely did peak my interest!!! I think this is definitely food for thought for those of you who's thinker is smarter than mine. I'll check back in and see where this might go and might even take a shot at it myself. Thanks for broaching the subject.

P.S. I decided I'd better consult my dictionary to make sure that I had used the appropriate word (age has blurred some of my memory). broach: to start a discussion of; bring up; introdu... [ More ]

Reply #9

jackpotismine — Thu, 17 Apr 2008 15:13:19 GMT

I know, I know..

Reply #8

Raven62 — Thu, 17 Apr 2008 11:33:23 GMT

Working with the Zero Trick is only One Tenth of the Equation, after all their are Nine other Tricks that need to be Identified and Documented.

The Old Man's One Trick

The Old Man's Two Trick

The Old Man's Three Trick

The Old Man's Four Trick

The Old Man's Five Trick

The Old Man's Six Trick

The Old Man's Seven Trick

The Old Man's Eight Trick

The Old Man's Nine Trick

Reply #7

jackpotismine — Thu, 17 Apr 2008 03:22:00 GMT

Thank you all for giving me some ideas. What I'm looking for is a formula that Will give you the numbers. Not just numbers. I have to back test the pumatations see if I find anything. Maybe it could be multiplied, divided or subtracted. The key is to find a formula that will actually give you hit 90% of the time. I know, I know I'm looking for the holy grail. But maybe you guys can back test the idea in your own states. I know the lottery is random (kind of) but I think this is worth giving so t... [ More ]

Reply #6

time*treat — Thu, 17 Apr 2008 02:55:37 GMT

This will give you (up to) 6 additional numbers per draw to play for a maximum of 10 days. That is six based on the starting number, plus six more based on the following draw if none of the first six fall, etc... you could have a running total of as many as 60 numbers to play per drawing.

Reply #5

emilyg — Wed, 16 Apr 2008 17:59:22 GMT

Thanks.

Reply #4

Raven62 — Wed, 16 Apr 2008 17:45:25 GMT

(Quote) For example, lets say: 123 is drawn and we use 036 or 0.36 somehow to calculate numbers that will be drawn within 10 days or less of the calculation.(Unquote)

036 = 3 Unmatched Digits

Permutations of 036 = 036 063 306 360 603 630

Reply #3

emilyg — Wed, 16 Apr 2008 17:36:02 GMT

Raven: last number

Reply #2

Raven62 — Wed, 16 Apr 2008 17:33:43 GMT

123 + 036 = 159

123 + 063 = 186

123 + 306 = 429

123 + 360 = 483

123 + 603 = 726

123 + 630 = 753

Reply #1

emilyg — Wed, 16 Apr 2008 17:23:13 GMT

bump

"The old man zero trick" possible formula idea

jackpotismine — Wed, 16 Apr 2008 12:58:32 GMT

Okay, I'm the first to admit it. I'm as dumb as hell so I'm looking to see if there's a mathematician that can maybe work on this idea. When zero is drawn a 3 or 6 or both like to follow about 90% of the time, that the zero theory more or less. Maybe it has to do with the fact that zero is the starting point of the numbers. Anyway, maybe using 036 or 0.36 or something like that to calculate future pick 3 draws. For example, less say 123 is drawn and we use 036 or 0.36 somehow to calculate number... [ More ]