Complete Systems Failure (predictions)

Reply #25

BobP — Wed, 20 Aug 2008 18:11:20 GMT

The most famous one is The Only Way to Win at LOTTO by Robert Serotic

ISBN 0-941271-06-4

UPC 0 13567 01495 3

This one is usually available through amazon, ebay and the Lotto Masta guy from down under.

Then there is a 3 book set . . .

Lotto: How to Play and Win

1. Introduction to Systems and Strategies

2. For Advanced Players

3. For Experts

There is, LOTTO Pick-5 How to Play and Win (no pairs and triples ;-)

There is a book called LOTTO PLANNER outdated b... [ More ]

Reply #24

Alcymart — Wed, 20 Aug 2008 07:21:24 GMT

Yep, thats me. Thanks for detailed explanation. You would know better than me as I don't have his books anymore and miss them. Whats the title of the most thorough Serotic book he wrote so I can look it up new or used online somewhere

Reply #23

BobP — Wed, 20 Aug 2008 06:35:46 GMT

Is that you Bernard?

In the Giant Systems section Robert Serotic does make systems that combine pairs with a rotation of numbers from a secondary group taking the remaining three places in the Pick-5 combinations.

Because he does not form the numbers from the secondary group into three number sets as I do, but instead makes a 3if3 wheel out of them to play against each pair in turn, his wheels are much more expensive to play. His 13 number wheel System 191 needs 119 combinations where a... [ More ]

Reply #22

Alcymart — Wed, 20 Aug 2008 05:22:40 GMT

Hi BobP, That sounds like a Serotic wheel to me...pairs, triplets, and their not cheap to play.

Reply #21

Stack47 — Tue, 19 Aug 2008 20:34:47 GMT

A coworker used a variation of this strategy playing one set of 3s with three sets of 2s and only a $3 bet in 5/37 pick-5 game. He played pet numbers and explained it after showing me his ticket that matched 2 numbers from the set of 3s with one of the sets of 2s for a 4 out of 5 win with two 2 out of 5 wins. I was skeptical about playing the same set of pet numbers in every drawing until he matched all 5 numbers and won $102,000 a few months later.

For a $10 bet we can combine two sets of 3s... [ More ]

Reply #20

RJOh — Tue, 19 Aug 2008 18:49:36 GMT

Every one who pick their own combinations have a theory about the best way to do it. Trying to understand the logic of them all is just confusing.

Reply #19

Editgap — Tue, 19 Aug 2008 11:29:29 GMT

I don't understand much about the paradox but I build on my best pick. If I find a pair on numbers, I will build the rest of my combinations from them.

Reply #18

BobP — Tue, 19 Aug 2008 06:42:25 GMT

Ok, Pick-5 we want to play 15 numbers. 6 Groups 3 of 3 and 3 of 2, play them against each other. (Remember these are pointers, use your best picks your research indicates will hit together to replace my numbers.)

01-02-03 04-05

06-07-08 09-10

11-12-13 14-15

Makes . . .

01-02-03-04-05

01-02-03-09-10

01-02-03-14-15

06-07-08-04-05

06-07-08-09-10

06-07-08-14-15

11-12-13-04-05

11-12-13-09-10

11-12-13-14-15

You can have more 3's or more 2's or the same n... [ More ]

Reply #17

BobP — Tue, 19 Aug 2008 06:32:35 GMT

Oh man RJOh I wish it worked that way.

Let's say you made a template, (cut a hole in a piece of paper the size of a column of 15 Pick-3 draws) and flipped to any page of your game's draw history and slapped it down. Half of the time, 50/50 you would find two of the same number boxed among the 15.

If on the other hand you began sliding the template up the page adding a draw and losing a draw at a time, it simple doesn't work. Same as if you found no one of the 23 people in the room wi... [ More ]

Reply #16

RJOh — Tue, 19 Aug 2008 06:23:27 GMT

.....the odds of my combination matching all 5 of the early combinations is as good as matching the 5 white balls that will be drawn.

I use to think that too until I added a feature to my RNG that not only rejects combinations that have matched 4-6 numbers of previous winning combinations but beeps and high light such combinations. When you limit your picks to the most popular parameters of previous winning combinations that is more likely to happen.

Reply #15

Editgap — Tue, 19 Aug 2008 05:06:37 GMT

That is a good point but I don't bother eliminating all those combinations because the odds of my combination matching all 5 of the early combinations is as good as matching the 5 white balls that will be drawn.

If a had a program that can eliminate the 5 and 4 set, I would definitely use it.

Reply #14

bennybaku — Mon, 18 Aug 2008 19:12:19 GMT

Bob, You are very helpful, and by the way I did download your book, it is very helpful. However I have a question as to your post, I am fairly new to the lottery system so forgive me if this is a dumb question, Could you clarify sets of numbers in 2's and 3's? And how would I play them off each other to make five number combo's?

Thanks so much

Reply #13

RJOh — Mon, 18 Aug 2008 19:08:50 GMT

The Birthday Paradox tells us the odds are 50/50 of a boxed match in any random set of 15 past drawn Pick-3 numbers you happen to look at.

I've only played the pick-3 game a few times but if the odds of getting a box hit are 50/50 when playing the previous 15 drawings then I may start playing it more.

Reply #12

BobP — Mon, 18 Aug 2008 18:23:28 GMT

The Birthday Paradox tells us the odds are 50/50 of a boxed match in any random set of 15 past drawn Pick-3 numbers you happen to look at. There is nothing about having to play all 220 boxed combinations nor does the payout affect the outcome, that's a side issue.

When a Pick-5/26 game has only 65,780 combinations there is a point where the paradox kicks in and there is a good chance of two combinations matching. The fact this did happen multiple times certainly suggests the paradox is in... [ More ]

Reply #11

RJOh — Mon, 18 Aug 2008 15:45:09 GMT

The Birthday Paradox works because there are only 365 possible outcomes. Lotteries with only a few possible out comes adjust their payouts such that you can't take advantage of the paradox. For example there are only 220 possible box hits in a pick-3 game including triples and doubles and playing them all will guarantee you a hit but the payout will only be 50% of what you spent.

Reply #10

time*treat — Mon, 18 Aug 2008 06:10:39 GMT

Ah, that would be the Complete Systems Success . It's still a work in progress.

Reply #9

BobP — Mon, 18 Aug 2008 04:33:46 GMT

For big Pick-5 games it is safe to eliminate past winning 5 number combinations from your plays and pretty safe to eliminate the 4-number sets of those 5 number wins, but you cannot discard the 2 and 3-number sets as those are drawn again and again.

The smaller the game the more you get repeats of previous sub-combinations.

The Florida Fantasy 5/26 repeated all 5-numbers many times, though not in the next draw. For the first couple of years players could win jackpots simply by playin... [ More ]

Reply #8

RJOh — Mon, 18 Aug 2008 02:25:51 GMT

You can't safely eliminate any number or combination but you can gamble based on what has happened in the past and that would be a good gamble. When ever you play the MegaMillions lottery, you're gambling.

Reply #7

Prov1x — Sun, 17 Aug 2008 23:40:19 GMT

Wouldnt it be safe to eliminate all numbers previously drawn - I know this is only a small fraction of possible outcomes but for people who play quick picks - get the quick picks off this site and make sure you arent getting something that has been drawn again. I did this last night and got lucky and had 4/5

Reply #6

RJOh — Sun, 17 Aug 2008 23:10:54 GMT

When you play a game like MegaMillions you need to stop paying the lottery big money for worthless prizes.

The problem is I never know that's what I've done that until after the drawing.

Reply #5

TigerAngel — Sun, 17 Aug 2008 22:44:07 GMT

Wow, that sounds outa sight Bob! Thanks for posting it. Just the other day I was vaguely thinking of 8-23. So it showed up. So I think I will try your idea and use my pairs with trip sets. Kuuuul. .

p.s. I didn't make it in time for your most gracious discount on your ebook but will pick it up soon anyway.

Reply #4

BobP — Sun, 17 Aug 2008 22:14:41 GMT

When you play a game like MegaMillions you need to stop paying the lottery big money for worthless prizes.

Make up unique sets of numbers in 2's and 3's (pairs and triples) no repeating numbers and play them off against each other to make 5 number combinations.

Not only is this method cheaper then wheeling, it has real world first prize potential. First prize is guaranteed when one correct pair and one correct triple combine.

Think about it.

BobP

Reply #3

RJOh — Sun, 17 Aug 2008 20:44:30 GMT

In a game like MegaMillions with 175,711,536 possible combinations, only 4,405,086 or 2.5% of those combinations are going to have a chance to win anything each drawing. That means there are 171,306,450 combinations that are losers every drawing. Wouldn't it be easier to try and pick some of those winning combinations than it would be to eliminate all of those losing combinations

Reply #2

time*treat — Sun, 17 Aug 2008 19:57:52 GMT

If I could come up with a method that would give me all of the combinations that were going to lose, I could work with that.

Reply #1

RJOh — Sun, 17 Aug 2008 18:57:22 GMT

With any prediction system you has to have realistic expectations. Most lotteries expect less than 4% of the tickets sold will have a combination that wins anything so if you're picking less than 20 combinations with your system you should expect all losers occasionally even when the system is working.

Check the prediction statistics for the top predictors, their hit percentages aren't that high.

Complete Systems Failure (predictions)

Editgap — Sun, 17 Aug 2008 18:31:43 GMT

Don't you hate complete systems failure while you are making your powerball/megamillions predictions?

My preditions system on powerball is not doing so well as of recent.

The only advantage to a total system failure is you find newer ways to improve your system.