Pathagorean Square Method

Reply #26

Shawn67 — Thu, 11 Dec 2008 17:52:44 GMT

Sorry, I've been a little busy the last 2 days. After trying this method on paper only since originally posting this, I have not hit once using this system. It appears to be pretty straightforward, but the fact that there are no 0's or doubles in this system, plus the high number of combo's you have to play with this is now a deal-breaker for me. Feel free to keep testing, and maybe someone can perfect this method, but I am officially abandoning this as a viable method of Pick-3 number selection... [ More ]

Reply #25

Timmer692002 — Wed, 10 Dec 2008 22:26:03 GMT

Markcornelius

Don't you mean 351 not 341?

I'd be interested in seeing that also, shawn67

Reply #24

markcornelius — Wed, 10 Dec 2008 05:07:30 GMT

hello shawn67 will this work for michigan midday evening ,today was 341 can do a samlpe.

Reply #23

Shawn67 — Sat, 06 Dec 2008 03:53:42 GMT

Some good information in some of those threads. Thanks for the heads up

Reply #22

LAVERNE MALONEY — Sat, 06 Dec 2008 03:17:09 GMT

Hello there Shawn67, I found a whole hosts of posts on the Pythagorean method. The link: Pythagorean Square triple theory - Lottery Post Forums

In the link below you will find many posts on the subject:

Pythagorean Search Engine

Reply #21

mcadoocharlotte — Sat, 06 Dec 2008 02:42:24 GMT

Great, Thank you so much!!!!!!!!!!!!!

mcadoocharlotte

Reply #20

Shawn67 — Sat, 06 Dec 2008 02:39:46 GMT

The chart doesn't change. It stays the same from day to day. The only thing that changes is where you pick numbers from on the chart.

Reply #19

mcadoocharlotte — Sat, 06 Dec 2008 02:35:38 GMT

Thank you for sharing this and all of your

hard work. Shawn I have another question

I'm confused on how to start the chart for the next day

Reply #18

Shawn67 — Sat, 06 Dec 2008 02:15:55 GMT

Correct, connect one 6 to the next 6 on the same line and play combos off of that line.

Reply #17

mcadoocharlotte — Sat, 06 Dec 2008 02:15:03 GMT

So each day of the month the beginning number will be different.

Since tomorrow will be the 6th wil the starting # be 6

Reply #16

Shawn67 — Sat, 06 Dec 2008 02:11:05 GMT

From what I've seen, I beleive it is universal. Of course, as previously stated, doubles and 0's are still a problem I can't figure out how to get around.

Reply #15

mcadoocharlotte — Sat, 06 Dec 2008 02:07:01 GMT

Shawn67 can this be used for nc?

Can the same grid be used or will it have to be

changed?

mcadoocharlotte

Reply #14

mdmegamillplyr — Sat, 06 Dec 2008 00:57:43 GMT

lol wow that was a large waste of time. ah well Ive already got my lines of numbers drawn from this so ... wish me luck.

Reply #13

Shawn67 — Sat, 06 Dec 2008 00:53:24 GMT

Okay, now I think I know where the confusion lies.........My fault for not mentioning this is in the beginning. Even though the original post says this will work for all games, I have only been finding this useful for Pick-3 and Pick-4 games. My bad.

Reply #12

mdmegamillplyr — Sat, 06 Dec 2008 00:49:28 GMT

Whats your take on this? How do you seperate single digit numbers from double digit ones? Any thoughts on which is the megaball? lol

Does it work

Reply #11

Shawn67 — Sat, 06 Dec 2008 00:45:28 GMT

This is exactly correct......if today is the 1st, you go off the 1's, off of the 2's for the 2nd and so on and so forth. Don't worry about the month and year. You are only concerned with the day of the month (reduced to it's lowest root form).

Reply #10

mdmegamillplyr — Fri, 05 Dec 2008 23:54:50 GMT

Should I include the 5's in my numbers

Reply #9

mdmegamillplyr — Fri, 05 Dec 2008 23:23:56 GMT

How would you find todays date? 12 5 08? I really want to know how to plug that date in that is what I am missing 1 + 2 = 3 5 08? 358? 3518? I still dont really get it exactly

Reply #8

SBIP$999 — Fri, 05 Dec 2008 23:14:39 GMT

Is this the box you are using?

3 6 9 3 6 9 3 6 9

4 7 1 4 7 1 4 7

2 5 8 2 5 8 2 5 8

3 6 9 3 6 9 3 6

1 4 7 1 4 7 1 4 7

The way I read this is that you highlight all numbers adjacent to the date, in this case it is the 5s on line 3. You also go up and down diagonally as noted below with yellow highlighting.

3 6 9 3 6 9 3 6 9

4 7 1 4 7 1 4 7

2 5 8 2 5 8 2 5 8

3 6 9 3 6 9 3 6

1 4 7 1 4 7 1 4 7

SC Midday today was 681, and that # is highlighte... [ More ]

Reply #7

mdmegamillplyr — Fri, 05 Dec 2008 22:18:45 GMT

I mean is it the numbers on the diagonals? the 12 5 08 or just the 5, the 0 the 5 what.. am I looking for

Reply #6

Shawn67 — Fri, 05 Dec 2008 22:05:11 GMT

Try it on the chart, you'll see what I'm saying.

Reply #5

mdmegamillplyr — Fri, 05 Dec 2008 22:02:21 GMT

I dont get it, it seems like the numbers near the 5 would always be the same, what makes it random? What is it Im not getting, its very frustrating

Reply #4

Shawn67 — Fri, 05 Dec 2008 22:00:59 GMT

The root of 5 is 5 all single digit roots are the same. 2-digit numbers are handled like this 13 (1+3=4), 23 (2+3=5) 29 (2+9+11....1+1=2). You add the numbers together until you reduce it to a single digit.

Reply #3

mdmegamillplyr — Fri, 05 Dec 2008 21:56:57 GMT

I found a site that reduces the day month and year like 2008 12 5 and reduces to the roots, not sure what the root of 5 is, not a mathematician here

Reply #2

Shawn67 — Fri, 05 Dec 2008 21:53:36 GMT

Let's say today is the 23rd. You would reduce 23 down to its root of 5 . Then, look on the chart and make an imaginary line from one 5 to the next 5 on the same line. After that you make your combos by making combos out of any numbers than run along, through, or beside that line.

Reply #1

mdmegamillplyr — Fri, 05 Dec 2008 21:28:56 GMT

Forgive my ignorance, but could you explain this method to me in greater detail

Pathagorean Square Method

Shawn67 — Fri, 05 Dec 2008 20:44:43 GMT

I ran across this method posted almost 3 years ago by a member who popped in and only made 2 posts before disappearing.

https://www.lotterypost.com/thread/119300

Now, what I have been doing is reducing the date down to it's root (the 23rd would be reduced to 5). In backtesting, this method is procing VERY good results with some exceptions: First, doubles are obviously a problem, and Second, what do we do about the digit 0? In backtesting I've been treating the 1 on the chart both as a 1 an... [ More ]