Can someone give me a formula?

Reply #7

LottoMining — Thu, 23 Jul 2009 04:32:04 GMT

If you had a database program such as MS Access, you could create a table named tblRnd1 with a single field named Num of data type number (though data type of text works too). Then populate your table with the five digits.

This query right below outputs the 625 records / combos (assuming you named the table as listed above and populated it):

SELECT tblRnd1.Num, tblRnd1_1.Num, tblRnd1_2.Num, tblRnd1_3.Num

FROM tblRnd1,

tblRnd1 AS tblRnd1_1,

tblRnd1 AS tblRnd1_2,

tblRnd1 AS tblRn... [ More ]

Reply #6

RJOh — Tue, 21 Jul 2009 23:49:24 GMT

You can down load a free program from LottoLogix called Maybelle QuickWheel that will calculate that it's 625 combinations and print them out for you.

Reply #5

KY Floyd — Tue, 21 Jul 2009 19:42:11 GMT

Perhaps you're thinking of factorials (n!), which are a number multiplied by each whole number that is less than that number and greater than zero. For 5 it's 5*4*3*2*1, which is 120. There are 120 permutations for 5 numbers if you use all 5 of them. In a permutation the order of the numbers matters. For combinations, OTOH, the order doesn't matter. 1,2,3,4,5 and 5,4,3,2,1 are different permutations, but represent irrelevant variations of the same combination. The formulas for permutations and c... [ More ]

Reply #4

Stack47 — Wed, 01 Jul 2009 13:43:18 GMT

I believe it's called factoring when any of 5 digits can appear in any of the four positions. To get the total number of combinations you multiple 5 (first position) times 5 (second) times 5 (third) times 5 ( fourth) equals 625. If you're using the digits 1-2-3-4-5 it would look like (1-2-3-4-5) with (1-2-3-4-5) with (1-2-3-4-5) with (1-2-3-4-5).

You'll probably need a program that generates all 625 combinations and allows you to apply filters.

Reply #3

johnph77 — Tue, 30 Jun 2009 15:35:22 GMT

I just did an Excel chart similar to this but for Pick 3. Pick 4 would be 10 times as large, of course. I presently have no plans to work on something like this, as 10,000 cells would have to be individually formatted. But:

There are 625 4-digit combinations that can be formed using 4 digits from the first 5-digit group. This includes doubles, triples and quads.

There are 2,500 4-digit combinations that can be formed using 3 digits from the first 5-digit group and 1 digit from the second 5... [ More ]

Reply #2

CARBOB — Tue, 30 Jun 2009 13:51:23 GMT

You need to go back to your original post, here. https://www.lotterypost.com/thread/196264

Then download the software. Then you will be able to do this. Just an example using any 5 digits.

0123, 0124, 0132, 0134, 0142, 0143, 0213, 0214, 0231, 0234, 0241, 0243, 0312, 0314, 0321, 0324, 0341, 0342, 0412, 0413, 0421, 0423, 0431, 0432, 1023, 1024, 1032, 1034, 1042, 1043, 1203, 1204, 1230, 1234, 1240, 1243, 1302, 1304, 1320, 1324, 1340, 1342, 1402, 1403, 1420, 1423, 1430, 1432, 2013, 2014, 2031,... [ More ]

Reply #1

Texas MadMan — Tue, 30 Jun 2009 13:50:46 GMT

ABCDE

=

ABCD

ABCE

ACDE

BCDE

Can someone give me a formula?

wellcrafted — Tue, 30 Jun 2009 13:13:53 GMT

Hi,

How can I figure out how many 4 digit combinations can be made from 5 digits.

Then, how do I actually GET these combinations? ( I want to put them through a filter, of course.)

Any help is appreciated.