Modeling The P3

Reply #23

retxx — Sat, 22 Aug 2009 14:30:19 GMT

can you tell me where on the chart to click on for a popup window to ask me how many days I want. What cell would it be/ Thanks

Reply #22

sysp34 — Wed, 19 Aug 2009 11:23:33 GMT

unstable tricks use 5, 10 n 15 for singapore 4D use last 50 draws pick 3

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

Enter the number of days back you want to go to determine the model

Choose a number less than or equal to 50

5

Best Model - 0-2-4-8-9

Best Model - 1-2-4-5-9

Best Model - 1-2-4-8-9

Wheeling with any of these models would have

produced 3 winners over the past 5 draws

***Enter any key to exit***

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

Enter the number

Reply #21

pick4hawk — Tue, 18 Aug 2009 16:19:09 GMT

jayemmar:

I enjoyed seeing the code --at least some people at LP share code ideas

Thanks

Hawk

Reply #20

jayemmar — Tue, 18 Aug 2009 15:48:22 GMT

For a continuation of this thread and instructions for downloading the program see: Modeling The P3 Part 2

jayemmar

Reply #19

jayemmar — Tue, 18 Aug 2009 14:48:39 GMT

There is a total of 252 different sets of 5 distinct digits. The program I wrote takes each of these sets of numbers and dtermines how many hit is was able to get over a given term(10 days, 15 days etc.). The set(s) of numbers with the highest performance is the model for the given term.

I'm looking in to finding a hosting site from which the program can be downloaded, so that everyone can use the program without having to be concerned about compiling programns.

jayemmar

Reply #18

jayemmar — Tue, 18 Aug 2009 14:43:52 GMT

I'm looking into this now. I hope we'll have some results by the end of day.

jayemmar

Reply #17

BobP — Tue, 18 Aug 2009 06:50:43 GMT

Using CoverMaster I get 17 sets for boxed all different, is that right?

1 2 3 5 9

1 2 4 6 7

1 2 4 8 9

1 2 7 8 0

1 3 4 7 0

1 3 6 7 9

1 3 8 9 0

1 4 5 7 8

1 5 6 8 0

2 3 4 5 6

2 3 5 6 0

2 3 5 7 8

2 4 6 8 0

2 6 7 9 0

3 4 6 8 9

4 5 7 9 0

5 6 7 8 9

Some overlap as 17 sets is 170 numbers and there are 120 all different boxed numbers. As you said, as soon as one hits, another pops up like whack-a-mole.

I also get 30 sets of 4 digits = four... [ More ]

Reply #16

retxx — Tue, 18 Aug 2009 01:57:22 GMT

amen to that. maybe to an excel format would be great for us dummies out here that cannot follow you. Thanks

Reply #15

mej023 — Mon, 17 Aug 2009 23:07:35 GMT

jayemmar,

You create the executable file and then put a copy of it on the Internet somewhere and then provide a link to that location. I have not looked but there has got to be a few free websites on the Internet that would allow you to upload a file.

At the very least you could create a copy of your file and then copy it to one of my domains. The resultant executable file should compile to a pretty small file.

What do you think

Reply #14

jayemmar — Mon, 17 Aug 2009 20:35:14 GMT

I'm posting this again, becase I did not see the answer I posted to the above Post.

You have probably been asked this before. Is there any way you could compile this to an executable file that people could download?

If someone could explain the mechanics of doing this, I would agree.

When boxing a 5 wheel number set there are 30 numbers minus the triples.

jayemmar

Reply #13

mej023 — Mon, 17 Aug 2009 20:11:12 GMT

Hi jayemmar -

You have probably been asked this before. Is there any way you could compile this to an executable file that people could download?

With the 5 digit models, when we wheel those then we get 35 boxed numbers and if we filter out triples then we get 30 boxed numbers. Is this correct?

To really test the models, would you take a draw file of say 100 draws and then run the model program on the first 50 draws to get the model that produces the most hits for the first 50... [ More ]

Reply #12

jayemmar — Mon, 17 Aug 2009 20:07:42 GMT

Here's something interesting to consider when creating models. A 10day model of the NY Midday P3 gave the following results, using 50 past draws starting from 08/12/09 and back:

Best Model - 1-3-4-7-8

Wheeling with this model would have produced

5 winners over the past 10 draws

These last 10 days of play provided quite a hefty win. Let's analyze this. The 5 number wheel set, 1-3-4-7-8, gave 50% winners over the last 10 days. Ordinarily, given any 5 number wheel set, the probabil... [ More ]

Reply #11

jayemmar — Mon, 17 Aug 2009 19:35:45 GMT

Hi mej023:

This is an interesting idea and would require some thought.

If you run the model program I wrote, you'll notice that over any term chosen, the model set(s) that comes up always shows quite a generous profit over the selected term. That's why I chose a 5 number model.

jayemmar

Reply #10

jayemmar — Mon, 17 Aug 2009 19:19:39 GMT

OK. I think we are back on track. Below the asterisks, you'll find the corrected code for modeling the P3.

Thanks for your patience.

jayemmar

***********************************************************

#include math.h

#include stdlib.h

#include stdio.h

int main()

{

int i, j , k, temp1, temp2, temp3, temp4, a1, a2, a3, a4, a, temp5, k1;

int drawCount, hit, percent, results, numSets = 0, hitNum = 50;

int twoHitsa1 = 0, twoHitsa2 = 0, twoHitsa3 = 0, two... [ More ]

Reply #9

jayemmar — Mon, 17 Aug 2009 18:32:40 GMT

You know what happens when you hit one nail - another one pops up. It seems that the correction to the last error has caused another. Please bear with me until all errors are determined and fixed. I'll keep you posted.

jayemmar

Reply #8

mej023 — Mon, 17 Aug 2009 17:52:24 GMT

I guess one way would be to develop some sort of indicator that would point to the appropriate model.

Maybe you find 5 models that account for 70% or more hits in all of the past draws. Then figure out what model to use on a particular day.

Let's say the last draw was 756. I have two models - one is 4-5-6-8-9 and the other is 1-2-4-5-7. I would probably choose the second model just because the next number drawn (in general) will probably be lower than 756.

You have a really in... [ More ]

Reply #7

jayemmar — Mon, 17 Aug 2009 17:45:54 GMT

I'm real sorry for this, but there's a mistake in the code I supplied to create the models that were described in the Post. Below the asterisks you'll find the correct code.

The error did not allow for the complete coverage of the 252 possible sets of 5 wheels. Only 210 of the 252 were considered.

jayemmar

********************************************************************

#include math.h

#include stdlib.h

#include stdio.h

int main()

{

int i, j , k, temp1, te... [ More ]

Reply #6

jayemmar — Mon, 17 Aug 2009 17:39:56 GMT

Not a bad idea, but how do you keep the cost down?

jayemmar

Reply #5

mej023 — Mon, 17 Aug 2009 17:27:49 GMT

I was wondering if it would be a good idea to switch out a couple of the numbers every other day or so.

For example, I have noticed that in the Indiana daily that a 0 or 1 shows up constantly with a draw or two gap in between hits of those digits. The same thing for the numbers 7, 8 or 9. The kicker is that the two groups seem to alternate, so one day playing 0-1-2-8-9 will result in a hit but not the next day. The next day the grouping might be 4-5-7-8-9.

I guess, I am wondering if the ti... [ More ]

Reply #4

jayemmar — Mon, 17 Aug 2009 15:26:46 GMT

Here are some models that were determined for the Ga Midday and Eve P3.

Ga Midday P3 - 50day model - 0-2-3-5-9; 30day model - 0-1-5-7-8, 0-4-5-8-9,and 0-5-7-8-9; 25day model -0-4-5-8-9; 10day model 0-3-4-5-8, 0-4-5-6-8, and 0-4-5-7-8

Ga Eve P3 - 50day Model - 2-3-4-5-9; 30day model - 2-3-5-6-9;

25day model - 0-2-5-6-9, 2-3-4-5-9, and 2-3-5-6-9; 10day model - 0-2-3-5-9,

0-3-5-6-9, 0-3-5-7-9, 0-3-5-8-9, 2-3-4-5-9, and 2-3-5-6-9

We can see two things from here:

1. The Midday

Reply #3

Stalyn — Sun, 16 Aug 2009 23:08:00 GMT

Thank you jay, will test this when i get some free time.

Reply #2

ace649 — Sun, 16 Aug 2009 22:57:48 GMT

Impresive idea JAY.

Reply #1

Shawn67 — Sun, 16 Aug 2009 22:42:59 GMT

Not sure that I understand the code, but I like the idea and thinking behind it. I've thought about something like this before, but as someone who does almost everything using pencil and paper, this seems like a huge pain to do manually. Hopefully someone with more knowledge and experience could explain a pencil and paper method for this approach that would be easy for everyone to understand.

Modeling The P3

jayemmar — Sun, 16 Aug 2009 21:57:47 GMT

In this post we will propose a method for modeling any P3lottery. The method consists of determining which set(s) of 5 number wheelsgave the most winners over the last N draws. So, for example, if we say thatthe 10 day model for such and such a P3 lottery is 1-2-4-6-9, we would meanthat the 5 number wheel set , 1-2-4-6-9, produced the most winners over thelast 10 days. In this scenario, this model would be considered a short termmodel. Longer term models (15, 20, 25, or 50 days, for example) can... [ More ]