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		<title>How to Win 20 Pick5/39 Jackpots a year: Hypothesis...</title>
		<link>https://www.lotterypost.com/thread/208227</link>
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		<description>Lottery Post Forum Topic: How to Win 20 Pick5/39 Jackpots a year: Hypothesis...</description>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/208227/1552005</link>
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			<pubDate>Thu, 11 Feb 2010 23:21:24 GMT</pubDate>
			<dc:creator>cdclark</dc:creator>
			<description><![CDATA[<p>This is an interesting approach. I&#x27;m a little confused about how it works but I tried it tonite. It reminds me of the delta numbers chosing numbers 1-15. I keep up with Fantasy 5 and it is amazing how the numbers will group together.</p>]]></description>
			<category>cdclark</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/208227/1544513</link>
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			<pubDate>Fri, 05 Feb 2010 04:16:09 GMT</pubDate>
			<dc:creator>pumpi76</dc:creator>
			<description><![CDATA[<p>you then divide the 12 range into: 3 s like for instance from: 22-34 you can: make it this way:<br /><br />22, 23, 24 = 3<br /><br />25, 26, 27 = 3<br /><br />28, 29, 30 = 3<br /><br />31,32, 33, 34 = 3<br /><br />3x3x3x3 = 81 but since you are selecting: 2 in 1 group of 3 sometimes it might be 3x2x3x3 = 54....<br /><br />if you READ it says: filter, i am asking you to filter them...</p>]]></description>
			<category>pumpi76</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/208227/1543622</link>
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			<pubDate>Thu, 04 Feb 2010 17:46:01 GMT</pubDate>
			<dc:creator>Stack47</dc:creator>
			<description><![CDATA[<p>So basically you&#x27;re saying to pair up 10 numbers and play them 12 other numbers in sets of 3. 10 numbers have 45 pairs and there are 220 sets of 3s in the other 12 numbers. 45 X 220 = 9900 combos. While it&#x27;s true you would hit the jackpot by matching any 2 of the 10 with any 3 of the 12, you haven&#x27;t said how to pick which 22 numbers out of 39 or how you determine which of the 22 numbers will be used as the 10 numbers.<br /><br />Are we suppose to wager $9900 on a guess</p>]]></description>
			<category>Stack47</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/208227/1543197</link>
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			<pubDate>Thu, 04 Feb 2010 06:37:04 GMT</pubDate>
			<dc:creator>pumpi76</dc:creator>
			<description><![CDATA[<p>so what you do is: For instance: Filter a Pick2/10 (combination game make sure is the Pick5 of your state) or should i say a: Pick2/1-10 (combination game not permutation game) and filter a: Pick3/12 (combination game) or should i say a: Pick3/22-34 (combination game)....And you pair them together....</p>]]></description>
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			<title>How to Win 20 Pick5/39 Jackpots a year: Hypothesis...</title>
			<link>https://www.lotterypost.com/thread/208227</link>
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			<pubDate>Thu, 04 Feb 2010 05:51:21 GMT</pubDate>
			<dc:creator>pumpi76</dc:creator>
			<description><![CDATA[<p>How will you like to pick 1 or 2 numbers from: 1-10 and 3 numbers from 1 to 12...And you win...<br /><br />Well A LOT OF PICK5/39 drawings are like that...I got the idea after i started thinking: divide a Pick5/39 in 2 halves....1-20 the first half, 21-39 the second half...Now what if you started counting from 1-20 (the first half) but the second half which is 21-39 you start back from 1 to 20 so that:<br /><br />21=1<br /><br />22=2<br /><br />23=3<br /><br />24=4<br /><br />25=5<br /><br />26=6<br /><br />27=7<br /><br />28=8...<br /><br />And so on until you reach to: 39... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/208227">More</a>&#xa0;&#x5d;</p>]]></description>
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