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		<title>Pennsylvania Cash 5/43 Lottery - Possible Strategy</title>
		<link>https://www.lotterypost.com/thread/212157</link>
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		<description>Lottery Post Forum Topic: Pennsylvania Cash 5/43 Lottery - Possible Strategy</description>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/212157/1614378</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/212157/1614378</guid>
			<pubDate>Fri, 09 Apr 2010 22:34:28 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>I created an Excel file that will take the 2214 combinations and randomly select 15 combinations from the 784 combinations with a Unique Value of 9 and randomly select 20 combinations from the 1430 combinations with a unique value of 10.<br /><br />Here are my picks for the Pennsylvania Cash 5/43 for Friday Eve April 9, 2010:<br /><br />See if we can catch some winners!!<br /><br />Here is the download link to the Excel file: (This is only if your playing a 5/43 game (no bonus numbers)<br /><br />Not sure how many states h... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/212157/1614378">More</a>&#xa0;&#x5d;</p>]]></description>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/212157/1614363</link>
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			<pubDate>Fri, 09 Apr 2010 22:21:16 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>In the 2nd post I said that there were a total of 3,125 total combinations using the highest totals for each position.<br /><br />Position 1: Digits 1, 2, 3, 4, 5<br /><br />Position 2: Digits 9, 10, 11, 12, 13<br /><br />Position 3: Digits 20, 21, 22, 23, 24<br /><br />Position 4: Digits 31, 32, 33, 34, 35<br /><br />Position 5: Digits 39, 40, 41, 42, 43<br /><br />The next step is that I took the 3,125 total combinations and filtered them down to any combination that had a Unique Value of 9 and 10.<br /><br />After filtering them I came up with the... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/212157/1614363">More</a>&#xa0;&#x5d;</p>]]></description>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/212157/1614341</link>
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			<pubDate>Fri, 09 Apr 2010 21:56:52 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>In this post the credit goes to Carbob for providing formula for Unique Values<br /><br />Unique Values is a calculating your draw as follows:<br /><br />The last drawing for Pennsylvania Cash 5/43 on April 8, 2010 was:<br /><br />2 - 19 - 27 - 34 - 38<br /><br />So to get the Unique Value you take Position 1 and Position 2 and calculate the differnce. So in the above example you take the difference between the 2 and the 19 and come up with 17.<br /><br />Here are all the difference calculations:<br /><br />P1(2) P2(19) = 17<br /><br />P1(2) P3(27</p>]]></description>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/212157/1614315</link>
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			<pubDate>Fri, 09 Apr 2010 21:23:27 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>So you can see from the images above the Top 5 in:<br /><br />Postion 1 the top 5 are 1, 2, 3, 4, 5,<br /><br />Postion 2 the top 5 are 9, 10, 11, 12, 13, 14,<br /><br />Postion 3 the top 5 are 20, 21, 22, 23, 24<br /><br />Postion 4 the top 5 are 31, 32, 33, 34, 35<br /><br />Postion 5 the top 5 are 39, 40, 41, 42, 43<br /><br />If you wheel all the digits by position you end up with 3,125 total combinations. So when the Pennsylvania Cash 5/43 is completed a sorted from low to high and you see that in Position 1 you have either 1 through 5</p>]]></description>
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			<title>Pennsylvania Cash 5/43 Lottery - Possible Strategy</title>
			<link>https://www.lotterypost.com/thread/212157</link>
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			<pubDate>Fri, 09 Apr 2010 20:58:31 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>Pennsylvania Cash 5/43 (changed from 5/39 to 5/43 on Feb. 1, 2008)<br /><br />There are a total of 962,598 possible combinations.<br /><br />I created a chart that shows how many times a digit in positions 1 through 5 appear in all 962,598 combinations<br /><br />So for example, the number 1 appears in the 1st position 111,930 times. Same for number 43.<br /><br />Each number 1-43 appears in 111,930 combinations<br /><br />What if you take each Position 1 through 5 and locate the top 5 totals for each position?<br /><br />It would loo... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/212157">More</a>&#xa0;&#x5d;</p>]]></description>
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