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		<title>Another Excel Question...</title>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/218023/1727229</link>
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			<pubDate>Sat, 31 Jul 2010 00:38:06 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>7412 (In Cell J3)<br /><br />=INT(J3/1000) &#x27; Formula in cell K3<br /><br />=INT((J3-(K3*1000))/100) &#x27; Formula in cell L3<br /><br />=INT((J3-((K3*1000)+(L3*100)))/10) &#x27; Formula in cell M3<br /><br />=INT((J3-((K3*1000)+(L3*100)+(M3*10)))) &#x27; Formula in cell N3</p>]]></description>
			<category>winsumloosesum</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/218023/1726475</link>
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			<pubDate>Fri, 30 Jul 2010 05:21:35 GMT</pubDate>
			<dc:creator>Rakster</dc:creator>
			<description><![CDATA[<p>Thanks guys...</p>]]></description>
			<category>Rakster</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/218023/1724564</link>
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			<pubDate>Wed, 28 Jul 2010 12:28:59 GMT</pubDate>
			<dc:creator>hotshot4</dc:creator>
			<description><![CDATA[<p>You will not have to use a formula if you use the Data to Column, and you can do a whole column of numbers. Work with it<br /><br />and see how easy it is.</p>]]></description>
			<category>hotshot4</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/218023/1724416</link>
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			<pubDate>Wed, 28 Jul 2010 03:58:43 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>Lottery Post Forums Search is Your Friend:<br /><br />https://www.lotterypost.com/thread/172280/1000196</p>]]></description>
			<category>Raven62</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/218023/1724256</link>
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			<pubDate>Wed, 28 Jul 2010 01:37:51 GMT</pubDate>
			<dc:creator>phileight</dc:creator>
			<description><![CDATA[<p>I assume you are looking for a formula<br /><br />several ways to do this. my favorite is =mid(j3,1,1) for the first # then =mid(j3,2,1) etc.<br /><br />j3 is obviously cell reference. next digit defines the position you want to start, then 3rd # tells it how many #&#x27;s to select. by using 1 i get 1 number</p>]]></description>
			<category>phileight</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/218023/1724069</link>
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			<pubDate>Tue, 27 Jul 2010 23:25:05 GMT</pubDate>
			<dc:creator>hotshot4</dc:creator>
			<description><![CDATA[<p>Hi-Lite the cell the numbers are in, click on Data, then Text to Columns, click the Fixed width , then next, click on to creat a breaking line click<br /><br />at the desired position, (place a line between each didgit), then click finsh.<br /><br />Hope this works for you</p>]]></description>
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			<title>Another Excel Question...</title>
			<link>https://www.lotterypost.com/thread/218023</link>
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			<pubDate>Tue, 27 Jul 2010 21:45:34 GMT</pubDate>
			<dc:creator>Rakster</dc:creator>
			<description><![CDATA[<p>If I have the number 7412 in cell J3<br /><br />How do I formulate it so I can get the 7 in one cell, the 4 in another cell the 2 in another cell and the 1 in another cell?<br /><br />These formulas get me the first 3 digits into seperate columns but how do I get the 4th digit...anyone know the formula for this one?<br /><br />Thanks<br /><br />=IF(ISBLANK(J3), ,INT(J3/100))<br /><br />=IF(ISBLANK(J3), ,INT((J3-(K3*100))/10))<br /><br />=IF(ISBLANK(J3), ,INT((J3-((K3*100)+L3*10</p>]]></description>
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