Paradoxical Dice

Reply #12

RL-RANDOMLOGIC — Fri, 01 Oct 2010 06:11:56 GMT

jimmy

no brainer, I let you select first and then I choose which I will use after you make your

selection.

RL

Reply #11

jimmy4164 — Fri, 10 Sep 2010 14:16:34 GMT

Sorry for that ?

http://mathforum.org/isaac/problems/prob1.html

Reply #10

jimmy4164 — Fri, 10 Sep 2010 14:10:23 GMT

Here's some more background for those interested...

http://mathforum.org/isaac/problems/prob1.html

Reply #9

jimmy4164 — Tue, 07 Sep 2010 17:34:31 GMT

All!

Joker17 is having some fun here, but I really thought there would be sincere interest in this Paradoxical Phenomenon.

If you have aspirations of logically deducing a method to predict lottery draws, this is the kind of challenge you should be accepting in an effort to hone your skills!

--Jimmy4164

Reply #8

joker17 — Sat, 04 Sep 2010 19:23:48 GMT

I really can't explain it any clearer than the above explanations. But here are the equations I used to determine the problems facing the variance degradation and paradoxal curve coefficient flux parameters.

J(y,z)=\int_a^b\[ y''z' + xyz'' + z'''y^2\] dx` `Answer: {xz'' + (2y + 1)z''' = 0` `{2y' + xy'' - 6y'y'' + (2y+1)y''' = 0..

(x-12) 2 + (y+9) 2 = 15 (y+9) 2 = 15 - (x-3) 2 y+9 = (15 - (x-12) 2 ) y =(15 - (x-12) 2 )-.. ( [3x - 3x^2 +1]^744 ) x ( [- 3x + 3x^2 +1]^745... [ More ]

Reply #7

jimmy4164 — Sat, 04 Sep 2010 16:49:49 GMT

joker17,

Mr Peterson's description over at MathTrek makes a lot more sense to me than yours. Of course, this could be a deficiency in my ability to comprehend [your] analysis. Are you going to be one of those members forced to craft a set of the dice so you can conduct the simulation yourself before you will be convinced? On 2nd thought, based on what you wrote above, maybe I shouldn't jump to the conclusion that you are not convinced!

--Jimmy4164

Reply #6

joker17 — Sat, 04 Sep 2010 14:46:41 GMT

I understand that it's not about a real dice game, but my point was that the die which was the opposing picks retained prior to the elevation of the data dealing with variance, was the one that the probability component devised, and not the additional sets which can be determined by the factors preceding the nontransitive dice, but not to be confused with the magic square properties written about earlier when the proposal was made to triumph in 10 games or less.

In other words ,beating the se... [ More ]

Reply #5

jimmy4164 — Sat, 04 Sep 2010 01:53:31 GMT

joker17,

Did you read the discussion linked to in the original post?

http://www.maa.org/mathland/mathtrek_04_15_02.html

This isn't about a real dice game played for money.

It's about math and probability, which all gamblers should know cold!

--Jimmy4164

Reply #4

joker17 — Sat, 04 Sep 2010 00:55:53 GMT

But what would happen when the chosen number containing the remaining ones were 2 out of 3 in the first and seconds throws?

Also, How would the bet be generated when it could've been based on an average probability theory not actual construct of a typical set?

Whether the 4 number selection was only 2/3 of the chosen 4 dice that remain, or whether the simulation was in fact a correct combination wouldn't matter because I'd rather have the ability to introduce the randomness delusion theory... [ More ]

Reply #3

Coin Toss — Fri, 03 Sep 2010 22:48:39 GMT

Yeah, good point, but I still would't get in such a game.

I forget exactly how it goes but there''s a bar room game of Solitaire for money, you pay $52 for the deck and then try to win it back, and more. Guess who usually wins that one

Reply #2

jimmy4164 — Fri, 03 Sep 2010 05:21:07 GMT

What did you think of the NON-Transitivity of the Probability Relationships among the 4 dice?

These dice are fun in a bar, playing for pennies. Initially, most people think they're loaded.

When you let them keep picking a new one, they then suspect you have a trick way of throwing

them. When you let one of their friends throw for you, and you still beat them, depending on

how much they had to drink, they get a very strange look on their face. I wouldn't suggest doing

this with peo... [ More ]

Reply #1

Coin Toss — Thu, 02 Sep 2010 23:37:24 GMT

I have four 6 sided FAIR dice, labeled A, B, C, D.

They are numbered differently than normal dice, but each contain some combination of the set [0 1 2 3 4 5 6].

Who is going to get into a dice game with someone using a die with 0 on it? Or a blank die with no pips. Not me.

Paradoxical Dice

jimmy4164 — Wed, 01 Sep 2010 18:54:20 GMT

For the believers in the Gambler's Fallacy mucking around in my Fooled By Randomness thread, this is going to be a real mind bender!

I have four 6 sided FAIR dice, labeled A, B, C, D.

They are numbered differently than normal dice, but each contain some combination of the set [0 1 2 3 4 5 6].

If you pick any one of the 4, I can select one of the 3 remaining, and in a simple game of match, I can beat you,

on average, 2 out of 3 times.

When you are convinced you are losing 2/3... [ More ]