Vtracs same as LDR (shortsum)

Reply #5

Jordans121 — Tue, 14 Dec 2010 04:03:06 GMT

BX

002,008,053,062,071,075,084,093,110,116,143

152,165,174,183,192,198,224,228,264,273,297

332,336,354,387,396,440,444,486,495,552,558

576,598,660,666,697,774,778,882,886,990,994

STr8

002,008,011,017,020,026,035,039,044,048,053,057,062,066,071,075,080,084,093,099,

101,107,110,116,125,129,134,138,143,147,152,156,161,165,170,174,183,189,192,198,

200,206,215,219,224,228,233,237,242,246,251,255,260,264,273,279,282,288,291,297

305,309,314,318,323,327,332,336,341,345,35... [ More ]

Reply #4

MzDuffleBaglady — Tue, 14 Dec 2010 00:56:37 GMT

Good Workout @ Jordans121

Wish I could have played in Illinois today, Missouri has not let that, 125 go since December of Last YEAR.

Hope Missouri follows Illinois, but,I didn't play, 125 tonight, lmaoooooooooooooooooooo

Good Luck.

Reply #3

Jordans121 — Mon, 13 Dec 2010 22:35:34 GMT

Reply #2

Todd — Mon, 13 Dec 2010 16:26:10 GMT

Reply #1

Jordans121 — Sun, 12 Dec 2010 19:47:45 GMT

Depending on how you represent each LDR you will have a different set of numbers but they still will be equally distributed in terms of the amount of numbers. Also, each holds singles, doubles, and triples, niiiiice

Vtracs same as LDR (shortsum)

Jordans121 — Sun, 12 Dec 2010 19:26:59 GMT

Over the past few months I have been really breaking down the vtracs and their distribution of numbers and what i have found is that when broken down from all possible P3 bx combinations you will end up with 10 sets of 22 numbers which is the same as choosing a shortsum (1=22 nums). Furthermore, I found that when you select a sum of a set of representers (vtracs) you only have 7 instead of 13 using regular vtrac sums. The only difference is that you can break vtrac numbers down to 12,8, and 6.