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		<title>Wheel Help</title>
		<link>https://www.lotterypost.com/thread/236810</link>
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		<description>Lottery Post Forum Topic: Wheel Help</description>
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			<title>Reply #14</title>
			<link>https://www.lotterypost.com/thread/236810/2220208</link>
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			<pubDate>Thu, 22 Sep 2011 21:39:40 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello ate 80 numbers<br /><br />02-61 24-52 36-48 24-40 13-70 03-79 31-39 04-51 52-70 ou ate 100 01<br /><br />02<br /><br />09<br /><br />10<br /><br />19<br /><br />29<br /><br />80<br /><br />83<br /><br />96<br /><br />40<br /><br />45<br /><br />56<br /><br />64<br /><br />71<br /><br />90<br /><br />92<br /><br />96<br /><br />97</p>]]></description>
			<category>dr san</category>
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		<item>
			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/236810/2218630</link>
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			<pubDate>Wed, 21 Sep 2011 17:26:55 GMT</pubDate>
			<dc:creator>Stack47</dc:creator>
			<description><![CDATA[<p>If you&#x27;re playing front pair or back pair, 81 would be the correct number using 9 digits.<br /><br />Let&#x27;s say you&#x27;re positive the digit 1 will be drawn in your next pick-3 drawing but don&#x27;t know in which digit position or how many times. You could play all the box combos using the digit 1 . There are 90 doubles and 120 single box combinations in pick-3 games but you only want the combos using the digit 1 . You multiple 10 times 9 and divide that by 2 or 45 combos which include all the combos with doubl... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/236810/2218630">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Stack47</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/236810/2218587</link>
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			<pubDate>Wed, 21 Sep 2011 16:44:55 GMT</pubDate>
			<dc:creator>Stack47</dc:creator>
			<description><![CDATA[<p>Hmm, isn&#x27;t the answer 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1?<br /><br />They are only using two number combos and want each number with each of the other 8 numbers, it&#x27;s 9 times 8 divided by 2. The reason 72 is divided by 2 is because in Keno the combo 1-9 is the same as the combo 9-1 and 2-8 is the same as 8-2, ect.<br /><br />The first number is paired with 8 numbers and since the second number is already paired with the first, it&#x27;s paired with the 7 other numbers. The third number is already paired with the fir... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/236810/2218587">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Stack47</category>
		</item>
		<item>
			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/236810/2218019</link>
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			<pubDate>Wed, 21 Sep 2011 02:36:41 GMT</pubDate>
			<dc:creator>Greg</dc:creator>
			<description><![CDATA[<p>Hmm, isn&#x27;t the answer 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1?<br /><br />But I don&#x27;t think is this 100% correct, hmmm</p>]]></description>
			<category>Greg</category>
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		<item>
			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/236810/2217281</link>
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			<pubDate>Tue, 20 Sep 2011 16:14:37 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, perfect, stack47, just by replacing letters in their positions, also when the inversion example 21 = 12 = AB = BA THANK STACK47</p>]]></description>
			<category>dr san</category>
		</item>
		<item>
			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/236810/2217259</link>
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			<pubDate>Tue, 20 Sep 2011 15:44:36 GMT</pubDate>
			<dc:creator>Stack47</dc:creator>
			<description><![CDATA[<p>In Keno since each number can only be drawn once. it can&#x27;t be 81 (9X9) so start with 72 (9X8). And because 1-9 is the same as 9-1, 2-8, 8-2, etc., divide 72 by 2 and you&#x27;ll have 36 two number combos using 9 numbers.<br /><br />Dr. San was helpful enough to show all 36 combos and if you use A to I instead of 1 to 9, you can substitute your 9 numbers for each letter.</p>]]></description>
			<category>Stack47</category>
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		<item>
			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/236810/2216727</link>
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			<pubDate>Tue, 20 Sep 2011 02:21:47 GMT</pubDate>
			<dc:creator>LANTERN</dc:creator>
			<description><![CDATA[<p>Yes, 81 including doubles if that game has doubles otherwise it would be fewer, I am not sure, but without doubles maybe only 72.</p>]]></description>
			<category>LANTERN</category>
		</item>
		<item>
			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/236810/2216270</link>
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			<pubDate>Mon, 19 Sep 2011 20:38:22 GMT</pubDate>
			<dc:creator>olplugger</dc:creator>
			<description><![CDATA[<p>That&#x27;s correct Teamprofit....For some reason I did 2 x 9, instead of 9 x 9. . . (not thinking maybe?)<br /><br />Thanks for getting us back on track.</p>]]></description>
			<category>olplugger</category>
		</item>
		<item>
			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/236810/2216265</link>
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			<pubDate>Mon, 19 Sep 2011 20:32:30 GMT</pubDate>
			<dc:creator>Teamprofit</dc:creator>
			<description><![CDATA[<p>It should be 9X9=81 total combinations</p>]]></description>
			<category>Teamprofit</category>
		</item>
		<item>
			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/236810/2216221</link>
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			<pubDate>Mon, 19 Sep 2011 19:30:03 GMT</pubDate>
			<dc:creator>olplugger</dc:creator>
			<description><![CDATA[<p>Hi downanddirty,<br /><br />My answer is not correct. Sorry about that</p>]]></description>
			<category>olplugger</category>
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		<item>
			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/236810/2216213</link>
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			<pubDate>Mon, 19 Sep 2011 19:23:06 GMT</pubDate>
			<dc:creator>olplugger</dc:creator>
			<description><![CDATA[<p>There are 18 combinations.<br /><br />(2 x 9 = 18)<br /><br />Hope that helps! Hope you WIN big</p>]]></description>
			<category>olplugger</category>
		</item>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/236810/2216208</link>
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			<pubDate>Mon, 19 Sep 2011 19:17:59 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, are all possible combinations of 1 to 9 in two digits</p>]]></description>
			<category>dr san</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/236810/2216181</link>
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			<pubDate>Mon, 19 Sep 2011 18:59:16 GMT</pubDate>
			<dc:creator>DownandDirty</dc:creator>
			<description><![CDATA[<p>Could you elaborate on your answer. What do all those numbers mean?<br /><br />I was was looking for one answer.....such as (there are 32 combinations</p>]]></description>
			<category>DownandDirty</category>
		</item>
		<item>
			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/236810/2216131</link>
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			<pubDate>Mon, 19 Sep 2011 18:09:07 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello downandirty<br /><br />12 13 14 15 16 17 18 19 23 24 25 26 27 28 29 34 35 36 37 38 39 45 46 47 48 49 56 57 58 59 67 68 69 78 79 89</p>]]></description>
			<category>dr san</category>
		</item>
		<item>
			<title>Wheel Help</title>
			<link>https://www.lotterypost.com/thread/236810</link>
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			<pubDate>Mon, 19 Sep 2011 17:22:11 GMT</pubDate>
			<dc:creator>DownandDirty</dc:creator>
			<description><![CDATA[<p>I have narrowed a Pick 2 game of Keno down to 9 possible numbers.<br /><br />How many combinations are there of 2 numbers in a filed of 9</p>]]></description>
			<category>DownandDirty</category>
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