How to win Pick3: 365 days a year...

Reply #3

Stack47 — Sun, 19 Feb 2012 18:47:12 GMT

The problem is Pumpi again forgot to do the math. There are a total of 657 three digit numbers with at least one of the digits from the previous drawing, only 343 without, and his 50% is actually 34.3%. Even if a double is drawn, the odds are only slightly against one of the two digits repeating by 51.2%.

A better percentage bet would be to key on one of the digits repeating from the previous drawing and play some of the 441 three digit numbers. It's only 294 playing the three numbers combos... [ More ]

Reply #2

dell1972 — Sun, 19 Feb 2012 17:59:23 GMT

Hello

Could you give us an example of your new wheel system? Thanks

Reply #1

flossdog — Sun, 19 Feb 2012 14:06:55 GMT

This topic has the wrong title.

Theoretically always looks good on paper. This whole reasoning is absurd. Working your magic? LOL. Are we magicians? Seriously, listen to what you are purporting.You have to be right 50% of the time with the 7 numbers being magically aligned? Try this experiment where you only need 1 out of 2. Put 50 black marbles in a box with 50 white ones. The white ones represent a win the black a loss. Take a marble out one at a time without looking. You could easily pick

How to win Pick3: 365 days a year...

pumpi76 — Sun, 19 Feb 2012 09:45:42 GMT

Half of the month s pick3 drawings whenever All 3 numbers play the following drawing those 3 numbers dont play/repeat...So a 3/3 box wheel comes out to: $35 dollars...

But what if you had a: 2/3 box wheel size 7...Lets say it comes out to: $10 it will have: 10 box combinations, thus the: $10...

so if you set it up where:

1,2,3 = 1A

4,5,6 = 2B

7,8,9 = 3C

the: 1A, 2B, 3C are compressed numbers the rest of numbers are regular numbers...

and each of those 10 box combinations... [ More ]