lottery

Reply #20

RJOh — Sun, 10 Jun 2012 04:46:43 GMT

I don't do Excel but if you use Excel and have data files for the games you play, it shouldn't be hard to come up with something. I'm still using GWBasic and it only took a few lines to code a routine to collect and display the data for each position.

Reply #19

dr san — Sat, 09 Jun 2012 13:00:12 GMT

Have you considered rather than looking at positional probabilities looking at positional actualities, that is which numbers have actually followed the winning numbers in those positions in past drawings. I've tracked numbers in Ohio Classic Lotto drawings since it started and find lately at least three repeat and the rest are ones that followed other numbers in different positions.

HR, you have an example in an excel spreadsheet that has been written up, Can you give more details, for good... [ More ]

Reply #18

RJOh — Sat, 09 Jun 2012 05:02:24 GMT

With only 258 of the possible 13,983,816 combinations having 5 of the 6 winning numbers, you would need to generate more than 50,000 combinations to have even one of them unless you knew something unique about the winning combinations that reduced the need to generate so many combinations.

Many at LP have worked on discovering such a unique group of numbers and some have even claimed to have discovered them but none have proved it by winning a jackpot or even getting a 5of6 repeatedly.

Reply #17

jslmsca — Sat, 09 Jun 2012 04:24:22 GMT

Would you recommend playing all numbers? I remember reading a story on here about a Math Department at some British University doing this for about two years and winning. It's not prohibitively expensive so it may be a logical way of playing. However, I wrote a program to generate a matrix based on filters but it didn't prove particulary valuable. I'd generate a thousand matrices per draw and other than the odd 5/6, it wasn't producing enough winners to make it worthwhile.

Reply #16

lottoburg — Sat, 09 Jun 2012 00:54:05 GMT

Hi, Jamie:

Long time no see! I remember that you told us you will finish the new version of LSA in the Jun.

How about your new LSA now?

Best regards,

lb

Reply #15

RJOh — Sat, 09 Jun 2012 00:35:15 GMT

Reply #14

Developer — Fri, 08 Jun 2012 23:29:32 GMT

I have read this 5 times and can't get my head around it, it is late so maybe I will get it in the morning.

Reply #13

Developer — Fri, 08 Jun 2012 23:28:28 GMT

Then the math in that draw becomes much more complex and the odds become massive, I personally would not play such a draw unless they offered prizes for match 2

Reply #12

SergeM — Fri, 08 Jun 2012 23:22:03 GMT

In Belgium we have a full lotto, which is the a qp using all numbers once, twice or more often, to your choice.

Reply #11

Developer — Fri, 08 Jun 2012 23:17:34 GMT

A intresting fact for 6/49

13,983,816 / 15180 = 921.2 the average number of draws to pass before each 3 ball combination will appear

921.2 / 20 = 46.06 the average number of draws to pass before you hit a 3 ball combination.

To cover all 49 numbers each draw costs 9 tickets

01 02 03 04 05 06

07 08 09 10 11 12

13 14 15 16 17 18

19 20 21 22 23 24

25 26 27 28 29 30

31 32 33 34 35 36

37 38 39 40 41 42

43 44 45 46 47 48

?? ?? ?? ?? ?? 49

So 46.06 / 9 = 5.11 the

Reply #10

dr san — Fri, 08 Jun 2012 23:12:33 GMT

Hello, developer, OK 04 23 46 suit was good or more likely to position 1,4,5 perfect! Look, the big problem is finding the suit pivot, or the tender reference , Not to walk in circles, ah! Then hitting the suit based, in position, the rest is best for forecasting, thank you

Reply #9

SergeM — Fri, 08 Jun 2012 22:52:35 GMT

Reply #8

Developer — Fri, 08 Jun 2012 22:42:58 GMT

My above examples prove that any 3 ball combination you choose has exactly the same chance to appear as any other 3 ball combination in the draw.

13,983,816 / 15180 = 921.2

So on average in a 6/49 each 3 ball combination will appear once every 921.2 draws.

So again to prove the math

921.2 x the 20 possible combinations =18424 which happens to be the number of 3 ball combinations in a 6/49 draw

Althought the 20 combinations vary from combination to combination the total will always... [ More ]

Reply #7

Developer — Fri, 08 Jun 2012 22:40:48 GMT

7 23 46 from a pool of 49 numbers and you pick 6

Each ball appears a total of 1,712,304 times in the 13,983,816 possible combinations no more no less

Each 3 ball combination appears a total of 15,180 times in the 13,983,816 possible combinations no more no less

The possible positions the 3 numbers can occupy on a single ticket = 20

So we have 3 numbers from 6 choosen which produce the following 20 possible positions

07 23 46 ?? ?? ?? = 1 line contains the 3 numbers in these positi... [ More ]

Reply #6

dr san — Sun, 27 May 2012 13:30:17 GMT

Hello, rl rando, it is possible to create this filter, for example umaloteria 49/6 I want to do a trio with a suit or fixed ok 07,23,46 The suit has six digits in their composition that do not repeat each other Q = the system will use the suit with fixed, and the other three numbers missing They have repeated the six digits, then suit = 07,23,46, three other 17 33 43 So the three numbers qie complete the meso one digit repeats, And so with peers also codi ao or warranty of accuracy, has hit the

Reply #5

LottoBoner — Sun, 27 May 2012 09:09:09 GMT

Reply #4

dr san — Sun, 27 May 2012 04:36:26 GMT

Hello rl randomlogic thanks good work, it can help me now? I plan to unite three probabalidades to form a suit positional Example of a lotto 49/6 we have 20 positions Rl the best way to see the positional probability of a suit? the formula should count pascal triangles multiple, low-probability calculation spreadsheet, tab positional probability formula is correct.

review:

td = total scores

a = affixed by dzs

d1, d2, ..., dx = tens,

p1, p2, ..., px = positions,

wher... [ More ]

Reply #3

RL-RANDOMLOGIC — Sun, 27 May 2012 00:59:51 GMT

dr sam

I forgot to mention how to use the calcs, first set the matrix at the very top of the program.

Set the number of numbers in each set then set the total numbers in the game. L-Click counts

up and R-Click counts down. Then just click on any digit or number and the results will be displayed.

RL

Reply #2

dr san — Sat, 26 May 2012 22:51:30 GMT

Rl Hello, thanks for help, and give you data, Rl was seeing it from your lottery 39/5, combine pairs of extremes (lowest to highest number) of the limit from 01 to 11 (number of 1 oumenor) and 30 to 39) number of the 5 th or higher number = we have 210 pairs, giving the suit within the limits of each pair Example 30 par 11 the trio will be central in 11 to 30 (12-29) are 816 = 100% of the suit in the central trio 02-38 but because the 01 can only be the 1st and 5th position 39da

Reply #1

RL-RANDOMLOGIC — Sat, 26 May 2012 22:20:22 GMT

dr san

The link below has two calculators one for digits and the other for numbers. They both calculate the probabilities

by position.

https://www.box.com/s/y1y81bjobtg15rkkzcay

RL

lottery

dr san — Sat, 26 May 2012 20:55:01 GMT

Hello, someone knows about positional probabilities of the lottery numbers? That is, more likely to see certain numbers fall into certain positions