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		<title>Are you good at Algebra?</title>
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			<title>Reply #32</title>
			<link>https://www.lotterypost.com/thread/249745/2691681</link>
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			<pubDate>Tue, 04 Sep 2012 05:37:11 GMT</pubDate>
			<dc:creator>Scientistman</dc:creator>
			<description><![CDATA[<p>Yes Stack you are on the right track with me, y varies but y varies between 1 though 10 most of the time.<br /><br />So figuring out y is a bit like figuring out the next lotto numbers but at least I have it narrowed down to selecting the numbers between 1 through 10 and not selecting numbers between 1 through 49.<br /><br />So if I can figure out y which is between the digits 1 and 10 then I can figure out the next lotto winning numbers each and every time. If I can figure out y which is between 1 through 10 t... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2691681">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Scientistman</category>
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			<title>Reply #31</title>
			<link>https://www.lotterypost.com/thread/249745/2681475</link>
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			<pubDate>Mon, 27 Aug 2012 17:15:11 GMT</pubDate>
			<dc:creator>psykomo</dc:creator>
			<description><![CDATA[<p>Whick came first:<br /><br />The Chicken R Chick Fil UR Lay !!??<br /><br />Y = Chicken<br /><br />X = Chick Fil UR Lay !!??<br /><br />LOL = JackPot</p>]]></description>
			<category>psykomo</category>
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			<title>Reply #30</title>
			<link>https://www.lotterypost.com/thread/249745/2677641</link>
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			<pubDate>Fri, 24 Aug 2012 18:56:58 GMT</pubDate>
			<dc:creator>Stack47</dc:creator>
			<description><![CDATA[<p>10 - 2 = 8<br /><br />11 - 7 = 4<br /><br />18 - 8 = 10<br /><br />I still dont know ( y )<br /><br />8 + y = z, 4 + y = z, 10 + y = z,<br /><br />If z = 12, y must be 4, 8, or 2.<br /><br />(y) is somewhat unpredictible yet might be possibly attainable through algebra. Maybe?<br /><br />I&#x27;m assuming the value of x , w , and v is always known, but the value of y varies. Since z is the result, you can use past results to determine the past values of y . If there is a consistent value of y , use that number. If the value of y is a random number betw... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2677641">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Stack47</category>
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			<title>Reply #29</title>
			<link>https://www.lotterypost.com/thread/249745/2676514</link>
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			<pubDate>Thu, 23 Aug 2012 20:54:55 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>mathh hello, very good job!! in your previous post, then a number in the draw, he will cycle high (greater delay leaving) cycles and low (less delay exiting)<br /><br />the final space (f), is the last test that came out for the last test drawn, because there seems to be the study of the behavior of a lottery number, that there is a relationship between mathematics and physics, which determines a logical reason for a number out, we need to make clear statistics of each number, to qualify. Mathh, you may... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2676514">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #28</title>
			<link>https://www.lotterypost.com/thread/249745/2676493</link>
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			<pubDate>Thu, 23 Aug 2012 20:34:56 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, thank you, mathh is easily the largest space of a number is when it came out (and was drawn back to be raffled, eg the number 17, was selected in the test returned 102 test<br /><br />189, so he has space of 87 draws, since the smaller space he left the test came back at 189 and 194 he had a test space (distance of 5 draws), then each instance of a number 49/6. Each number see its largest space (distance output) with less space, so do have the statistic to see the biggest and best range to see me... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2676493">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #27</title>
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			<pubDate>Thu, 23 Aug 2012 12:13:22 GMT</pubDate>
			<dc:creator>mathhead</dc:creator>
			<description><![CDATA[<p>dr san wrote: ``04 = (A) (greater than) space between the draws. 05 = (B) less than) space between the draws``<br /><br />I am having trouble understanding what you want. But if it has something to do with determining the spacing between drawing the same number (or set of numbers), perhaps the following will be helpful.<br /><br />Consider the mega number of the Mega Millions lottery. There are 46 mega numbers. The probability of the same mega number appearing k drawings later (and not before) is given by t... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2675897">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>mathhead</category>
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			<title>Reply #26</title>
			<link>https://www.lotterypost.com/thread/249745/2673282</link>
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			<pubDate>Tue, 21 Aug 2012 13:11:58 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello guru thanks for replying, the big problem is the creation of the code<br /><br />Statistics. then the formula is easier then every number of a lottery<br /><br />Analyzed by formula, have an average, which will in time join a sector of the line<br /><br />Guru, you can also do to pick3 and pick 4, or a 49/6, do or spend the formula<br /><br />Only the last digit where a 49/6 or similar, then placing the first part (random) until because ranges from 0 to 4 (first digit 49/6</p>]]></description>
			<category>dr san</category>
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			<title>Reply #25</title>
			<link>https://www.lotterypost.com/thread/249745/2673266</link>
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			<pubDate>Tue, 21 Aug 2012 12:58:30 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>Dr san, I understand, unfortunately I&#x27;m not there yet. I plan on doing statistical analysis at some later point in time but its not what I&#x27;m focused on right now. When I get there, if I come up with something I&#x27;ll definitely let you know. Thanx for all the input. Good luck.</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #24</title>
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			<pubDate>Tue, 21 Aug 2012 12:57:21 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>Sorry ScientestMan, not information for me to work off of. But good luck in solving it yourself.</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #23</title>
			<link>https://www.lotterypost.com/thread/249745/2673100</link>
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			<pubDate>Tue, 21 Aug 2012 07:52:53 GMT</pubDate>
			<dc:creator>Scientistman</dc:creator>
			<description><![CDATA[<p>Ok hi this is scientistman I am the one who started the discussion. Thank you all for your input.<br /><br />I will attempt to break it down somewhat.<br /><br />I am only attempting to see if algebra might work for my formula.<br /><br />I am not wanting to give my formual away so I hope if someone wins with it they might remember me.<br /><br />I should have included more than x y and z so I will now.<br /><br />We will use v w x y and z if this is ok to do in algebra<br /><br />I know (v) and I know (w) and I know (x) I just dont know... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2673100">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>Scientistman</category>
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			<title>Reply #22</title>
			<link>https://www.lotterypost.com/thread/249745/2672924</link>
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			<pubDate>Tue, 21 Aug 2012 03:05:46 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, guru, thanks for making the item 4 may leave out. The purpose of the formula of frequencies, is to see if a given time, join the frequencies in a sector of the line,<br /><br />How you get the line, and applying the formula, the result of the registration of a lottery<br /><br />An example of a lottery = 49/6, after seeing the value of each digit of the final formula, will give an example value = the number 26 after applying the formula given = 11.213 and 10.097 47 gave (is an example) in the list number... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2672924">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #21</title>
			<link>https://www.lotterypost.com/thread/249745/2672665</link>
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			<pubDate>Tue, 21 Aug 2012 00:07:56 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>I understand a little better thank you for the clarification. I guess I still don&#x27;t see how the intial formula you described of F = ( A - B + F ) / 3 fits into the schema. Let me clarify again though your process. You are saying:<br /><br />1. Find the frequency of each possible number in the set (i.e. 1-49 in a 49/6 game)<br /><br />2. Create a frequency value that is incremented the more frequent the number appears.<br /><br />3. List the numbers with highest frequency first in a list (or file/table whatever)<br /><br />4. t... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2672665">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #20</title>
			<link>https://www.lotterypost.com/thread/249745/2672642</link>
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			<pubDate>Mon, 20 Aug 2012 23:54:48 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>Actually the first post is in this forum said what is X if you know y and z. So I was solving for X. You didn&#x27;t say you wanted a solution for Z. Besides I don&#x27;t understand the benefit of doing your problems. Again I ask, what is your point, what are you getting at? And how are these particular equations relevant to anything other than an exercise in wit</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #19</title>
			<link>https://www.lotterypost.com/thread/249745/2671832</link>
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			<pubDate>Mon, 20 Aug 2012 12:20:16 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, guru, the goal is to create a method of the frequencies of the numbers of a loteria.pois may be a relationship of numbers mathematics and physics, in the legend, are criteria for<br /><br />Classify each number, and then put a line in ascending order by the value of the classification, and see if the next draw on that sector of the line is located most of the numbers drawn from a sample = 49/6 = 12,45,06, 25,35,39,42,12,09,10,36,28,17 ...... up to 49, then to classify each number by the formula,</p>]]></description>
			<category>dr san</category>
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			<title>Reply #18</title>
			<link>https://www.lotterypost.com/thread/249745/2671728</link>
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			<pubDate>Mon, 20 Aug 2012 07:16:30 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>You did not isolate z. The question is what is z, so you have to isolate it and it is relevant.</p>]]></description>
			<category>SergeM</category>
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			<title>Reply #17</title>
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			<pubDate>Mon, 20 Aug 2012 05:15:09 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>Irrelevant. Z can be any arbitrary number (preferably an integer). The value of Z and the value of Y affect the value of X based on the formula you first posed. I don&#x27;t really understand what these formulas are pointing to anyways. Do you need to know the answer of the formula or are you just throwing random formulas out there to test the acumen of the users? Can you solve the equations yourself</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #16</title>
			<link>https://www.lotterypost.com/thread/249745/2671696</link>
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			<pubDate>Mon, 20 Aug 2012 05:12:44 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>I&#x27;m sorry dr san but I really don&#x27;t understand what you are trying to do nor how to set it up. I&#x27;ll go back over what you&#x27;ve written when I have time and see if I can figure something out, but I think we have different approaches and I&#x27;m not sure I follow yours. I&#x27;ll need some time.</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #15</title>
			<link>https://www.lotterypost.com/thread/249745/2671107</link>
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			<pubDate>Sun, 19 Aug 2012 22:14:22 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>What is z</p>]]></description>
			<category>SergeM</category>
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			<title>Reply #14</title>
			<link>https://www.lotterypost.com/thread/249745/2671092</link>
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			<pubDate>Sun, 19 Aug 2012 21:58:25 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, where is the guru understood A B E etc?, You are allowed to improve the formula<br /><br />The goal, and classify each number of a lottery, and dpois put in ascending order in a line to see for the next drawing on sector line of all the lottery numbers<br /><br />It is located most of the numbers, it is the end or the beginning of the line, you can improve the formula</p>]]></description>
			<category>dr san</category>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/249745/2670903</link>
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			<pubDate>Sun, 19 Aug 2012 19:36:21 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>x = (the (Z -2) root of 1246)) / 2y</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/249745/2670897</link>
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			<pubDate>Sun, 19 Aug 2012 19:33:06 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>Ill look at this. I&#x27;ll let ya know.</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/249745/2670648</link>
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			<pubDate>Sun, 19 Aug 2012 16:07:03 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>(2xy)z-2=1246</p>]]></description>
			<category>SergeM</category>
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			<title>Reply #10</title>
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			<pubDate>Sun, 19 Aug 2012 12:56:15 GMT</pubDate>
			<dc:creator>savagegoose</dc:creator>
			<description><![CDATA[<p>heres a goood place to start.<br /><br />http://www.khanacademy.org/exercisedashboard</p>]]></description>
			<category>savagegoose</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/249745/2670411</link>
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			<pubDate>Sun, 19 Aug 2012 11:35:58 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello, guru, perfect, good job, down to the full caption, the formula, the frequencies of the numbers of a lottery, the legend, the names of the groups A, BF, etc ....<br /><br />Guru the goal is that after each number by the frequency sorting, putting them<br /><br />In a straight line, and see if the next sweepstakes, are grouped in a sector of the line, the higher parts of numbers,<br /><br />caption =<br /><br />01 = the number of lottery<br /><br />02 = the last test<br /><br />03 = number of times the output of the number / (divided) Av... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2670411">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/249745/2670345</link>
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			<pubDate>Sun, 19 Aug 2012 08:12:49 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>It looks like your calculations are incorrect. If you are trying to isolate the F, then the calculations should run like this:<br /><br />F = (A - B + F) / 3<br /><br />F*3 = A - B + F<br /><br />3F - F = A - B<br /><br />2F = A - B<br /><br />F = (A - B) / 2<br /><br />Of course if you incorrectly typed the first line of the equation and it was supposed to read : F = (A - B + F) * 3<br /><br />Then it would follow:<br /><br />F/3 = A - B + F<br /><br />F/3 - F = A - B<br /><br />2/3(F) = A - B<br /><br />F = (A - B) * (3/2)<br /><br />OR: F = ((A - B) * 3) / 2<br /><br />The last line c... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2670345">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #7</title>
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			<pubDate>Sat, 18 Aug 2012 22:49:59 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>Hello guru is here to see the frequency of each digit<br /><br />In a lottery, after sorting the numbers put in ascending order<br /><br />In a straight line, should be grouped into sectors for the next sweepstakes<br /><br />How to calculate the execel, from a lists of sweepstakes<br /><br />The frequency of each number? Can you help me!<br /><br />Mount the frequency formula below numexcel 2010?<br /><br />Fazendo o isolamento de F:<br /><br />F = ( A - B + F ) / 3<br /><br />F / 3 = A - B + F<br /><br />B - A = F - ( F / 3 )<br /><br />B - A = 2F / 3</p>]]></description>
			<category>dr san</category>
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			<title>Reply #6</title>
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			<pubDate>Sat, 18 Aug 2012 18:43:52 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>x = the y root of (z - 2)<br /><br />example: if z = 10 and y = 3, then x = 2</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #5</title>
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			<pubDate>Sat, 18 Aug 2012 14:13:29 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>xy+2=z<br /><br />Solve that one</p>]]></description>
			<category>SergeM</category>
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			<title>Reply #4</title>
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			<pubDate>Sat, 18 Aug 2012 10:10:45 GMT</pubDate>
			<dc:creator>AlgorithmGuru</dc:creator>
			<description><![CDATA[<p>I&#x27;m curious.... Is this a question based somewhat more on number theory? Or is it more literal. You haven&#x27;t given any context for the question so it&#x27;s hard to decide in which direction to approach the answer. Your user name suggests you know how to do basic algebra and the relation between the variables is of paramount importance. So since you left it out it leads me to believe either you&#x27;re being rhetorical in a sense (maybe even mocking) or that you&#x27;re trying to see if any one knows the genera... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/249745/2669004">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>AlgorithmGuru</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/249745/2668960</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/249745/2668960</guid>
			<pubDate>Sat, 18 Aug 2012 07:55:19 GMT</pubDate>
			<dc:creator>Lucky5of5</dc:creator>
			<description><![CDATA[<p>reverse operation, right?<br /><br />X * Y=Z, so then X = Z / Y<br /><br />Z=X+Y, so then Z-Y = X</p>]]></description>
			<category>Lucky5of5</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/249745/2668105</link>
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			<pubDate>Fri, 17 Aug 2012 17:18:47 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>If x+y=0 and z=? then z=?.</p>]]></description>
			<category>SergeM</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/249745/2667952</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/249745/2667952</guid>
			<pubDate>Fri, 17 Aug 2012 15:15:57 GMT</pubDate>
			<dc:creator>RJOh</dc:creator>
			<description><![CDATA[<p>First you have to know X relation to Y and Z.<br /><br />Examples: X * Y=Z, Z=X+Y, Y/Z=X and etc.</p>]]></description>
			<category>RJOh</category>
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			<title>Are you good at Algebra?</title>
			<link>https://www.lotterypost.com/thread/249745</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/249745</guid>
			<pubDate>Fri, 17 Aug 2012 14:56:47 GMT</pubDate>
			<dc:creator>Scientistman</dc:creator>
			<description><![CDATA[<p>Ok how would you find out what X is if you know Y and Z</p>]]></description>
			<category>Scientistman</category>
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