My current approach

Reply #5

Ramijami — Mon, 22 Oct 2012 19:06:17 GMT

Thanks dr san......will have a look at your suggestion

Reply #4

dr san — Fri, 19 Oct 2012 14:08:37 GMT

Hello, ramie, you can also use a 49/6, two vtrac ok like two pick 3

We are speaking of endings (last digit 0-9)

Example = 12,25,28 36,45,49 = last digit = 2,5,8, 6,5,9

Or any way to predict pairs, any good sistem of trios and pairs of pick3 can use

On 49/6 (last digit) into two parts, or dividing into two parts, the front digits, ranging from 4 0th

Arises later

Reply #3

Ramijami — Fri, 19 Oct 2012 12:48:47 GMT

Thanks for your input BobP....my sets were chosen using RL's mirror digits (1-6, 2-7, 3-8, 4-9, 5-0) and limiting the number of consecutives. Out of the 120 sets I only kept those with 2 or less mirrors, and 4 or less consecutives which left me with the 18 sets I have. Testing on these sets in my games show a match 7/8 out of 10 draws to one of these 18 sets, and then it's just a matter of choosing which set/s to play. My sets for PowerBall tonight are 1 2 4 5 6 8 9 and 2 3 4 6 7 9 0, and for Lo... [ More ]

Reply #2

BobP — Fri, 19 Oct 2012 11:02:21 GMT

This set also closes 4if4 and brings 5if5 to 97%.

1 2 3 4 5 6 7

1 2 3 4 5 7 8

1 2 3 4 8 9 10

1 2 3 5 7 9 10

1 2 3 6 7 8 10

1 2 4 5 6 8 10

1 2 4 6 7 9 10

1 2 5 6 7 8 9

1 3 4 5 6 8 9

1 3 4 5 7 9 10

1 3 5 6 7 9 10

1 3 5 7 8 9 10

1 4 6 7 8 9 10

2 3 4 5 6 9 10

2 3 4 6 7 8 9

2 3 5 6 8 9 10

2 4 5 7 8 9 10

3 4 5 6 7 8 10

Transposed

11 12 13 14 15 16 17

11 12 13 14 15 17 18

11 12 13 14 18 19 20

11 12 13 15 17 19 20

11 12 13

Reply #1

BobP — Fri, 19 Oct 2012 10:30:08 GMT

Your sample set has 4if4 at 95%, this set closes 4if4 and improves 5if5 coverage a little.

1 2 3 4 5 9 10

1 2 3 4 6 7 8

1 2 4 5 6 8 10

1 2 4 5 7 8 9

1 2 4 5 7 8 10

1 2 4 6 8 9 10

1 3 4 5 6 7 9

1 3 4 5 7 8 10

1 3 4 6 7 9 10

1 3 5 6 7 9 10

1 3 5 7 8 9 10

2 3 4 5 6 8 9

2 3 4 5 6 8 10

2 3 4 6 7 9 10

2 3 5 6 7 9 10

2 3 5 6 8 9 10

2 4 5 6 7 8 10

2 4 6 7 8 9 10

With CoverMaster you can test, optimize and transpose like this . . .

11 1... [ More ]

My current approach

Ramijami — Thu, 18 Oct 2012 10:20:25 GMT

Hi,

I play 5/45 PowerBall and 6/49 Lotto and have looked at the right digit/end digit (e.g. 10 would have a right digit 0 and 23 would have a right digit 3) as a way of selecting numbers, and using 7 per set (as a starting point). Using 7/10 right digits, there are a total of 120 sets, and I have narrowed it down to the following 18 which give good results in my games (for both 5 and 6 number games):

1, 2, 3, 4, 5, 7, 9

1, 2, 3, 5, 7, 9, 10

1, 2, 4, 5, 6, 8, 9

1, 2, 4, 5, 6,... [ More ]