3 pairs...

Reply #34

ranman17 — Thu, 21 Feb 2013 18:09:22 GMT

Congratulations!....Are you talking about the On the Road to a P3 Str8 program

Reply #33

TMONEY312 — Thu, 21 Feb 2013 17:41:39 GMT

I just want to say I downloaded the excel program and along with my workout I got a straight hit in ny mid day I was just testing it out . 836 str8

Reply #32

ranman17 — Thu, 21 Feb 2013 16:50:03 GMT

OK, I will give that a try and let you know what happens. Thanks

Reply #31

Rakster — Thu, 21 Feb 2013 16:47:56 GMT

Sort them from highest to lowest.

Then create a pyramid using both highest to lowest in one pyramid then lowest to highest in the other.

Create 3 digit numbers from pyramids... look for pairs that appear the most often...

Reply #30

ranman17 — Thu, 21 Feb 2013 16:22:20 GMT

OK, now when you have a chance and if you are so inclined can you take me through the next step

Reply #29

Cierra — Thu, 21 Feb 2013 16:04:22 GMT

what state these plays are for

Reply #28

Rakster — Thu, 21 Feb 2013 16:01:09 GMT

By George I think you've got it

Reply #27

ranman17 — Thu, 21 Feb 2013 15:54:29 GMT

I've got it now.

1 - 269

2 - 872 = 2

3 - 858 = 6

4 - 579

5 - 264

6 - 899 = 6

7 - 505

8 - 711

9 - 138 = 9

10 -516

Total = 23

Reply #26

ranman17 — Thu, 21 Feb 2013 15:43:10 GMT

I guess I'm not that sharp. I thought that since there is one 8 across from the 2 that would be 2 points and there are 2 8's across from the 3 so I thought that would be 24 points (8*3), etc. I guess I got it wrong.

Reply #25

Rakster — Thu, 21 Feb 2013 15:41:27 GMT

your mutiplying them by 3... you ADD them by 3

Reply #24

Rakster — Thu, 21 Feb 2013 15:39:09 GMT

look at previous reply

Reply #23

ranman17 — Thu, 21 Feb 2013 15:38:07 GMT

Wouldn't it be 2 for 872, 24 for 858, 6 for 899 and 9 for 138?

What did I do wrong

Reply #22

Rakster — Thu, 21 Feb 2013 15:35:03 GMT

total value for 8 is 23

2 points in 872

6 points in 858..... its acroiss from #3... so 3 points for each 8 here

etc...

total value for 2 is 8.. .thats correct.

Reply #21

ranman17 — Thu, 21 Feb 2013 15:33:39 GMT

OK, so the total value for 2 would be 8, and the total value for 8 would be 41 correct

Reply #20

Rakster — Thu, 21 Feb 2013 15:26:46 GMT

you have your values 1 to 10 stacked... beside each of these you stack your last 10 days

like this...

if a 1 appears in numbers across from 8 then give it 8 points... since there are 2 ones in 711 it gets 16 points bc its across from 8. Do this for every digit.

total value of 1 is... 35... 16 points for 711, 9 points for 138, and 10 points for 516.... do this for each digit

1 269

2 872

3 858

4 579

5 264

6 899

7 505

8 711

9 138

10 516

Reply #19

ranman17 — Thu, 21 Feb 2013 15:11:08 GMT

Can you give an example of a short stack and their values

Reply #18

Rakster — Thu, 21 Feb 2013 15:00:13 GMT

Sure, but its complicated as I use a few different systems to derrive at the final outcome.

I use a point total to give to each digit from 1 to 10... so you take the last 10 draws.... stack them up and give them their values.

I then sort them from highest to lowest in points.

I then run them thru a pyramid where the top of pyramid is LOWEST value to highest value

From here it generates 8 sets of numbers....

I do the pyramid again using HIGHEST value of numbers to lowest and genera... [ More ]

Reply #17

ranman17 — Thu, 21 Feb 2013 14:51:15 GMT

Rakster,

Would you consider sharing the method you use to arrive at your pairs

Reply #16

adobea78 — Thu, 21 Feb 2013 00:51:04 GMT

Chk this link https://www.lotterypost.com/thread/256775 , it might interest you

Reply #15

Rakster — Thu, 21 Feb 2013 00:46:39 GMT

great info... thanks

Reply #14

adobea78 — Thu, 21 Feb 2013 00:43:09 GMT

You have to factor in the risk in your waging strategy else you'll be chasing a shadow!. If you are confident about your generated pairs, then your x should be a second thought. The issue I presumed is the choice of the pairs, which of the pairs should be left out?. Supposing I have these pairs 12, 23,34, I may choose the pair 12 for 18 picks(12x and 21x, x=0-9) waging 50cent or 25cent str8 bets for $9 or $4.5(online). You have to study the frequencies of generated pairs and median time frame(ho... [ More ]

Reply #13

Rakster — Wed, 20 Feb 2013 23:58:04 GMT

I ran the top 5 HOT digits from each week and they have hit 10 of the 12 weeks so far... this week was not one of them :(

So this would eliminate half of the plays.... which is do-able I feel... cost... $18.50 a day... hmmm decissions.

Reply #12

Rakster — Wed, 20 Feb 2013 23:40:17 GMT

Interesting... thing is if I reduce my x to 2 digits I will play the wrong two... its what I do...lol

Reply #11

adobea78 — Wed, 20 Feb 2013 22:43:07 GMT

maintain the 3 pairs and reduce your x to max of 2 digits or reduce your pairs and increase your x.

Reply #10

ranman17 — Wed, 20 Feb 2013 21:12:22 GMT

You might have more luck looking at a week from the day the month starts rather than from Sunday. In other words if the month starts on a Friday it would end on a Thursday and begin again on Friday the 8th like this month did. So the start to each week would be a Friday rather than Sunday for the sake of entering numbers into your system.

Reply #9

Rakster — Wed, 20 Feb 2013 20:35:42 GMT

I back rested the CD pairs... 7 wins of the 12 weeks... so just over half the time it hits... but it sure would reduce the number of plays so something to consider.

So costs would reduce from a $37.50 a day cost to... $22.50 per day.... still a lot ... but if garanteed (nothing ever is...) a win a week... thats still a nice little profit every week..... espcially if one stops for the week once a hit comes in.

Reply #8

lakerben — Wed, 20 Feb 2013 19:39:36 GMT

Reply #7

Rakster — Wed, 20 Feb 2013 19:19:48 GMT

Thanks... will do

Reply #6

ranman17 — Wed, 20 Feb 2013 18:59:03 GMT

If the consec pairs don't work for you forget it. It was just an idea off the top of my head. All that matters is that your system produced a winner. I have a str8 system that might help you in someway, check it out and let me know:

https://www.dropbox.com/s/kfjcdjv5d4mq9rd/On%20the%20road%20to%20a%20P3%20Str8%20with%20P4%202_16_13.xlsm

Reply #5

Rakster — Wed, 20 Feb 2013 18:43:16 GMT

Western Canada's pairs are 01-04-14

Last night it hit 640

no consecutive...

Reply #4

Rakster — Wed, 20 Feb 2013 18:40:36 GMT

good eye

Reply #3

ranman17 — Wed, 20 Feb 2013 18:39:11 GMT

So the 67 looks good. Also, using midday to midday or eve to eve you might want to take a number (let's say from Sunday) and run it through a +1+2+3 rundown and see what consecutive pairs that produces and compare it to your pairs, maybe that would help.

Illinois Sunday midday was 981. Run it down like this:

9

8

1

0

0

4

1

2

7

2

4

0

3

6

3

4

8

6

5

0

9

6

2

2

Reply #2

Rakster — Wed, 20 Feb 2013 18:31:49 GMT

Thanks Ranman17...

Illinois midday pairs that should have a hit this week...

06-07-67

Reply #1

ranman17 — Wed, 20 Feb 2013 18:27:03 GMT

I'm just spit balling here but I can tell you that many many times the pick three contains consecutive pairs i.e. 01 12 23 34 45 56 67 78 89 90. You might want to remove from your results any non consecutive pairs.

Do a quick backtest and see if I am correct for your area. I hope it works for you. If I saw your workout I might be able to be more help as may others.

GL

3 pairs...

Rakster — Wed, 20 Feb 2013 18:05:30 GMT

I found something that WILL predict at least 1 of 3 pairs for that week....

My problem is this.... I like playing straights.... so each pair will cost $13.75 or $37.50 a day to cover online for a $225.00 win.

Any hit before 6 days is profit... 6 days its break even.... 7th day... well......

I back tested Western Canada and have had at least 1 hit the past 12 weeks... (3 months back)

Question is... how can I successfully reduce my number of plays without eliminating the winner