<?xml version="1.0" encoding="utf-8"?>
<rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/">
	<channel>
		<title>Pick 4 - add 0 to 9999 limit 10000 rows</title>
		<link>https://www.lotterypost.com/thread/289437</link>
		<atom:link href="https://www.lotterypost.com/rss/topic/289437" rel="self" type="application/rss+xml" />
		<description>Lottery Post Forum Topic: Pick 4 - add 0 to 9999 limit 10000 rows</description>
		<dc:language>en-us</dc:language>
		<generator>Lottery Post RSS Generator</generator>
		<item>
			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/289437/4109149</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4109149</guid>
			<pubDate>Sat, 16 May 2015 18:21:08 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>It was written in the very first comment.<br /><br />%=10000 per value<br /><br />% , mod and rest() are the same. In this case you could use right().<br /><br />x%=10000;<br /><br />Assign x mod 10000 to x.<br /><br />Basically:<br /><br />Dim x, y, z as Integer<br /><br />x = x + y<br /><br />x = x mod z<br /><br />int x,y,z;<br /><br />x+=y;<br /><br />x%=z;<br /><br />Same as by digit: x%=10;<br /><br />Of course you did x+=some_value;<br /><br />I need to do other things first. I supposed you all know your basic college mathematics.<br /><br />The rest is logic, there you fail.</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/289437/4109123</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4109123</guid>
			<pubDate>Sat, 16 May 2015 17:58:16 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>It&#x27;s simple when you know the Functions of each Box: We don&#x27;t!<br /><br />What&#x27;s needed: A description/explanation of how it works.</p>]]></description>
			<category>Raven62</category>
		</item>
		<item>
			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/289437/4109005</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4109005</guid>
			<pubDate>Sat, 16 May 2015 16:46:34 GMT</pubDate>
			<dc:creator>SkyLine69</dc:creator>
			<description><![CDATA[<p>Now that I checked it out, hmmmm I don&#x27;t understand LOL kidding thanks</p>]]></description>
			<category>SkyLine69</category>
		</item>
		<item>
			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/289437/4108932</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108932</guid>
			<pubDate>Sat, 16 May 2015 15:34:30 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>002 113 224 335 446 557 668 779 890 001 112 223 ...<br /><br />REST 2<br /><br />DIVISOR 111<br /><br />RECORDS: 1 to 9<br /><br />CONDITION: REC%11==2</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/289437/4108925</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108925</guid>
			<pubDate>Sat, 16 May 2015 15:18:43 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>It does the job you ask it to do. The length of the result depends of the input. Filters and extra functions would make it more complicated. Since the new record is the return of a rest function, the list stops before the first combination. You could start with a rest as combination, add a value bigger than the rest and only take the combinations = 9999. Since the program does not have a break, you get the list in the order of the calculations.<br /><br />Example:<br /><br />Divisor: 11<br /><br />Rest: 2<br /><br />Input comb... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/289437/4108925">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/289437/4108914</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108914</guid>
			<pubDate>Sat, 16 May 2015 15:06:57 GMT</pubDate>
			<dc:creator>lakerben</dc:creator>
			<description><![CDATA[<p>Cool!<br /><br />I&#x27;ll give it try here shortly for the morning draw. I&#x27;m experimenting with using digits from the root, width for the next draw.<br /><br />Thanks for the work</p>]]></description>
			<category>lakerben</category>
		</item>
		<item>
			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/289437/4108907</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108907</guid>
			<pubDate>Sat, 16 May 2015 15:00:38 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>Digits of combination Digits to add at each step<br /><br />You guess it with the first use.<br /><br />I could put comments, but it is so simple.</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/289437/4108903</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108903</guid>
			<pubDate>Sat, 16 May 2015 14:54:49 GMT</pubDate>
			<dc:creator>lakerben</dc:creator>
			<description><![CDATA[<p>Is the additive the first entry or the second one</p>]]></description>
			<category>lakerben</category>
		</item>
		<item>
			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/289437/4108900</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108900</guid>
			<pubDate>Sat, 16 May 2015 14:52:06 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>You better play with the tool instead of asking me.</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/289437/4108725</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108725</guid>
			<pubDate>Sat, 16 May 2015 11:27:45 GMT</pubDate>
			<dc:creator>SkyLine69</dc:creator>
			<description><![CDATA[<p>Serge,<br /><br />What is this about, can you explain or is this a way t get all the combinations of a P4</p>]]></description>
			<category>SkyLine69</category>
		</item>
		<item>
			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/289437/4108671</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108671</guid>
			<pubDate>Sat, 16 May 2015 09:45:12 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>The amount of rows is variable and depends of your input.<br /><br />If you add 0 0 1 to 0 0 0 for pick 3, you create 1000 rows ranging from 000 to 999.<br /><br />The added value cannot be negative here. To create -1 you have to add 999.<br /><br />I give two options for the addition:<br /><br />by position combination as value<br /><br />The first two systems are:<br /><br />separate start combination +/- 0|1 for each position separate start combination +/- user input for the specific position</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/289437/4108517</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4108517</guid>
			<pubDate>Sat, 16 May 2015 03:14:53 GMT</pubDate>
			<dc:creator>lakerben</dc:creator>
			<description><![CDATA[<p>What is the two limit rundown</p>]]></description>
			<category>lakerben</category>
		</item>
		<item>
			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/289437/4107779</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437/4107779</guid>
			<pubDate>Fri, 15 May 2015 16:54:40 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>For the systems above, you can now use negative values.</p>]]></description>
			<category>SergeM</category>
		</item>
		<item>
			<title>Pick 4 - add 0 to 9999 limit 10000 rows</title>
			<link>https://www.lotterypost.com/thread/289437</link>
			<guid isPermaLink="true">https://www.lotterypost.com/thread/289437</guid>
			<pubDate>Thu, 14 May 2015 22:44:52 GMT</pubDate>
			<dc:creator>SergeM</dc:creator>
			<description><![CDATA[<p>Link: Addition of a value between 0 and 9999<br /><br />Limit 10000 rows!<br /><br />Enter your first four digits or not.<br /><br />Enter your value to add, like 0023 = 23.<br /><br />%=10000 per value.</p>]]></description>
			<category>SergeM</category>
		</item>
	</channel>
</rss>

