pick3 20 groups digits

Reply #11

dr san — Wed, 02 Sep 2015 12:32:45 GMT

Hello past two pick 3 lottery example

456

178

Digits missing = 0,2,3,9 From here you choose pairs in 20 groups

Choose from 5th 6 Total groups 25.30 pairs and keep in 5.10 followed sweepstakes

Reply #10

dr san — Wed, 02 Sep 2015 12:13:23 GMT

Hello you can get 5-6 groups these 20 groups after seeing the latest statistics, 5.6 groups 25,30 numbers, .. and keep in a different sweepstakes as fixed Pair have to have repeating the last digit or digits who left not adding 2,3ultimos sweepstakes,

Reply #9

dr san — Wed, 02 Sep 2015 11:53:05 GMT

hello TIALU YES , YES. You have the couple in 5 or 10 ... sweepstakes, look for the missing couple

In 5.10 or more draws as soon as they saw him, thus joining factors or patterns

Delays and repetitions of a range of sweepstakes, (alias the dream of a lot) to have this control

Of number of past lottery, like pairs of repeat cycle.

Reply #8

Tialuvslotto — Wed, 02 Sep 2015 10:43:43 GMT

This pairs analysis would be useful with Adobe's straight method of finding the first number and playing with all 100 pairs.

Reply #7

dr san — Tue, 01 Sep 2015 23:10:58 GMT

Hello, hardly repeats the pattern of the last to close

Example in the last gave 211ou be more smaller, lower

Hardly 211 will repeat the same pattern of the last draw pick3

Reply #6

Lildarryl — Tue, 01 Sep 2015 21:34:23 GMT

good work

Reply #5

dr san — Tue, 01 Sep 2015 21:34:09 GMT

river, a friend can put in Excel 2010 or higher, so macro can generate the bet on the three patterns = greater and lesser same at every position of pick3 and also pick4, does a friend who knows excel help

Reply #4

dr san — Tue, 01 Sep 2015 21:31:00 GMT

hello river, you can do estatistiscas of 27 formations of major, minor and equal in 5,10,15 ..

the pick 3 lottery

to see late example, suppose that the formation 220 is delayed and the last draw

It was 456

then the digits of the 1st and 2nd positions seram all major base (last draw)

for the 1st = 5,6,7,8,9 and for the second = 6,7,8,9 already equals the third digit = 6

then we have 27 formations all possible formations, it is as electrocardiogram

high and low and equal in re... [ More ]

Reply #3

dr san — Tue, 01 Sep 2015 21:20:40 GMT

Hello, river, you can also reduce to 27 the three standards, major, minor and equal

Based on the last draw of pick3

0= is equal

1 = less

2 = higher

example

478 = last draw pick3

153 = close to 221

Below all possible formations of May, smaller and equal

0 0 0

0 0 1

0 0 2

0 1 0

0 1 1

0 1 2

0 2 0

1 0 2

0 2 2

1 0 0

1 0 1

1 0 2

1 1 0

1 1 1

1 2 1

1 0 2

1 2 1

1 2 2

2 0 0

1 0 2

2 0 2

1 0 2

1 2 1

2 1 2

2 2

Reply #2

river26 — Tue, 01 Sep 2015 19:48:32 GMT

good explanation

Reply #1

dr san — Tue, 01 Sep 2015 17:01:26 GMT

There are 100 pairs in Pick3 +

1 6 = 1

2 7 = 2

3 8 = 3

4 9 = 4

5 0 = 5

[which are the compressed numbers]

total 25 groups 100%

1, 1

1, 2

1, 3

1, 4

1, 5

2 ,1

2, 2

2, 3

2, 4

2, 5

3, 1

3, 2

3 ,3

3, 4

3, 5

4, 1

4 ,2

4, 3

4 ,4

4, 5

5 ,1

5, 2

5, 3

5, 4

5, 5

examplo 458 45 58= 5,3 45=4,5

pick3 20 groups digits

dr san — Mon, 31 Aug 2015 15:44:48 GMT

hello we can also split the 100 pairs in 20 groups of 5 each

And numbers them 01-20

01 02 03 04 05 = 01

06 07 08 09 10 = 02

11 12 13 14 15 =03

16 17 18 19 20 = 04

21 22 23 24 25 =05

26 27 28 29 30 =06

31 32 33 34 35 = 07

36 37 38 39 40 = 08

41 42 43 44 45 =09

46 47 48 49 50 =10

51 52 53 54 55 =11

56 57 58 59 60 = 12

61 62 63 64 65 = 13

66 67 68 69 70 = 14

71 72 73 74 75 = 15

76 77 78 79 80 = 16

81 82 83 84 85 = 17

86 87 88 89 90 = 18

91... [ More ]