Getting 20/40, you might just get four times 5/10 by Murphy's law, where all goes wrong anyway.

I did a quickpick version with 70 numbers, randomnly spread over 7 combinations, on my system page.]]>

There are 76,904,685 possible combinations of 8 in a pool of 40 numbers.]]>

Taking any 5 numbers from the first line and combining it with any 5 number from the second line in sets of 8, lowest to highest, no repeating number in any line we get 45 sets.This is true for all 8 number combinations made with any 10 numbers.

The more numbers you add to the total, the trickier it gets.

Taking 5 from line 1, 5 from line 2, 5 from line 3 and 5 from line 4 we have 20 numbers total.

Using any 20 numbers, lowest to highes... [ More ]]]>

I have the number 1-40 set as a normal keno board like so

1 2 3 4 5 6 7 8 9 10

11 12 13 14 15 16 17 18 19 20

21 22 23 24 25 26 27 28 29 30

31 32 33 34 35 36 37 38 39 40

I want to know how many sets of 8 numbers I can get from these 40 numbers. The conditions I wish to add to this to cut down the possibilities or bad numbers are:

at least 1 numbers from each line must be use and maximum of 5 numbers from each line will be used.

so]]>

Can't blame them.

You have 4 lines of ten numbers. Got it.

1 2 3 4 5 6 7 8 9 10

1 2 3 4 5 6 7 8 9 10

1 2 3 4 5 6 7 8 9 10

1 2 3 4 5 6 7 8 9 10

Now what do you want?

Do you want every number combination out of ten?

Do you want every 8 number combinations out of 20 (which would be 5 numbers from each of the four lines)?

Or do you want to know how many 8 n... [ More ]]]>

(1-10,11-20,21-30 and 31-40). How do we work out every combination possible to get 8 numbers while using a maximum of 5 numbers from each of the 4 lines. As 8 numbers will be chosen this means that on average 2 numbers from each set of 10 will be used to make up the 8 so if we set a maximum of 5 from each set of 10 then we should have it covered. I need to know every possible combination so what I mean is usually if I were to do it manually]]>