System Question

Reply #19

Tialuvslotto — Fri, 29 Jan 2016 17:14:50 GMT

You can always block him.

Reply #18

Tialuvslotto — Fri, 29 Jan 2016 17:11:19 GMT

These are historical values.

Reply #17

AllenB — Fri, 29 Jan 2016 17:11:06 GMT

Dude, you a warring me out. Do you ever get into the actual discussion or do you just drop your leaflets on coin toss, your server, over active filters? If I listen to you, I can't play.

Reply #16

AllenB — Fri, 29 Jan 2016 17:03:43 GMT

I have looked at this also. Columns in Excel set up to track hit % over Variable game blocks (number of games) have not yet found a way to predict from the array of percentages in the matrix. It looks like you may have a way that could work. Are the percentages you show above historical values or are you computing these by another formula.

Reply #15

SergeM — Fri, 29 Jan 2016 16:58:21 GMT

If you eliminate the wrong numbers, you end up with a smaller chance to win.

Say that you flip a coin, and you eliminate head while it turns out to be head, you killed your chance to win.

Reply #14

AllenB — Fri, 29 Jan 2016 16:51:05 GMT

Interesting. Not sure what you mean by N-String. My original question on this post was looking for an elimination processes. My example is just to illustrate one method. Any Process or formula can be used. The real question for me is when a process is only 10-15% successful in predicting a draw, is it also 85%-90% successful in predicting a number will not hit?

I know that just picking a number in a position has a 10% chance of being correct. The idea makes me think about a process where you

Reply #13

SergeM — Fri, 29 Jan 2016 14:25:54 GMT

Anything can happen.

All you could do is create some rule that you want to follow.

Flip a coin, what will be the next side up? Do you have a formula

Reply #12

mmx1 — Fri, 29 Jan 2016 13:34:26 GMT

A single digit longest out is the most interesting to me too besides longest out doubles.

In this table are longest outs ready for today. If 1 dig has been out for more than 20 draws the chances are very high, but be aware that it could take up to 40 draws to show up.

Mor(xx1) Mid(xx2)

State 1 Dig Pairs Double Pos1 Pos2 Pos3 ShortΣ RootΣ

CT2 57-182

IL2 4-61

NC2 1-58 2-67

TX1 4-71

Eve(xx3) Ngt(xx4)

State 1 Dig Pairs Double Pos1 Pos2 Pos3 Short... [ More ]

Reply #11

Tialuvslotto — Fri, 29 Jan 2016 12:26:58 GMT

This is an interesting question, AllenB, and one worth pursuing. The problem for me is that all my spreadsheets are set up backwards , i.e. looking for what will hit!

One place that I would look for a number that will not show is among numbers that have not been hitting recently. If a digit has not hit for 7 games there is a 73% chance that it will not hit in the next game and a 27% chance that it will hit. These streaks continue to decay at 27% per game, with the average streak being 2 games... [ More ]

Reply #10

DELotteryPlyr — Fri, 29 Jan 2016 11:49:16 GMT

Great discussion and idea! I agree with amber123 as I often JUST miss by one digit. But when I go 'all in' on a 2 digit chase, it still doesn't work.

Reply #9

amber123 — Fri, 29 Jan 2016 04:12:11 GMT

The only issue I see right now is that ALL of the pick-3 numbers have to be wrong for this to work. Speaking for myself, I can predict two out of three numbers correctly, a good portion of the time for Florida. Mybe it's that elusive third digit we should track.

Reply #8

adobea78 — Fri, 29 Jan 2016 03:25:31 GMT

Why not find a process that generates N-string based on current draw?. N is the size of the string.

If the next draw has 'no anchor', then find a process to simulate the pool(0 through 9) for forward-testing.

Reply #7

AllenB — Fri, 29 Jan 2016 02:29:31 GMT

Another possible eliminator. The Percentage of hits for a difference from -3 to +3 is 90%. Probably because most averages are in the middle part of the numbers (0-9). Adding or subtracting 4 or 5 to the average may also be an effective eliminator.

Reply #6

AllenB — Fri, 29 Jan 2016 02:09:46 GMT

Table Showing Average of 3 Previous picks by position compared to next draw

0 in the Dif column is a match. Percentages of no match is 84% to 85%.

Average over Previous

N1

N2

N3

N4

3

Dif

+

-

Dif

+

-

Dif

+

-

Dif

+

-

*

0

15%

*

0

16%

*

0

14%

*

0

16%

Games

1

16%

15%

1

16%

18%

1

16%

11%

1

12%

14%

200

Reply #5

mmx1 — Fri, 29 Jan 2016 01:20:31 GMT

Can you clarify your method by posting an example

Reply #4

AllenB — Fri, 29 Jan 2016 01:13:16 GMT

Thank You. I will study this and add it as a step in my elimination-inclusion process.

I have been looking at the average of the last 3 picks for each position of the next draw. In about 90% of draws this average number is not selected. The results show the percentages for the difference between the average and the actual draw. 0 means a match. I am also tracking when this match occurs to try to use it either as an inclusion or as the selection.

Reply #3

mmx1 — Fri, 29 Jan 2016 00:12:07 GMT

You're in CA and here is one of my elimination / winning methods.

In the last 188 combined SINGLES draws it happened that a max two consecutive times 2 or 3 of digits 034579 were not in the draw. After two consecutive skips they have always showed up again. This evening we have this situation where 2 or 3 of these digits didn't show up in the last two consecutive SINGLES draws.

This wheel has 80 of 120 total SINGLES (every combo here has 2 or 3 of digits 034579):

013 014 015 017 01... [ More ]

Reply #2

AllenB — Thu, 28 Jan 2016 21:47:02 GMT

The Later. I'm trying to eliminate some numbers by a series of eliminations. Not much different than just picking a number at random that won't hit, but with a system that calculates the miss by a consistent formula or process.

Reply #1

GoogilyMoogily — Thu, 28 Jan 2016 21:26:45 GMT

Let's take the daily 3. Typically, one may try to find the 3 most likely numbers to hit. Are you asking for a formula to find the 7 least likely numbers to hit? Or, are you asking to eliminate one unlikely number which leaves you to pick 3 out of 9 with some confidence

System Question

AllenB — Thu, 28 Jan 2016 21:12:44 GMT

A formula or process, produces a number or a second formula that equals a number. If that process is only successful 10% of the time is it 90% capable of predicting the number will not be next? Could a few of these eliminate numbers from the next draw effectively

I know the process of formula is anchored in the past. The next draw has no anchor; but, if you could add this negative prediction to your other process results could you weed out losers