How often P3 digit repeats on top next draw?

Reply #36

dr san — Fri, 11 Mar 2016 02:59:47 GMT

Hello ok then we have 3 conditions (standard) odds

Repetition of a digit, the digit position of the highest or the lowest digit

And the position of the central digit.

Reply #35

Wisconsin3054 — Fri, 11 Mar 2016 00:09:35 GMT

I think the answer would vary depending on what number is the highest digit. The lower the highest digit, the lower the probability it both repeats and remains the highest digit.

Reply #34

dr san — Fri, 11 Mar 2016 00:01:34 GMT

ok yes ,yes, perfect

Reply #33

Wisconsin3054 — Thu, 10 Mar 2016 19:38:19 GMT

All of it really. Are you asking the probability of a repeat of the highest digit in the same position and that it is still the highest digit in the draw

Reply #32

dr san — Thu, 10 Mar 2016 19:31:33 GMT

Hello,Wisconsin3054 what part do not you understand? On the higher digit positions or lower digit in the draw for the pick 3

Reply #31

Wisconsin3054 — Mon, 07 Mar 2016 23:18:16 GMT

I'm sorry dr san, I'm not really understanding what you are looking for here

Reply #30

dr san — Sat, 05 Mar 2016 12:50:27 GMT

Hello, wisconsin, also the probability of the biggest digit Retry in position? Example = 478 the highest digit is 8 in 3rd place

Next he gave = repeated a digit the digit 8 and 8 is the largest digit but gave in 2nd position We may see the lowest I type too? Positional pairs form the largest less example

1.2 1.3 2, 3 with the highest and lowest Example 478 gave the pair the pair = 4.8 1.3 Positional Calro knowing then that the third digit is between 4 and 8 and in 3rd place. Very good

Reply #29

SergeM — Thu, 03 Mar 2016 19:14:37 GMT

- homepage - daily 3 - last 10 - button repeaters

Look at it

Reply #28

Wisconsin3054 — Wed, 02 Mar 2016 02:19:13 GMT

Eh.. I dont go that far with it. The fact is that the chance of a repeat is the same as the chance of predicting the result. When you look at repeats, you are effectively picking the same number as the last draw for the next draw. Your chance of getting at least one number in the correct position is 27.1% with either the same numbers or new numbers. The only way the odds are much different is if you are trying to predict the repeat before the first of the two draws.

Reply #27

hypersoniq — Wed, 02 Mar 2016 01:41:20 GMT

1 in 10 for a repeat in any position, if a repeat is what you are favoring.

1 in 100 for doubles to repeat on the next draw in the same position.

for three single repeats, 1 in 10 twice, not 1 in 100, but 2 separate events of 1 in 10.

No need to get any fancier than that. if they draw a 7, there is one chance the next draw to get a 7, 9 chances to NOT get a 7.

Reply #26

dr san — Sat, 27 Feb 2016 21:35:17 GMT

ok perfect=, 27% then 73% are not repeated. the repetition of the condition of a digit in the last draw for the next is better not to play in the same position position are 73% / 27%

The best thing is to play not repeating the position

Reply #25

Wisconsin3054 — Sat, 27 Feb 2016 19:53:27 GMT

I believe each line would have a 1 in 10 chance of repeating. The chance of one or more repeating in the same position would be:

1-(.9*.9*.9) as a percentage. 27.1%.

Reply #24

dr san — Sat, 27 Feb 2016 19:28:00 GMT

Hello tucker, how likely repeat a 1 digit of the previous draw in the same position

Example

478

Next draw gave 158 repeated the digit 8 in the same position

Reply #23

Tucker Black — Fri, 26 Feb 2016 20:04:17 GMT

The probability of one of the three digits from the last draw being in the next draw depends on whether the previous draw had 3 distinct digits, 2 distinct digits, or just one (e.g., 555). If it's 555, then the probability the next draw will have a 5 in it is 1-0.9^3=27.1% (a bit less than 3/10 because the result could have 2 5's or 3 5's). 2 distinct digits is more likely, and 3 is even more likely.

Because probability theory only works for future events, let's calculate the probability of t... [ More ]

Reply #22

Wisconsin3054 — Tue, 16 Feb 2016 16:46:44 GMT

This is the mathematics forum. The OP was inquiring how the math looks in various circumstances and my point was to try to answer those questions.

Reply #21

lakerben — Tue, 16 Feb 2016 03:20:41 GMT

What's your point? Nothing anyone had spent too much time explaining to you does any good. Why not play the way you prefer instead of all the verbage

Reply #20

Wisconsin3054 — Tue, 16 Feb 2016 03:02:19 GMT

IMO, your best chances according to the odds are the same no matter what the last draw was. Picking singles is twice as likely to hit as doubles if you are playing box because there are twice as many ways the singles can be arranged. Of course, generally, you win twice as much on the double. So, half the chance, double the reward.

Reply #19

Edibs3 — Mon, 15 Feb 2016 19:37:25 GMT

because your proposed strategy started with assuming that there is a repeat in the next draw and that it is a double.

Oh well, the attempt was to show both sides using 2 demos and present both ways. Will it have a repeat digit next or not?

Will it, or will it not be a double or single? Which one of the options have the best chances to win according to the odds?

The example of 012 was an arbitrary choice. However, the subsequent options/odds shown in the 2 demos were valid. Regardle... [ More ]

Reply #18

Wisconsin3054 — Mon, 15 Feb 2016 18:01:51 GMT

Past history was part of your demo, because your proposed strategy started with assuming that there is a repeat in the next draw and that it is a double. With the assumption, you are basing your pick selection on that last draw, in some kind of attempt to improve your odds for the next draw.

TBH, I'm having kind of a difficult time getting to what your points are in some of your posts, so it is difficult to respond to it all either agreeing or disagreeing.

Reply #17

Edibs3 — Mon, 15 Feb 2016 17:33:53 GMT

Past draw history wasn't part of the demo at all, so it was confusing when mentioned.

Everything up to now has only been about ODDS and how to best use those odds.

The only draw history used here so far has been, sometimes its a double, and sometimes it's a single. 72%,27%,1%

The odds and payouts of Pick 3 are not good, but we have to know what they are. We have to make the best of them, and play within those limits.

Odds are hard facts and they never change regardless of past... [ More ]

Reply #16

Wisconsin3054 — Mon, 15 Feb 2016 02:17:16 GMT

I was just expressing my own opinion. It doesn't take long to realize that many people on here believe that past results do affect future results. Maybe they are right. I was just making clear my belief so as to explain my reason to be sceptical of buying in to your theory. That way you can discount my scepticism if you so choose for the right reason.

I'm not trying to be dismissive, but this is the mathematics forum so I feel like I should be able to counter a theory using math. The math sim... [ More ]

Reply #15

Edibs3 — Sun, 14 Feb 2016 16:48:19 GMT

What would you consider a good gamble?

Gambling by it's very nature is assumption and risk.

My view of Reality The House odds are the stricter reality.

The State government's Pick 3house odds and payouts are worse than bad.

Their game and their rules, but that's the gambler's reality.

The house odds are just like Aunt Bee's pickles. Like sheriff Andy Taylor says, we just have to learn to love em' .

Gamblers start at the top of those odds and attempt to work their way down... [ More ]

Reply #14

Wisconsin3054 — Sat, 13 Feb 2016 22:58:33 GMT

Your first problem is getting to the point where you could assume that one of the numbers will repeat and assume that it will be a double. If you somehow knew that would happen in advance then yes, you have improved your odds with a filter. However, my view of reality is that the past draws do not affect the future draws, so I am not sticking down 42, 48, 126, or 144 plays in a single draw based on the initial assumption.

Reply #13

Edibs3 — Sat, 13 Feb 2016 18:56:44 GMT

Then again, we could bet the other half of the coin. Instead of 48 we could go with the opposite42 boxes below. This other half is a little bit cheaper.

No return digits from the previous draw 0,1,2

#42 box

334, 488, 668, 677, 335, 344, 399, 588, 669, 336, 499, 688, 778, 337, 355, 445, 599, 779, 788, 338, 446, 455, 699, 339, 366, 447, 799, 889, 448, 466, 556, 899, 377, 449, 557, 566, 477, 558, 388, 559, 577, 667

or --these 126 straight versions of those box up there.

334,... [ More ]

Reply #12

Edibs3 — Sat, 13 Feb 2016 17:02:29 GMT

Thinking out loud. In general terms at first ok?

As we are waiting for the next double just about to hit we can prepare to do the following:

$$ We can assume at least ONE of the 3 digits {0,1,2,} will repeat in the next draw today, and it will be a DOUBLE.

The odds of our being right are these 48 of the 90 total boxes below. Playing all/or part.

055, 118, 226, 244, 299, 001, 119, 155, 227, 002, 011, 066, 228, 255, 003, 166, 229, 004, 022, 077, 112, 266, 005, 113, 122,

Reply #11

Wisconsin3054 — Sat, 13 Feb 2016 15:38:07 GMT

I thought of one thing that complicates this a little bit, but I don't have the time at the moment to try to do the math on it.

The above math is based on the preceding draw having unique digits, ie. no doubles, triples, quads.

When you factor those in the overall daily percentage probably goes down a little bit.

Reply #10

Wisconsin3054 — Sat, 13 Feb 2016 15:32:57 GMT

Do you have long term results to show that it proves out? What we have shown above is that when you are only dealing with 10 digits, the chance that one of those digits, especially if you are looking at all positions, will repeat, that is just math not a pattern. There is no way to predict which number or numbers will repeat nor what position they will repeat in. I may not be great at this, but I believe the math looks like this:

1-(.7 X .7 X .7) = 65.7% chance of at least one repeat looking

Reply #9

Lucky Loser — Sat, 13 Feb 2016 07:04:52 GMT

Hey guys, here's a link to a discussion on this very same topic about nine months ago. I tried my best to establish the validity of using a system based on this approach but, the OP of the topic felt otherwise. Since then, this same method has continued to prove out...and always will. The topic is called 'Indicators' and I hope it helps.

https://www.lotterypost.com/thread/289701

Reply #8

Wisconsin3054 — Fri, 12 Feb 2016 19:05:56 GMT

Repeats in a particular position are 1 in 10 odds so 3 per month per position should be considered normal. Odds of a 3-peat in a particular position would be 1 in 100. So on average 3-4 times a year would be expected. The 4-peat goes to 1 in 1000 odds so expected once every 3 years or so I would say.

Remember these are odds for each line though so the odds that it occurs in one of the three lines is better.

Reply #7

Edibs3 — Fri, 12 Feb 2016 18:39:55 GMT

Seemed as if we were getting an average of around THREE 1st position repeats per month for evening draws.

It also looked like the same for the other 2 positions in general.

What would that look like using the correct math averages for each position per month?

Secondly, what would 3 like digits in a row look like odds wise? Ever seen 4 in a row?

Sure glad we have good help on these odds/probability questions here and willing to share it with the earthlings. Thanks

Reply #6

Wisconsin3054 — Fri, 12 Feb 2016 16:46:04 GMT

Good catch. I was thinking of there being at least one repeat as opposed to only one. Better to be precise though when we are talking math

Reply #5

KY Floyd — Fri, 12 Feb 2016 07:56:38 GMT

The chances are even better that one of the three numbers will repeat: 1-(.9X.9X.9)=27.1% chance, so a little over 1 in 4.

Just to expand on that a bit, and add either a correction or a clarification: Figuring out the probability of something happening often requires figuring out the probability of the alternative not happening. The chance of not having the first digit match is 9 in 10, so the probability is .9. The probability of not matching the first or 2nd is .9 * .9 = .81. For also not

Reply #4

Wisconsin3054 — Fri, 12 Feb 2016 04:18:17 GMT

Yes, I think when you see the repeating digits they stand out, but the reality of the numbers as I showed is that in about one in four draws there will be a repeating digit in one of the lines. Turns out its just the math and I don't think it makes for a pattern that would help with predictions.

Reply #3

Edibs3 — Fri, 12 Feb 2016 00:35:41 GMT

Thanks Wisconsin3054! A lot times the stats just don't seem to sync up with current reality.

So much so, that you start to question long-held beliefs. We need to revisit these every once in awhile just to knock down the cobwebs.

These repeating digits have always seemed sort of a flimsy trend but they may be underrated after all.

The longer I'm around the more POSITIONAL repeat digits seem to hold interest. Playing more straights lately has done it.

Reply #2

Wisconsin3054 — Thu, 11 Feb 2016 19:59:46 GMT

It really depends on your point of reference. If you are saying predicting before the first draw that a particular number will appear in the same position on the next two draws, then the odds are 1 in (10X10) 100. 3 draws 1 in (10X10X10) 1000. If you are predicting after the first draw that in the next draw a particular number will appear in the same position as the last draw it would be 1 in 10. The chances are even better that one of the three numbers will repeat: 1-(.9X.9X.9)=27.1% chance, so... [ More ]

Reply #1

Edibs3 — Thu, 11 Feb 2016 19:30:53 GMT

Come on and give a fella' a break Math Masters! Will work for Math Tips.

What are the correct P3 odds for a like digit to hit directly on top of yesterday's draw? How about 3 in a row? Thanks for any help around the return of like digits and the odds.

986

912

993

How often P3 digit repeats on top next draw?

Edibs3 — Wed, 10 Feb 2016 18:55:44 GMT

Little help showing the correct P3 Math average for one digit to repeat on top of itself from the last drawn digit .

Include doubles and then just single to single only as well. Thanks

1 n 10 odds for each draw that the same digit will repeat on top of itself correct ? 1/10 x1/10 seems too much.