(New member) Have any of you broken down a keno game?

Reply #53

alsports2000 — Sat, 03 Jun 2017 01:33:14 GMT

THANK YOU SO MUCH FOR TAKING THE TIME TO RESPOND. I ONLY PLAY THE EIGHTY NUMBERS KENO. WHERE CAN I FIND THE RESULTS FOR THIS GAME???. THANKS. AL

Reply #52

Novan60 — Fri, 02 Jun 2017 04:15:59 GMT

You do realize there is not going to be a universal set of numbers that will apply to all Keno games. Every game will have a different set of most common numbers and the only way to get that information is to look at the results for that specific game.

Reply #51

alsports2000 — Fri, 02 Jun 2017 02:27:17 GMT

Well you did not give it to me the way i wanted either but i have to thank you so so much for even taking the time to respond. Yes its not what I wanted to hear but its an ongoing search for the ten most drawn combination numbers in an eighty number keno...Thanks again...AL.

Reply #50

Novan60 — Thu, 01 Jun 2017 06:51:17 GMT

Pick 3 is basically 1 in 1000. 3 digits 0 to 9. Pick 4 is 1 in 10,000, 4 digits 0 to 9. The odds are fairly straightforward to calculate, if 1 digits is fixed in P3 there are then 100 combinations where that 1 digit appears. There are additional calculations for box versus straight or odd versus even. The problem with those games is that the payout isn't enough to make winning worthwhile.

Reply #49

Novan60 — Thu, 01 Jun 2017 06:35:34 GMT

Actually depending on how you have the data stored it can be accessed using a simple query like this:

Select d1,d2,d3,d4, count(*) as Drwings, min(d1.Drwing) as FirstDrwing, Max(d1.Drwing) as LastDrwing from

(Select drwing, N0 as D1 from tblWinDigits ) as D1

inner join (Select drwing, N0 as D2 from tblWinDigits ) as D2 on D2 D1 and D1.drwing = D2.Drwing

inner join (Select drwing, N0 as D3 from tblWinDigits ) as D3 on D3 D2 and D3.drwing = D2.Drwing

inner join (Select drwing, N0 a... [ More ]

Reply #48

Datapile — Thu, 01 Jun 2017 03:42:41 GMT

alsports2000 you're about to understand what my wife means when she says You almost always give me what I want, but never the way I want it!

Sure, I can answer your question, but you won't like it...

(This is out of over a 1.45 million drawings, btw...)

Perhaps you want the lower numbers...

N1 N2 N3 Count Chance

1 2 3 20201 1.39%

1 3 4 15729 1.08%

1 2 4 15668 1.08%

2 3 4 15565 1.07%

Maybe you want the middle 4 numbers...

N9 N10 N11 N12 Count Chance... [ More ]

Reply #47

Datapile — Thu, 01 Jun 2017 03:08:11 GMT

dr san I don't know those games... Tell me how they work, and I would be happy to do a work up for you, Sir.

Reply #46

alsports2000 — Thu, 01 Jun 2017 02:59:02 GMT

ALL I WANT TO KNOW IS: WHAT COMBINATION OF NUMBERS HAVE BEEN DRAWN THE MOST IN A 80 BALL KENO???. I UNDERSTAND RANDOM BUT DOES ANYONE HAVE THE AVERAGE NUMBER OF TIMES THAT A CERTAIN COMBINATION OF NUMBERS HIT THE MOST OFTEN?. THANKS SO MUCH AND I DON'T MEAN THIS IN A SARCASTIC WAY....THANK. YOU.

Reply #45

dr san — Wed, 31 May 2017 15:10:07 GMT

Hello datapile, can you make the PICK 3 AND PICK4 PROBABILITIES table

Reply #44

Datapile — Tue, 30 May 2017 23:45:57 GMT

Hey Novan60 !!

Care to try a trip down the rabbit hole??

Sudoku has over 27,000 times more possiblities than Keno... 5 Years ago a simple Blackberry could solve an ultra hard Sudoku puzzle in less than 10 seconds.

The only difference is that a puzzles rules are designed for a clear outcome...

We've been looking at the same thing different ways, so why don't you join me and let's make some rules in the Systems section?

https://www.lotterypost.com/thread/312911

Reply #43

Novan60 — Mon, 29 May 2017 19:47:14 GMT

I've been spending a lot of time on this over the last 6 months and in the end regardless of what method I choose the problem is consistently getting past 6 digits with any kind of reliability. The conditions that allow me to isolate 6 matching digits simply do not occur often enough in the remaining 4 digits (I am only concerned about matching 10 out of 10) to establish any kind of affordable playing strategy.

The best I've been able to do is about 40% consistency when simulating playing 500... [ More ]

Reply #42

dr san — Sat, 27 May 2017 01:18:50 GMT

Hello, very good work are 45 pairs, well we can when playing use of minimum of one and maximum of 3 pairs polindronos

My lottery has a prize pool of 15,16,17,18,19,20 = it has 6 prize money

Reply #41

Datapile — Sat, 27 May 2017 00:28:24 GMT

dr san unfortunately, it doesn't work. For your game:

There are 44 possible palindromes.

The chance of any number is 20% the chance of any 2 numbers being drawn is 20% * 20%= 4%. The average number of sets drawn will be 50*4%=2 pairs.

In the sample you posted above.

02 07 09 12 23 25 34 35 45 46 48 51 53 57 62 74 76 80 88 90 2

07 08 11 18 23 25 26 34 38 40 42 43 51 58 70 72 85 93 94 97 2

05 09 15 24 27 36 39 40 50 52 54 55 60 63 66 69 73 75 82 96 3

03 05 11 13 21 23 24 32... [ More ]

Reply #40

dr san — Fri, 26 May 2017 12:40:11 GMT

Hello datafile and novan ok on your 80/20 lottery we have 27 pairs of polyindromes (inverted digitios)

Rarely, it is drawn to doubles

An example

32,23 or is drawn 23 or 32 times the two together and thus with the remaining 27 pairs

Can make the table of 27 pairs polindromos (capicuas) and see how many doubles is drawn

Example if playing 25 do not play 52

01 10

02 20

03 30

04 40

05 50

06 60

07 70

08 80

12 21

13 31

23 32

14 41

15 51

24 42

Reply #39

dr san — Fri, 26 May 2017 11:16:15 GMT

hello draws 100/20

02 07 09 12 23 25 34 35 45 46 48 51 53 57 62 74 76 80 88 90

07 08 11 18 23 25 26 34 38 40 42 43 51 58 70 72 85 93 94 97

05 09 15 24 27 36 39 40 50 52 54 55 60 63 66 69 73 75 82 96

03 05 11 13 21 23 24 32 33 39 46 47 49 60 73 74 79 86 93 94

03 04 05 06 16 19 28 35 44 45 54 55 60 61 78 80 86 87 90 93

21 39 40 43 63 66 68 70 72 73 76 77 80 87 90 91 94 95 97 98

04 06 17 22 24 31 33 39 54 59 63 66 75 80 83 92 94 95 97 00

09 11 14 20 24 26 27 29 34 38 43 44 4... [ More ]

Reply #38

dr san — Fri, 26 May 2017 11:14:00 GMT

Hello ok DATAPILE very good job, perfect, I'll post a list of the last 30 draws of my lottery, 100/20 (lotomania) but the table works perfect

Reply #37

Datapile — Fri, 26 May 2017 01:02:10 GMT

dr san I didn't see a way to pull the historical data from the game's website, but here is the order derived from the probability table above. The first row has the highest chance per slot, followed by the second, etc. You can compare this to your past draw results, and find a rough idea of how your game behaves.

The 'Apex' number on the left most column is the rank of its chance to come out.

ApexListFull

Apex S1 S2 S3 S4 S5 S6 S7 S8 S9 S10 S11 S12 S13 S14 S15 S16 S17 S18 S19 S20... [ More ]

Reply #36

dr san — Fri, 26 May 2017 00:09:40 GMT

Ok datapile thanks but how can i

Cross a search algorithm of the best percentage in each position but a lot of variant, let's assume that half of the 20 or ten numbers is drawn within the average of the highest percentage how to do this

Reply #35

Datapile — Thu, 25 May 2017 04:49:57 GMT

dr san My profound apologies for not answering you sooner!

Yes, the concept will still work.

Here are the chances for each number in each location for 20 numbers drawn out of 100.

N1 N2 N3 N4 N5 N6 N7 N8 N9 N10 N11 N12 N13 N14 N15 N16 N17 N18 N19 N20

1 0.20000000000000

2 0.16161616161616 0.03838383838384

3 0.13028241599670 0.06266749123892 0.00705009276438

4 0.10476317987364 0.07655770836920 0.01744352848918 0.00123558326798

5 0.08402880052365 0.08293751739996... [ More ]

Reply #34

Datapile — Sun, 21 May 2017 21:31:29 GMT

Using the pool of 10 table above, I can say (with reasonable certainty) that if I pick 10 random numbers from a pool of 80, I can expect 0-6 of them to be correct.

This will hold true 99.82% of the time or put another way:

Total sub-pools of 10 from pool of 80 1,646,492,110,120

In range 0-6 1,643,528,424,322

out of range 2,963,685,798

If I look at 8 non-overlapping pools (1-10,11-20,...,71-80), I can predict that each one of them will still fall within 0-6 numbers drawn... [ More ]

Reply #33

Datapile — Sun, 21 May 2017 20:55:42 GMT

I've looked looked at it, but I use it as a limiter instead of a method to generate numbers to play...

Over\under 40... Every (99.62%) draw sequence will have between 5-15 over\under 40.

As odd\evens also have 40 number pools, the curves(chances) are the same.

Pool of 40 Chance

0 0.00%

1 0.00%

2 0.00%

3 0.02%

4 0.16%

5 0.75%

6 2.52%

7 6.35%

8 12.15%

9 17.88%

10 20.32%

11 17.88%

12 12.15%

13 6.35%

14 2.52%

1... [ More ]

Reply #32

Novan60 — Sun, 21 May 2017 19:32:52 GMT

I've looked at odd/even, over 40, under 40, pairs, dividing the base of 80 by 4, 5 and 8 and still wind up back in roughly the same space. The methods that have worked best for me have typically involved converting the numbers to their binary values or an integer and limiting the number of picks that I have to make.

Reply #31

DownandDirty — Mon, 15 May 2017 03:42:02 GMT

I play and analyze the NY Pick 10 every day for years now. You have found a highly analytical (and way over my head) way to figure out the things I already know....and can put in to much more simplistic terms.

Sadly, you may find that while data can put you in the right direction sometimes, it can point you in the wrong direction too.

I am convinced that you need to employ several methods for each draw. I have many I have developed. I try to use them all. My limitation is the budget needed... [ More ]

Reply #30

Datapile — Thu, 27 Apr 2017 02:23:35 GMT

I look at it like behavior analysis- If I know what it acts like, the limits of what it will do in any given situation, then I can predict it.

Reply #29

Datapile — Thu, 27 Apr 2017 02:04:34 GMT

It's been years since I played frequently. When I do, I buy 20 tickets.

I built my first prototype when I was downsized at the age of 31. It was all duct tape and staples but it ran without crashing. One night I played with $20 of birthday money I had been saving. 19 of the tickets won for a total of $750. (1 for 8,3 for 7,15 for 6). If every person on the planet bought 1,000 packs of 20 tickets, 1 would be like mine was. Tens of Thousands would jackpot.

The next night, I was set- played 1... [ More ]

Reply #28

Novan60 — Thu, 27 Apr 2017 01:29:10 GMT

My gut says that you are much better at math than me so in that you have an advantage. I've just learned what math I needed to as I went along and have spent countless hours brute forcing my way through an equation that could have taken someone else minutes to figure out. I like to say that when I first started I was basically doing the computer equivalent of counting on my fingers. In some cases I may very well still be.

My motivations for posting were very similar to yours as normally I am... [ More ]

Reply #27

Datapile — Thu, 27 Apr 2017 00:11:00 GMT

Novan, I think I need to explain my intentions a little better before we continue with our chats.

I came here to listen to different perspectives on the goals we share, but I didn't want to come to the party empty handed. So I've shared the more interesting things that I have found, on the off chance anyone hasn't seen them before. It is my hope that some of you find it more interesting than '7 is the most common number in every lottery so you should always play that'. In looking at your SQL... [ More ]

Reply #26

Novan60 — Wed, 26 Apr 2017 03:39:01 GMT

You missed my point and the example that you point to is a perfect example of what I am trying to say. They were not able to figure out exactly what house the perp lived in, just the general neighborhood.

It is the same way with the numbers, you can get in the right neighborhood, you just aren't going to get the house number, only in this instance we are not talking about a couple of thousand homes, we are talking about millions of subset combinations.

Also as I have said before if I play... [ More ]

Reply #25

Datapile — Wed, 26 Apr 2017 01:58:11 GMT

While I'm working out your posts, I have something different for you. Kim Rossmo is a Mathematician, and former Police Officer. He made a mathematical model to catch serial predators (rapists\killers). It doesn't work on all of them, but it does work.

Scenario: An intelligent predator lives somewhere (large city), and targets people at random.

Rossmo figured out that the majority while hunting would follow a few simple patterns:

Wherever they lived, they wouldn't hunt near their home t... [ More ]

Reply #24

Novan60 — Wed, 26 Apr 2017 00:04:05 GMT

https://www.lotterypost.com/thread/311275

https://www.lotterypost.com/thread/311108

These are other threads that you should check out if you have not already. In short what I did was to take all the number and rearrange them in a specific order 30 times.How the numbers are sorted matters because I went from averaging requiring 28 lines down to 23 by time I was finished exploring that method.

I would then split the numbers lines in 2 and then decide how many numbers from each side the wi... [ More ]

Reply #23

Novan60 — Tue, 25 Apr 2017 23:39:28 GMT

While identifying and understanding patterns is helpful, I would advise that you focus your energies on developing a method of picking within a given pattern. I spent a lot of time trying to find the optimum pattern so that I could have my computer make all my picks for me. What I found was that while some patterns may have offered better odds than just picking randomly from the big pool of numbers, in the end I still had to figure out the best way of making a 1 in X choice and that I was better... [ More ]

Reply #22

Sunglasses — Tue, 25 Apr 2017 23:21:13 GMT

20/70 pick 2 to pick 10 playable by forms with options for x days and x times.

There is no break down in odd/even, or low/high. You can play only low, or only high if you want to.

There is no wheel, just play 20 numbers spread over two pick 10's.

There is no size for everywhere, payouts differ. If I get 5000:-1 for 7/7, I can play that. If I get 3000 or less, I don't. ... Statistics? How much of that do you want? I stuff you

Reply #21

dr san — Tue, 25 Apr 2017 23:08:00 GMT

Hello,DATAPILE my keno lottery date, has 100 numbers and are drawn 20 numbers,

If you can play up to 50 numbers, it is possible to adapt unprovised in this study,

So it changes from 80 numbers to 100 numbers, the rest is the same

Reply #20

Datapile — Tue, 25 Apr 2017 23:05:21 GMT

If you track the MaxApex for all the drawings, and count them up, there is a pronounced ripple in the bell curve.

Query1

ApexMax CountOfApexMax

5 4

6 135

7 800

8 2625

9 7697

10 13329

11 26311

12 35075

13 48149

14 60791

15 61379

16 79221

17 70641

18 84230

19 70873

20 81632

21 73412

22 68138

23 65365

24 59848

25 56124

26 50017

27 43922

28 41364

29 37157

30 32049

Reply #19

Datapile — Tue, 25 Apr 2017 22:46:51 GMT

AD1 is almost identical to AD19, AD2 to AD18, etc.

If you graph it, those 19 columns turn into what appears as 10 lines.

The other thing you will see is the several jagged patterns that appear in the graph.

Reply #18

Datapile — Tue, 25 Apr 2017 22:41:56 GMT

Ok... I have something for you, but I recommend you graph this to get the ramifications, because it's hard to explain. (I remember your preferences for no visuals.)

So the Apex rows that I put up earlier, there are multiple correlations in the data. Here is how I made the table at the bottom:

For each drawing, note the apex line that it was on. So you have DrawID, ApexofN1, ApexofN2, etc. For each record in the new table, take the abs(ApexofN1 - ApexofN2) as ApexDelta1 or AD1, abs(ApexofN... [ More ]

Reply #17

Novan60 — Tue, 25 Apr 2017 03:40:18 GMT

Nope, just trying to save you some time and encourage you to start thinking beyond just the math of it. Although if you start going down an avenue I have not already explored I will be more than happy to assist.

Reply #16

Datapile — Tue, 25 Apr 2017 02:27:07 GMT

You're going to confound my efforts to offer up something interesting\new, aren't you

Reply #15

Datapile — Tue, 25 Apr 2017 02:25:30 GMT

The diamond is all 61 numbers possible for each slot, using 1 row for each number. The ellipse is formed by all the numbers that have actually been drawn. (It radiate out from the central line.

Reply #14

Novan60 — Tue, 25 Apr 2017 02:19:08 GMT

You are correct in assuming that I already did something like this. Here is the thread. https://www.lotterypost.com/thread/310864

You can actually get it down to a very reliable 1 in the first 8 if you play the next seven drawings and even as low as 1 in 4 if you dynamically reorder the numbers based on certain logic derived from past performance.

I frequently refer to playing the next X drawings because I think it is impossible to predict what the numbers are going to be for a specif... [ More ]

Reply #13

Datapile — Tue, 25 Apr 2017 00:42:31 GMT

If you take the first 20 Apex lines, and run them against historical data...(Remember: A number has to be in the exact slot for it to count as a hit its apex...)

Hit Apex1 Apex2 Apex3 Apex4 Apex5 Apex6 Apex7 Apex8 Apex9 Apex10 Apex11 Apex12 Apex13 Apex14 Apex15 Apex16 Apex17 Apex18 Apex19 Apex20

0 0.170 0.024

1 0.332 0.145 0.027 0.008 0.005 0.003

2 0.265 0.217 0.068 0.036 0.022 0.012 0.007 0.005 0.002 0.001 0.001 0.001

3 0.144 0.215 0.102 0.067 0.043 0.026 0.019 0.014 0.0... [ More ]

Reply #12

Datapile — Tue, 25 Apr 2017 00:20:43 GMT

We can list each of these lines, and come up with a column for each slot for descending probability of being drawn. I call these probability lines 'apex lines' as they start with the highest chance, and go down from there...

Apex N1 N2 N3 N4 N5 N6 N7 N8 N9 N10 N11 N12 N13 N14 N15 N16 N17 N18 N19 N20

Apex1 1 5 9 13 17 22 26 30 34 38 43 47 51 55 59 64 68 72 76 80

Apex2 2 4 8 14 18 21 25 29 35 39 42 46 52 56 60 63 67 73 77 79

Apex3 3 6 10 12 16 23 27 31 33 37 44 48 50 54 58 65 69... [ More ]

Reply #11

Datapile — Tue, 25 Apr 2017 00:17:10 GMT

(I'm looking for something new to show you- I never thought to look at the ratios the way you do, and I'm trying to find something that piques your interest...)

You can calculate the chance of every number in every slot in Excel with a formula- I suspect you've done this already. The data shows that for each slot, there is 1 number with the highest chance of being drawn in that slot. Also, the data shows that there is a direct inverse symmetry- 1 in N1 has the same chance as 80 in N20, 2 in N... [ More ]

Reply #10

Novan60 — Mon, 24 Apr 2017 23:19:03 GMT

I have not spent a lot of time trying to convert patterns to visualizations. I don't find them very helpful in this endeavor as all they do is confirm visually what I already know from the math.

In NY that game is the same as Quick Draw. I downloaded a half million results just to have them, but haven't made any use of them given that the 7000 plus Pick 10 drawings that I have are more than sufficient for my purposes.

After all of the research that I have done I have determined that I can... [ More ]

Reply #9

Datapile — Mon, 24 Apr 2017 22:49:14 GMT

IMHO, the evens are worse!

Novan, have you seen the ellipse that forms inside the diamond when you calculate the chance for each number, in each possible slot? (The 20/80 here is a bar game that runs every 4 minutes, for 340 drawings per day, so I have 1.3 million draws in the db...

Reply #8

Novan60 — Mon, 24 Apr 2017 01:12:00 GMT

It is hard enough trying to get 10 out of 20 much less the full 20. At this point while I'm always grateful when I hit an 8 or 7 out of 10 I'm more pissed off that I am having so much trouble getting those last 2-3 digits, much less the additional 10.

That said for a while I looked at targeting all 20, but abandoned that path pretty quickly as the odds were ridiculous. what makes Keno worth playing is not having to match the full 20.

Reply #7

Datapile — Mon, 24 Apr 2017 00:33:00 GMT

(After quick look at NY lottery... You're talking Pick 10, yes?

I've been leaning toward hexadecimal for a while- so that I'm only picking 20 from 0-F... Then trying to make rules as to frequency and behavior.

And I made a numbering algorithm, so that I can put in a full 20 digit sequence, and get its location ID or vice versa. (1,2...19,20 would be location ID 1. 61,62,...79,80 would be last possible combination 3535316142212174319.

Reply #6

Novan60 — Sun, 23 Apr 2017 23:40:46 GMT

No worries on terminology. Like you I have been doing this solo for a long time as well and have made up my own terminology along the way.

It was 7 days not 10, but you have the basic idea. When looking at the next X drawings from a given point in time we can see that the numbers appeared together in certain patterns in the previous drawings. In NY the jackpot is to match 10 numbers so I limited my results to only include combinations where all 10 of the numbers appeared in the previous 4 dra... [ More ]

Reply #5

Datapile — Sun, 23 Apr 2017 21:35:36 GMT

I've been doing this solo for years, so I'm a little behind on the terminology- So in one of the next 10 drawings there will be : 4 numbers from the last drawing, 3 numbers from the 2nd one back, 4 in the 3rd, and 4 in the 4th?

I'm foolhardy- have this crazy notion that it's possible to build a multifaceted model, where by I can find all 20 numbers. The trick is giving a program a clear set of steps, so that it can narrow down several broad categories, until the last step is finding the combi... [ More ]

Reply #4

Novan60 — Sun, 23 Apr 2017 20:14:00 GMT

Keno has been my game of choice because within each drawing there are tens of thousand of possible patterns to try and match. Each drawing is like playing 184,756 lotto drawings. I've managed to hit 9 out of 10 twice and averaged above the statistical average on the 8's and 7's.

Every strategy that I have explored always breaks down to the base 1 in 4 odds. The problem is that while it averages out to that over time in a given window it can go as high as 1 in 62 or as frequent as 8 in 8.

I... [ More ]

Reply #3

Datapile — Sun, 23 Apr 2017 15:17:24 GMT

If we keep going backward, up to 10 drawings back, with numbers that have only been drawn once, we find that there is actionable information contained in the historical data.

Count D1 D2 D3 D4 D5 D6 D7 D8 D9 D10

0 0.1% 1.0% 3.7% 9.3% 17.8% 28.1% 39.2% 50.0% 59.7% 68.1%

1 1.1% 5.8% 14.6% 25.2% 33.6% 38.2% 38.8% 36.0% 31.7% 26.8%

2 5.0% 15.1% 25.5% 30.0% 28.5% 23.2% 17.0% 11.5% 7.4% 4.6%

3 12.5% 23.6% 26.1% 21.4% 14.2% 8.2% 4.3% 2.1% 1.0% 0.5%

4 20.4% 24.1% 17.9% 10.0

Reply #2

Datapile — Sun, 23 Apr 2017 15:02:12 GMT

Let us push on, and go further backward in time...

If D1 was the drawing just before current, then D2 is the drawing 2 back and so on.

If each drawing has numbers that repeat with any other drawing, what if we look at the numbers that haven't repeated?

For the drawing D2, of the pool of numbers that didn't get drawn in D1 (average of 15), how many will be drawn in the current drawing? 15 * 25% = 3.7.

Looking at historical data, we find the average is indeed 3.7. We also see that any... [ More ]

Reply #1

Datapile — Sun, 23 Apr 2017 14:51:16 GMT

If we accept the base chance percentage of 25%, then out of any pool of numbers an average of 25% of them will be drawn.

Applying this to the drawing that has come just before current, we should see an average of 5 numbers repeat in the current drawing. (Lets call this previous drawing D1, as it is 1 drawing ago.)

Count D1

0 0.1%

1 1.1%

2 5.0%

3 12.5%

4 20.4%

5 23.3%

6 19.0%

7 11.4%

8 5.0%

9 1.7%

10 0.4%

11 0.1%

12 0.0

(New member) Have any of you broken down a keno game?

Datapile — Sun, 23 Apr 2017 02:26:22 GMT

Hello everyone. Have any of you broken down a keno game?

Out of a pool of 80 numbers, 20 are drawn. Order drawn is not important, so the numbers are put in numerical order afterward. (Forget about the tickets, or playing, just looking at the draw data.)

Selecting 20 out of 80, means that each number has a 25% chance of being drawn. The trick is that every number has the same total chance of being drawn, but not the same chance of being drawn in every place. (Example: The numbers 1 and 80,