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		<title>Trigonometry Question</title>
		<link>https://www.lotterypost.com/thread/315410</link>
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		<description>Lottery Post Forum Topic: Trigonometry Question</description>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/315410/5265513</link>
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			<pubDate>Mon, 25 Sep 2017 01:44:42 GMT</pubDate>
			<dc:creator>mitachoo</dc:creator>
			<description><![CDATA[<p>Cool, that&#x27;s exactly what I was looking for. Thanks</p>]]></description>
			<category>mitachoo</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/315410/5265321</link>
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			<pubDate>Sun, 24 Sep 2017 22:58:21 GMT</pubDate>
			<dc:creator>JADELottery</dc:creator>
			<description><![CDATA[<p>sin(a + b) is just an expression by itself.<br /><br />to solve for something you need an equation, like y = sin(a + b);<br /><br />then b = sin-1(y) - a, where sin-1() is the Arcsin or Inverse Sin function.</p>]]></description>
			<category>JADELottery</category>
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			<title>Trigonometry Question</title>
			<link>https://www.lotterypost.com/thread/315410</link>
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			<pubDate>Sun, 24 Sep 2017 03:18:18 GMT</pubDate>
			<dc:creator>mitachoo</dc:creator>
			<description><![CDATA[<p>Hi all! I&#x27;m backtesting a Pick 3 Strategy that (unfortunately) involves Trigonometry, and I&#x27;m stumped regarding a deceptively simple question that is making my backtesting extremely labor intensive. Any help would be greatly appreciated!<br /><br />So . . . with b being the unknown . . . how the (insert your favorite expletive here) do you solve for b when you have sin (a + b)? I know the basic Trig equations sin(a + b) = sin a cos b+ cos a sin b and cos(a + b) = cos a cos b - sin a sin b, but beyond th... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/315410">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>mitachoo</category>
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