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		<title>hello help in excel, to work with the 4 missing digits of the 10 6 digit strings &#xa0; the 10 strings .</title>
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		<description>Lottery Post Forum Topic: hello help in excel, to work with the 4 missing digits of the 10 6 digit strings &#xa0; the 10 strings .</description>
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			<title>Reply #17</title>
			<link>https://www.lotterypost.com/thread/324340/5776857</link>
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			<pubDate>Wed, 26 Dec 2018 15:39:25 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>You can use the adjacent digits of the last draw.<br /><br />and can also use the three major smaller and equal from the last draw<br /><br />example last = 683 = 5x7 7x9 2x4 where xxx = is last draw<br /><br />we also have the three standards per position<br /><br />greater, lesser and equal<br /><br />in the next was drawn. 354<br /><br />1st 2nd 3rd<br /><br />683<br /><br />354<br /><br />smaller smaller smaller<br /><br />being =<br /><br />1 = minor<br /><br />2 = equal<br /><br />3 = higher<br /><br />we have in 100% in 27 patterns<br /><br />111<br /><br />112<br /><br />113<br /><br />121<br /><br />122<br /><br />123<br /><br />131<br /><br />132<br /><br />133<br /><br />2... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/324340/5776857">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #16</title>
			<link>https://www.lotterypost.com/thread/324340/5776688</link>
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			<pubDate>Wed, 26 Dec 2018 09:47:54 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello you also have this double-digit option<br /><br />in 7 within the ratio = 6/4<br /><br />6/4<br /><br />0 2<br /><br />1 1<br /><br />2 0<br /><br />and still within the 6 strings and 4 absent, taking the last three digits<br /><br />example<br /><br />last 478 =<br /><br />Let&#x27;s choose the strings ==, 347890 I will take from it the 3 digits of the last draw, that is 478<br /><br />then the strings will stay with 3 digits 390 x the 4 absent = 1,2,5,6<br /><br />then for the pair I go from 1/1 where 1 is the three digits of the strings of 6 minus the last draw and another digi... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/324340/5776688">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #15</title>
			<link>https://www.lotterypost.com/thread/324340/5776126</link>
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			<pubDate>Tue, 25 Dec 2018 19:12:52 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello we have 4 conditions for the ratio 6/4<br /><br />that is<br /><br />6 strings x 4 missing<br /><br />3 0<br /><br />2 1<br /><br />1 2<br /><br />0 3<br /><br />where two conditions are hybridized the conditions = 1/2<br /><br />and 2/1<br /><br />an example you chose for the next draw the ratio<br /><br />ie 1 digit in the string and 2 in the absent<br /><br />the string was chosen = 1,2,3,4,5,6 = absent 7,8,9,0<br /><br />1 2<br /><br />the draw was 379<br /><br />we have 36 trainings without even a filter<br /><br />179<br /><br />178<br /><br />170<br /><br />198<br /><br />190<br /><br />180<br /><br />279<br /><br />278<br /><br />270<br /><br />298<br /><br />290<br /><br />280<br /><br />379</p>]]></description>
			<category>dr san</category>
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			<title>Reply #14</title>
			<link>https://www.lotterypost.com/thread/324340/5775743</link>
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			<pubDate>Tue, 25 Dec 2018 08:46:20 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello, sorry missed the growing doubles = 01 12 23 34 45 56 67 78 89 90<br /><br />the location of these 6 types of doubles within pick3 and 4 is important.<br /><br />because the cycle of repeating the doubles can best be seen, you can see<br /><br />by the table of ion doubles the probabilities of the repetitions came out,<br /><br />The objective of the study is to pick up empty sequences within matrix 0 to 9, to better filter<br /><br />not crossroads of patterns</p>]]></description>
			<category>dr san</category>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/324340/5775741</link>
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			<pubDate>Tue, 25 Dec 2018 08:33:12 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello,winsum, very good work, fantastic, will serve as the basis for a system<br /><br />of pick 3 and 4, to work, empty sectors within matrix 0 to 9<br /><br />in the relation 6/4 = where 6 are the strings and 4 are the absent ones, then we have two groups<br /><br />6/4, you can now choose the next pair easier than in the 4 missing,<br /><br />you can choose the double in 4 digits of the absent<br /><br />ex = 159 = doubles = 15 19 59, if you look at the 4 absent you will always have doubles there in pick3<br /><br />we have 6 types of doub... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/324340/5775741">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/324340/5775615</link>
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			<pubDate>Tue, 25 Dec 2018 03:17:11 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>I uploaded a new Excel file with the Missouri Pick 3 combined draws:<br /><br />https://my.pcloud.com/publink/show?code=XZQT1C7ZrKB0s1BgOtBPqbYSKpgTIR797FFy</p>]]></description>
			<category>winsumloosesum</category>
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			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/324340/5775537</link>
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			<pubDate>Tue, 25 Dec 2018 01:13:39 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p></p>]]></description>
			<category>winsumloosesum</category>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/324340/5775525</link>
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			<pubDate>Tue, 25 Dec 2018 01:04:11 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>Excel file:<br /><br />https://my.pcloud.com/publink/show?code=XZQ21C7ZqvFlWPmRPzj861di0gqWYV53pvv7<br /><br />D = 4 Hits<br /><br />Ranking = 1</p>]]></description>
			<category>winsumloosesum</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/324340/5775075</link>
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			<pubDate>Mon, 24 Dec 2018 16:27:33 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>http://www.mediafire.com/file/s9praseblunmkyu/padroes_e_strings.xlsx/file</p>]]></description>
			<category>dr san</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/324340/5775047</link>
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			<pubDate>Mon, 24 Dec 2018 16:03:55 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>http://www.mediafire.com/file/duaoe6ab0mxjlsh/10_strings_repetidas_e_ausentes.xlsx</p>]]></description>
			<category>dr san</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/324340/5775038</link>
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			<pubDate>Mon, 24 Dec 2018 16:00:53 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello winsum, you can divide into 4 sectors the matrix 0 to 9 of the pick 3<br /><br />= there are the 4 large groups = groups of repetitions, groups of absences, group of frequencies and group of lags = based on the last draw. If we can get, always get the block or empty sequences, we will have great prizes in 65% to 70% of the Weather is great,<br /><br />when crossing other filter patterns</p>]]></description>
			<category>dr san</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/324340/5774910</link>
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			<pubDate>Mon, 24 Dec 2018 13:21:36 GMT</pubDate>
			<dc:creator>Raven62</dc:creator>
			<description><![CDATA[<p>Piece of Cake</p>]]></description>
			<category>Raven62</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/324340/5774869</link>
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			<pubDate>Mon, 24 Dec 2018 12:00:53 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>ok, the base or reference, will always be the last draw for the next,<br /><br />using, the repetitions and absent, and frequency and delays both by the whole and by vertical position, also crossing the odd couple patterns high low, keeping the game several raffles<br /><br />the string alone is nothing, but when you cross with a pattern the thing happens,<br /><br />then the filter, are the repetitions of both pick 3 and 4, the repetitions can be the same or different position of the last draw, or missing digits, not</p>]]></description>
			<category>dr san</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/324340/5774868</link>
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			<pubDate>Mon, 24 Dec 2018 11:48:53 GMT</pubDate>
			<dc:creator>winsumloosesum</dc:creator>
			<description><![CDATA[<p>How do you determine what string to use for each game</p>]]></description>
			<category>winsumloosesum</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/324340/5774867</link>
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			<pubDate>Mon, 24 Dec 2018 11:43:50 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>well you can use the 10 strings also for pick3 and pick4, and also the absent ones<br /><br />ok the pick 3 and pick 4 with repeated digits does not enter the study singles only<br /><br />we have 6 positions<br /><br />for strings you can filter by vertical position for delays</p>]]></description>
			<category>dr san</category>
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			<title>Reply #2</title>
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			<pubDate>Mon, 24 Dec 2018 11:07:53 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>draw= 354<br /><br />string= 127890=absent= 3456<br /><br />345 ok<br /><br />346<br /><br />356<br /><br />456</p>]]></description>
			<category>dr san</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/324340/5774858</link>
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			<pubDate>Mon, 24 Dec 2018 11:06:06 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>we can also use for pick3, these 10 strings to be excluded<br /><br />and the remainder is deployed to pick3<br /><br />123456<br /><br />123478<br /><br />123490<br /><br />125678<br /><br />125690<br /><br />127890<br /><br />345678<br /><br />345690<br /><br />347890<br /><br />567890<br /><br />example = a string = 123456 = absent 7,8,9,0 =<br /><br />789<br /><br />780<br /><br />790<br /><br />890<br /><br />already in the string = 567902 absent that will be for game are = 1,2,3,4<br /><br />ok you can use the 10 strings, it will be 40 pick3 for the game<br /><br />how was this 10 strings used 5 pairs<br /><br />in sequences = 01 23 45 67 89<br /><br />s... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/324340/5774858">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>hello help in excel, to work with the 4 missing digits of the 10 6 digit strings &#xa0; the 10 strings .</title>
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			<pubDate>Mon, 24 Dec 2018 11:03:58 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>hello help in excel, to work with the 4 missing digits of the 10 6 digit strings<br /><br />the 10 strings will always be the same, we will work with the 4 missing digits, we can play the 4 arrays or filter by delay, would ask who knows excel 2010 to be able to test this method, because it eliminates blocks or sequences within the matrix from 0 to 9 . please</p>]]></description>
			<category>dr san</category>
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