Excessively Complicated Eigenvalue Method for Pick 3

Reply #12

AllenB — Thu, 21 Feb 2019 20:06:54 GMT

You've got to think Big Here.

You can not have to many Systems.

Think of it this way.

It takes a lot of Systems to make enough predictions. If you have enough you will find that the Left Out Pool is very small. That is where you take a Dip.

Reply #11

oate — Wed, 20 Feb 2019 19:18:01 GMT

Much needed laughs, thanks.

Reply #10

lakerben — Wed, 20 Feb 2019 15:54:11 GMT

Reply #9

Lottomeister — Wed, 20 Feb 2019 15:50:27 GMT

Reply #8

GuesssWork — Tue, 19 Feb 2019 19:24:13 GMT

why how many systems does one need to follow to seldom win at p3

Reply #7

GuesssWork — Tue, 19 Feb 2019 19:05:21 GMT

Q W E R T Y U I O P

LOL

Make up anything, use a structure to follow.

most of all don't waste your money on actual playing there is no sure fire way to win

at pick 3 or 4.. cash flow after your initial investment if you want

to call gambling an investment it will result in cash flowing out of your pockets to the states not into them..

Reply #6

oate — Tue, 19 Feb 2019 18:32:24 GMT

For the 3x3 case, an upper limit on the number of unique solutions is 500,500,000 since any matrix M and its transpose MT have the same set of eigenvalues, and there are only 1,000,000 symmetric matrices (matrices that are equal to their transpose) in this space. You could further reduce the upper limit with some fancier linear algebra, perhaps characterizing families of similar matrices within this space.

I didn't address what to do in cases where two of the eigenvalues are complex conjugate... [ More ]

Reply #5

RL-RANDOMLOGIC — Tue, 19 Feb 2019 18:20:41 GMT

LOL.

RL

Reply #4

JADELottery — Tue, 19 Feb 2019 18:13:05 GMT

This ain't my party.

I muss be a Genie or something.

Take Spongebob's advice and, Let's use our Imagination.

Reply #3

lakerben — Tue, 19 Feb 2019 16:49:10 GMT

Program it!

I'm ready to backtest

Reply #2

JADELottery — Tue, 19 Feb 2019 13:51:36 GMT

What are all the possible values for all 1,000,000,000 possible permutations?

How about for Ultra-complicated Pick 4's 10,000,000,000,000,000?

And even more Hyper-complicated Pick 5's 10,000,000,000,000,000,000,000,000?

Math layout made with MathCast.

Reply #1

Wentworth — Tue, 19 Feb 2019 11:13:31 GMT

and your point is

Excessively Complicated Eigenvalue Method for Pick 3

oate — Tue, 19 Feb 2019 05:04:12 GMT

Here is a method that combines arbitrariness with needless complexity.

Step 1: Take the last three Pick 3 results and make them rows of a 3x3 matrix with the most recent result as the top row. Example: 958, 357, 766 in matrix form:

[[9, 5, 8]

[3, 5, 7]

[7, 6, 6]]

Step 2: Find the three eigenvalues of the matrix: Continuing with example above, the eigenvalues are approximately -1.69012, 2.78551, and 18.9046.

Step 3: Take only the first two digits after the decimal point of each