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		<title>challenge, to create an algorithm for crossing statistical and standard data</title>
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			<title>Reply #20</title>
			<link>https://www.lotterypost.com/thread/325626/5851024</link>
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			<pubDate>Thu, 28 Feb 2019 06:53:26 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>Went ahead and finished anyway. Broke down the overall 5/35 and then the Texas draws. In the chart side by side.<br /><br />The results for the draws may not add up. That&#x27;s because the cutoff is 35, but in the past Texas had 37 and 39 ball draws so that&#x27;s the reason.<br /><br />Haven&#x27;t had time to check every single line, sorry. But for two days I&#x27;d say this is a pretty good start at a statistical breakdown. Some additions could be made. Have a couple in mind already.<br /><br />Stats go a lot deeper (IMHO) than... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5851024">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #19</title>
			<link>https://www.lotterypost.com/thread/325626/5850435</link>
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			<pubDate>Wed, 27 Feb 2019 21:29:41 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>If it suits your purpose write the algorithm. Might make you a rich man.<br /><br />Unfortunately I don&#x27;t see how its any different from any other system where someone has said, The first number will go to X, and the second number is between G and Q, and the third is larger than R but less the W and the fourth is.....<br /><br />Same stuff has been posted hundreds of times.</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #18</title>
			<link>https://www.lotterypost.com/thread/325626/5850402</link>
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			<pubDate>Wed, 27 Feb 2019 20:57:18 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo, you can also use the trio<br /><br />from 02 to 36 in the lottery case<br /><br />37/5 or the first and last number is missing<br /><br />then two ways to see the trio<br /><br />we have ex =<br /><br />02 x 15 x 35 or x 15 18 26 x<br /><br />the number of trios from 02 to 36, central trios<br /><br />is 6.545 in 100% of any lot goes very filter in them then we have the example where the two remaining nemeros goes in position 2 and 4 and we have the case of the two remaining numbers being of the 1st and 5th<br /><br />if your lottery went to 01 a35 th... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5850402">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #17</title>
			<link>https://www.lotterypost.com/thread/325626/5849971</link>
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			<pubDate>Wed, 27 Feb 2019 15:50:16 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>Good deal! Let me know when ou figure out how many numbers you&#x27;ll have</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #16</title>
			<link>https://www.lotterypost.com/thread/325626/5849890</link>
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			<pubDate>Wed, 27 Feb 2019 14:13:08 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo of course can filter this trio<br /><br />go to the top 5% of this list<br /><br />filter as, repetition of the ulttimo trio maximum two digits, long and average delays, etc ..</p>]]></description>
			<category>dr san</category>
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			<title>Reply #15</title>
			<link>https://www.lotterypost.com/thread/325626/5849714</link>
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			<pubDate>Wed, 27 Feb 2019 07:18:10 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>Well, okay! I guess this means you are planning to wheel 1673 three number combinations? Nice plan if you have the money to play until you hit.<br /><br />Meanwhile, I did some tinkering with an old program. Its running and should produce 424,632 rows by 53 columns (that&#x27;s 22.5 million) little blocks of data in a CSV.<br /><br />G</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #14</title>
			<link>https://www.lotterypost.com/thread/325626/5849675</link>
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			<pubDate>Wed, 27 Feb 2019 05:39:32 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo it was made the following<br /><br />the limit from 01 to 10 for 1st position<br /><br />from 03 to 20 the central number and from 27 to 37 the third trio, where x is the remaining two numbers<br /><br />ex = 05x15x36<br /><br />then we have the lowest x center x largest</p>]]></description>
			<category>dr san</category>
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			<title>Reply #13</title>
			<link>https://www.lotterypost.com/thread/325626/5849674</link>
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			<pubDate>Wed, 27 Feb 2019 05:39:13 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo 37/5 01 10 x 2 20 x 27 a 37<br /><br />01x 03 x27<br /><br />01x 03x 28<br /><br />01 x03x29<br /><br />01 03 30<br /><br />01 03 31<br /><br />01 03 32<br /><br />01 03 33<br /><br />01 03 34<br /><br />01 03 35<br /><br />01 03 36<br /><br />01 03 37<br /><br />01 04 27<br /><br />01 04 28<br /><br />01 04 29<br /><br />01 04 30<br /><br />01 04 31<br /><br />01 04 32<br /><br />01 04 33<br /><br />01 04 34<br /><br />01 04 35<br /><br />01 04 36<br /><br />01 04 37<br /><br />01 05 27<br /><br />01 05 28<br /><br />01 05 29<br /><br />01 05 30<br /><br />01 05 31<br /><br />01 05 32<br /><br />01 05 33<br /><br />01 05 34<br /><br />01 05 35<br /><br />01 05 36<br /><br />01 05 37<br /><br />01 06 27<br /><br />01 06 28<br /><br />01 06 29<br /><br />01 06 30<br /><br />01 06 31<br /><br />01... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5849674">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #12</title>
			<link>https://www.lotterypost.com/thread/325626/5849670</link>
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			<pubDate>Wed, 27 Feb 2019 05:35:21 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo 37/5 01 10 x 2 20 x 27 a 37<br /><br />01x 03 x27<br /><br />01x 03x 28<br /><br />01 x03x29<br /><br />01 03 30<br /><br />01 03 31<br /><br />01 03 32<br /><br />01 03 33<br /><br />01 03 34<br /><br />01 03 35<br /><br />01 03 36<br /><br />01 03 37<br /><br />01 04 27<br /><br />01 04 28<br /><br />01 04 29<br /><br />01 04 30<br /><br />01 04 31<br /><br />01 04 32<br /><br />01 04 33<br /><br />01 04 34<br /><br />01 04 35<br /><br />01 04 36<br /><br />01 04 37<br /><br />01 05 27<br /><br />01 05 28<br /><br />01 05 29<br /><br />01 05 30<br /><br />01 05 31<br /><br />01 05 32<br /><br />01 05 33<br /><br />01 05 34<br /><br />01 05 35<br /><br />01 05 36<br /><br />01 05 37<br /><br />01 06 27<br /><br />01 06 28<br /><br />01 06 29<br /><br />01 06 30<br /><br />01 06 31<br /><br />01... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5849670">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>dr san</category>
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			<title>Reply #11</title>
			<link>https://www.lotterypost.com/thread/325626/5849441</link>
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			<pubDate>Wed, 27 Feb 2019 01:57:50 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>Yeah, those things are a given. One (1) can never appear as anything but the lowest number in any game since there is nothing lower than 1. And 37, 36,35,34 could never appear in the first position since there is not enough higher numbers to take their place in the higher positions.<br /><br />In 5/37 the third position is the hardest to predict. RL says the same thing. So that&#x27;s the position to place the most variations.<br /><br />My opinion is people give up on a set too soon. The idea is not just to w... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5849441">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #10</title>
			<link>https://www.lotterypost.com/thread/325626/5849334</link>
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			<pubDate>Wed, 27 Feb 2019 00:26:36 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>PATTERNS IN THE LOTTERY GAME</p>]]></description>
			<category>dr san</category>
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			<title>Reply #9</title>
			<link>https://www.lotterypost.com/thread/325626/5849323</link>
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			<pubDate>Wed, 27 Feb 2019 00:11:09 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo, one of the factors of<br /><br />would be the smallest number with the highest<br /><br />increasing order, ex in a lottery<br /><br />35/5 then the 1st number will be<br /><br />12 and last 29 among the other three we have<br /><br />17, garyo in any lottery is important 1st number and the last number, you can ride double<br /><br />of this, there was a lottery in which the first number was 32<br /><br />and the last 43 or delta of 11 of the other 3 numbers, crosses of statistical patterns<br /><br />is promising to predict or exclude blocks</p>]]></description>
			<category>dr san</category>
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			<title>Reply #8</title>
			<link>https://www.lotterypost.com/thread/325626/5849307</link>
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			<pubDate>Tue, 26 Feb 2019 23:56:57 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>oate, ahh, dr, there is nothing to be is just nick name, of course I&#x27;m not a doctor. Hey, I&#x27;m still young, I respect the experience of the elders, I agree that I have to, but then I would not enter the forum<br /><br />in fact many who know good system do not put in the forns, but there is always that wants to help willingly! if you do not want to help I respect this is a forum for debate and help,</p>]]></description>
			<category>dr san</category>
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			<title>Reply #7</title>
			<link>https://www.lotterypost.com/thread/325626/5849273</link>
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			<pubDate>Tue, 26 Feb 2019 23:20:07 GMT</pubDate>
			<dc:creator>Soledad</dc:creator>
			<description><![CDATA[<p>Combine them. All points or crosses , and then try your algorithm. Can be anything really, but it must work see. You need good filter. What better than to use everything to see what works and what doesn t. Eliminate as you see fit. Filter. Not a rule. Maybe</p>]]></description>
			<category>Soledad</category>
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			<title>Reply #6</title>
			<link>https://www.lotterypost.com/thread/325626/5849270</link>
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			<pubDate>Tue, 26 Feb 2019 23:19:11 GMT</pubDate>
			<dc:creator>oate</dc:creator>
			<description><![CDATA[<p>As the Greek playwrights were fond of saying, the gods help those who help themselves. I&#x27;m starting to suspect you are not even a real doctor, dr san</p>]]></description>
			<category>oate</category>
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			<title>Reply #5</title>
			<link>https://www.lotterypost.com/thread/325626/5849269</link>
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			<pubDate>Tue, 26 Feb 2019 23:19:06 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>I take it there are no prizes?<br /><br />Either way, I understand.<br /><br />Of course, you should recognize there would is a LOT of prep work in that idea. Somebody posted they had a list of the entire MegaMillion matrix which (I believe) they said 56Megs. Its conceivable a data base with the various statistics would be on the high side of 500Megs. I don&#x27;t say that lightly knowing that the total 5/37 count is 435897 lines and goes 10Megs. And once you&#x27;ve derived and added 47 columns of data that Excel... &#x5b;&#xa0;<a href="https://www.lotterypost.com/thread/325626/5849269">More</a>&#xa0;&#x5d;</p>]]></description>
			<category>garyo1954</category>
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			<title>Reply #4</title>
			<link>https://www.lotterypost.com/thread/325626/5849247</link>
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			<pubDate>Tue, 26 Feb 2019 22:59:35 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>to do alone? means not to be in the forum, if you do not want to help I respect, let others who want to help, the forum is debates and help</p>]]></description>
			<category>dr san</category>
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			<title>Reply #3</title>
			<link>https://www.lotterypost.com/thread/325626/5849227</link>
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			<pubDate>Tue, 26 Feb 2019 22:22:00 GMT</pubDate>
			<dc:creator>oate</dc:creator>
			<description><![CDATA[<p>Instead of starting threads every day to ask people to carry out various poorly described lottery analysis projects on your behalf, you should learn some math so you can do these projects on your own. I have yet to see you contribute any of your own findings, only a mountain of suggestions of what other people should do for you.</p>]]></description>
			<category>oate</category>
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			<title>Reply #2</title>
			<link>https://www.lotterypost.com/thread/325626/5849223</link>
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			<pubDate>Tue, 26 Feb 2019 22:14:34 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>garyo we know that a statistic alone, does not represent anything,<br /><br />but when crossed with another pattern increases the forecast, synchronism is everything, you can divide a certain statistics into sectors and cross with other indices, either to predict numbers or to exclude empty blocks.<br /><br />example, we can have ten different statistic lists or lists, and see where the lottery goes<br /><br />so we have a sequence of index crosses, you see!<br /><br />for this you need the algorithm</p>]]></description>
			<category>dr san</category>
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			<title>Reply #1</title>
			<link>https://www.lotterypost.com/thread/325626/5849212</link>
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			<pubDate>Tue, 26 Feb 2019 21:54:02 GMT</pubDate>
			<dc:creator>garyo1954</dc:creator>
			<description><![CDATA[<p>How about some ideas of what stats we are to use!<br /><br />Are there senior and junior divisions? Or is this just a pro and amateur event?<br /><br />Do we need to include percentages for each category?<br /><br />If so, at what percent should the program display, WARNING WILL ROBINSON!! DANGER! DANGER!<br /><br />Who are the judges?<br /><br />What are the prizes for the top programs?<br /><br />And are there any bonus prizes for the most columns in the data stats file</p>]]></description>
			<category>garyo1954</category>
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			<title>challenge, to create an algorithm for crossing statistical and standard data</title>
			<link>https://www.lotterypost.com/thread/325626</link>
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			<pubDate>Tue, 26 Feb 2019 10:48:17 GMT</pubDate>
			<dc:creator>dr san</dc:creator>
			<description><![CDATA[<p>challenge, to create an algorithm for crossing statistical and standard data<br /><br />hello objective is to cross the statistics as we know an index alone is nothing but when in crossing with another it helps,</p>]]></description>
			<category>dr san</category>
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